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a)\([\)5(a-b)\(^3\)+2(a-b)\(^2]\):(b-a)\(^2\)
=\([\)5(a-b)\(^3\)+2(a-b)\(^2]\):(a-b)\(^2\)
=5(a-b)+2
b)5(x-2y)\(^3\):(5x-10y)
=5(x-2y)\(^3\):5(x-2y)
=(x-2y)\(^2\)
c)(x\(^3\)+8y\(^3\)):(x+2y)
=\([\)x\(^3\)+(2y)\(^3]\):(x+2y)
=(x+2y)(x\(^2\)-2xy+4y\(^2\)):(x+2y)
=x\(^2\)-2xy+4y\(^2\)
a: \(5x^2y^4:10x^2y=\dfrac{1}{2}y^3\)
c: \(\left(-xy\right)^{10}:\left(-xy\right)^5=-x^5y^5\)
a: \(=\dfrac{27a^6b^3\cdot a^2b^6}{a^8b^8}=27b\)
b: \(=3y^2-5x^2y^3-2y^2+3x^2y^3\)
\(=y^2-2x^2y^3\)
c: \(=6x-y+2x^2+3y-2x^2+x\)
\(=7x+2y\)
d: \(=x-y+2y^2-6xy+\dfrac{10x^2}{y}\)
c: \(=\dfrac{3x\left(x-1\right)\left(x+1\right)}{\left(x-1\right)\left(x+1\right)\left(x^2+1\right)}=\dfrac{3x}{x^2+1}\)
a: \(=3y^2-5x^2y^3-2y^2+3x^2y^3=y^2-2x^2y^3\)
b: \(=6x-y+2x^2+3y^2-2x^2+x=7x-y+3y^2\)
c: \(=x-y+4y^2-6xy+\dfrac{10x^2}{y}\)
\(a.\left(9x^2y^3-15x^4y^4\right):3x^2y-\left(2-3x^2y\right)y^2\)
\(=3y^2-5x^2y^3-2y^2+3x^2y^3\)
\(=y^2-2x^2y^3\)
\(b.\left(6x^2-xy\right):x+\left(2x^3y+3xy^2\right):xy-\left(2x-1\right)x\)
\(=6x-y+2x^2+3y-2+x\)
\(=2x^2+7x+2y-2\)
\(c.\left(x^2-xy\right):x+\left(6x^2y^5-9x^3y^4+15x^4y^3\right):\dfrac{3}{2}x^2y^3\)
\(=x-y+4y^2-6xy+10x^2\)
a)\((\dfrac{5}{7}x^2y)^3:(\dfrac{1}{7}xy)^3\)
=\((\dfrac{5}{7}x^2y:\dfrac{1}{7}:x:y)^3\)
=(\(\dfrac{5}{7}.7.x^2:x.y:y)^3\)
=(5x)\(^3\)
=5\(^3\).x\(^3\)
=125.x\(^3\)