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-6.(-35).(-27) < 0 ( Vì chưa lẻ số dấu "-")
5.35 > 0 ( Vì tích hai số dương)
Do đó -6.(-35).(-27) < 5.35
a, 128 – 3(x+4) = 23
b, 12 x - 4 3 . 8 3 = 4 . 8 4
c, [(4x+28).3+55]:5 = 35
d, 720:[41 – (2x – 5)] = 2 3 . 5
a, 2 3 x + 5 2 x = 2 5 2 + 2 3 - 33
8x+25x = 33
33x = 33
x = 1
b, 260 : x + 4 = 5 2 3 + 5 - 3 3 2 + 2 2
260:(x+4) = 5.13–3.13
x+4 = 260:26
x+4 = 10
x = 6
c, 720 : [ 41 - 2 x - 5 ] = 2 3 . 5
41–(2x–5) = 720:40
2x–5 = 41–18
2x = 28
x = 14
d, 3 2 - 2 x - 12 + 35 = 5 2 + 279 : 3 2
7(x–12)+35 = 56
7(x–12) = 21
x–12 = 3
x = 15
a; \(\dfrac{9}{27}\) + \(\dfrac{7}{-49}\)
= \(\dfrac{1}{3}\) - \(\dfrac{1}{7}\)
= \(\dfrac{7}{21}\) - \(\dfrac{3}{21}\)
= \(\dfrac{4}{21}\)
b; - \(\dfrac{12}{10}\) + \(\dfrac{-25}{30}\)
= - \(\dfrac{6}{5}\) - \(\dfrac{5}{6}\)
= -\(\dfrac{36}{30}\) - \(\dfrac{25}{30}\)
= \(\dfrac{-61}{30}\)
c; \(\dfrac{-20}{35}\) + \(\dfrac{-16}{-24}\)
= - \(\dfrac{4}{7}\) + \(\dfrac{2}{3}\)
= - \(\dfrac{12}{21}\) + \(\dfrac{14}{21}\)
= \(\dfrac{2}{21}\)
d; - \(\dfrac{21}{77}\) + \(\dfrac{10}{-35}\)
= - \(\dfrac{3}{11}\) - \(\dfrac{2}{7}\)
= - \(\dfrac{21}{77}\) - \(\dfrac{22}{77}\)
= - \(\dfrac{43}{77}\)
85.(35-27)-35.(85-27)
=85.35-85.27-35.85-35.27
=85.35(1-1)-27(85-35)=
=0-27.50
=-1350
b)
16.(38-12)-38(16-12)
=16.38-16.12-38.16-38.12
=16.38(1-1)-12(16-38)
=16.38.0-12.-22
=0+264
=264
chúc bn hok tốt
\(\frac{6^5.35^7}{14^7.15^5}=\frac{2^5.3^5.5^7.7^7}{2^7.7^7.3^5.5^5}=\frac{5^2}{2^2}=\frac{25}{4}\)
\(5.3^5:\left(3^8:3^5\right)-2^3.5\)\(=\)
\(5.3^5:3^3-2^3.5\)\(=\)
\(5.3^2-2^3.5\)\(=\)
\(5\left(3^2-2^3\right)\)\(=\)\(5\)