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1 - \(\dfrac{3}{4}\) + \(\dfrac{1}{4}\) = \(\dfrac{4}{4}\) - \(\dfrac{3}{4}\) + \(\dfrac{1}{4}\) = \(\dfrac{2}{4}\) = \(\dfrac{1}{2}\)
Vậy a, S còn b, Đ
a) \(\frac{3}{4}-\frac{1}{6}-\frac{a}{b}=\frac{1}{2}\)
\(\frac{7}{12}-\frac{a}{b}=\frac{1}{2}\)
\(\frac{a}{b}=\frac{7}{12}-\frac{1}{2}\)
\(\frac{a}{b}=\frac{1}{12}\)
b) \(\frac{a}{b}\times\frac{1}{4}\times\frac{2}{5}=\frac{1}{7}\)
\(\frac{a}{b}\times\frac{1}{10}=\frac{1}{7}\)
\(\frac{a}{b}=\frac{1}{7}:\frac{1}{10}\)
\(\frac{a}{b}=\frac{10}{7}\)
c) \(\frac{1}{3}:\frac{a}{b}=\frac{2}{3}:\frac{4}{3}\)
\(\frac{1}{3}:\frac{a}{b}=\frac{1}{2}\)
\(\frac{a}{b}=\frac{1}{3}:\frac{1}{2}\)
\(\frac{a}{b}=\frac{3}{2}\)
a. \(\left(\dfrac{1}{3}+\dfrac{2}{3}\right)+\dfrac{3}{4}=1+\dfrac{3}{4}=\dfrac{7}{4}\)
b. \(\dfrac{3}{4}+\dfrac{3}{5}+\dfrac{2}{8}+\dfrac{4}{10}=\left(\dfrac{3}{4}+\dfrac{2}{8}\right)+\left(\dfrac{3}{5}+\dfrac{4}{10}\right)=1+1=2\)
a ) `1/3 + 3/4 + 2/3 + 1/4 `
`= (1/3 + 2/3 )+ (3/4 + 1/4)`
`= 1 + 1 `
`= 2
b 3/4 + 3/5 + 2 phần 8 + 4/10`
`= (3/4 + 2/8 ) + ( 3/5 + 4/10 ) `
`= 1 + 1 `
`= 2`
\(1+\frac{3}{4}=\frac{4}{4}+\frac{3}{4}=\frac{7}{4}\)
\(1+\frac{3}{4}=\frac{4}{4}+\frac{3}{4}=\frac{7}{4}\)