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a) \(70-5\left(x-3\right)=45\)
\(5\left(x-3\right)=25\)
\(x-3=5\)
\(\Rightarrow x=8\)
b) \(12+\left(5+x\right)=20\)
\(5+x=8\)
\(\Rightarrow x=3\)
c) \(130-\left(100+x\right)=25\)
\(100+x=105\)
\(\Rightarrow x=5\)
d) \(175+\left(30-x\right)=200\)
\(30-x=25\)
\(\Rightarrow x=5\)
e) \(5\left(x+12\right)+22=92\)
\(5\left(x+12\right)=70\)
\(x+12=14\)
\(\Rightarrow x=2\)
a. 70 - 5.(x - 3) = 45
5.(x - 3) = 70 - 45
x - 3 = 25 : 5
x = 5 + 3
x = 8
b. 12 + (5 + x) = 20
5 + x = 20 - 12
x = 8 - 5
x = 3
c. 130 - (100 + x) = 25
100 + x = 130 - 25
x = 105 - 100
x = 5
d. 175 + (30 - x) = 200
30 - x = 200 - 175
x = 30 - 25
x = 5
e. 5.(x + 12) + 22 = 92
5.(x + 12) = 92 - 22
x + 12 = 70 : 5
x = 14 - 12
x = 2
a) \(70-\left(x-3\right)=45\)
\(x-3=70-45\)
\(x-3=25\)
\(x=25+3\)
\(x=28\)
b) \(12+\left(5+x\right)=20\)
\(5+x=20-12\)
\(5+x=8\)
\(x=8-5\)
\(x=3\)
c) \(130-\left(100+x\right)=25\)
\(100+x=130-25\)
\(100+x=105\)
\(x=105-100\)
\(x=5\)
d) \(175+\left(30-x\right)=200\)
\(30-x=200-175\)
\(30-x=25\)
\(x=30-25\)
\(x=5\)
e) \(\left(x+12\right)+22=92\)
\(x+12=92-22\)
\(x+12=70\)
\(x=70-12\)
\(x=58\)
f) \(95-\left(x+2\right)=45\)
\(x+2=95-45\)
\(x+2=50\)
\(x=50-2\)
\(x=48\)
a)
70 - (x - 3) = 45
x - 3 = 70 - 45 = 25
x = 25 + 3 = 28
Vậy x = 28
b)
12 + (5 + x) = 20
5 + x = 20 - 12 = 8
x = 8 - 5 = 3
Vậy x = 3
c)
130 - (100 + x) = 25
100 + x = 130 - 25 = 115
x = 115 - 100 = 15
Vậy x = 15
d)
175 + (30 - x) = 200
30 - x = 200 - 175 = 25
x = 30 - 25 = 5
Vậy x = 5
e)
(x + 12) + 22 = 92
x + 12 = 92 - 22 = 70
x = 70 - 12 = 58
Vậy x = 58
f)
95 - (x + 2) = 45
x + 2 = 95 - 45 = 50
x = 50 - 2 = 48
Vậy x = 48
A = (75.54 + 175.54 ) : ( 20 . 25 . 125 - 625 . 75 )
= [(75 + 175).54 ] : (20.25.25.5 - 625.75)
= (250.54 ) : [ 625.(100 - 75)]
= (250.54 ) : (54 . 25)
= 250 : 25
= 10
\(\dfrac{75.5^4+175.5^4}{20.25.125-625.75}\)
\(=\dfrac{5^4\left(175+75\right)}{4.5.5^2.5^3-5^4.5^2.3}=\dfrac{5^4.225}{4.5^6-3.5^6}\)
\(=\dfrac{5^4.225}{4.5^6-3.5^6}=\dfrac{5^4.15^2}{5^6\left(4-3\right)}=\dfrac{5^4.\left(5.3\right)^2}{5^6}=\dfrac{5^4.5^2.3^2}{5^6}=\dfrac{5^6.3^2}{5^6}=9\)
TL :
Mình làm lun 2 cách
C1 :
\(\left(75-100\right)-\left(175-200\right)+\left(-5\right)\)
\(=-25-\left(-25\right)+\left(-5\right)\)
\(=0+\left(-5\right)\)
\(=-5\)
C2 :
\(\left(75-100\right)-\left(175-200\right)+\left(-5\right)\)
\(=75-100-175-200+\left(-5\right)\)
\(=175-75-200-100+\left(-5\right)\)
\(=100-100+\left(-5\right)\)
\(=0+\left(-5\right)\)
\(=-5\)