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\(23.18+18.\left(-23\right)\)
\(=23.18+\left(-18\right).23\)
\(=23.\left(-18+18\right)\)
\(=23.0=0\)
\(\left(23.18\right):\left(23.2\right)=\dfrac{23.18}{23.2}=\dfrac{18}{2}=9\)
(23.18) : (23.2)= (23:23) . (18:2)= 1.9=9
a) = 8 . 15 - [115- 72 ]
= 8 . 15 - [115- 49 ]
= 120 - 56
= 64
b) = 100 : {250 : [450 - (2.125 - 8.25)]}
= 100 : {250 : [450 - (250 - 200 )]}
= 100 : {250 : [450 - 50]}
= 100 : {250 :400}
= 100 : 0,265
= 0,00265
=
\(a,2^3.15-\left[115-\left(12-5\right)^2\right]\)
\(=8.15-\left[115-\left(12-5\right)^2\right]\)
\(=120-\left[115-7^2\right]\)
\(=120-\left[115-49\right]\)
\(=120-66\)
\(=54\)
\(b,100:\left\{250:\left[450-\left(2.5^3-2^3.25\right)\right]\right\}\)
\(=100:\left\{250:\left[450-\left(2.125-8.25\right)\right]\right\}\)
\(=100:\left\{250:\left[450-\left(250-200\right)\right]\right\}\)
\(=100:\left\{250:\left[450-50\right]\right\}\)
\(=100:\left\{250:400\right\}\)
\(=100:0,625\)
\(=160\)
\(2^3.15-\left[115-\left(12-5\right)^2\right]=8.15-\left[115-7^2\right]=120-\left[115-49\right]=120-66=54\)
\(100:\left\{250:\left[450-\left(4.5^3-2^2.25\right)\right]\right\}=100:\left\{250:\left[450-\left(4.125-4.25\right)\right]\right\}=100:\left\{250:\left[450-\left(500-100\right)\right]\right\}\)
\(=100:\left[250:\left(450-400\right)\right]=100:\left(250:50\right)=100:5=20\)
a)36:32+23.22-33.3
= 34+25-34
=25
=32
b)38:34-95:93
= 34-92
= 34-34
= 0
c)23.15+23.35
= 23(15+35)
= 8.50
= 400
a: \(3^6:3^2+2^3\cdot2^2-3^3\cdot3\)
\(=3^4+32-3^4\)
=32
b: \(3^8:3^4-9^5:9^3\)
\(=3^4-9^2\)
=0
c: Ta có: \(2^3\cdot15+2^3\cdot35\)
\(=8\cdot50\)
=400
\(55-\left[48-\left(23.18-23.15\right)\right]\)
\(55-\left\{48-\left[23.\left(18-15\right)\right]\right\}\)
\(55-\left\{48-69\right\}\)
\(55+21\)
\(76\)
nhóm 23 vào với nhau ta
55-{48-(23(18-15)}
55-(-21)
76
vậy biểu thức trên ra 76