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C
16 tháng 9 2018
\(\left(\dfrac{2}{3}-\dfrac{1}{4}+\dfrac{5}{11}\right)-\left(5-\dfrac{1}{3}-\dfrac{6}{5}\right)-\left(6-\dfrac{7}{4}+\dfrac{3}{2}\right)\)
\(=\left(\dfrac{88-33+60}{132}\right)-\left(\dfrac{75-5-18}{15}\right)-\left(\dfrac{24-7+6}{4}\right)\)
\(=\dfrac{115}{132}-\dfrac{52}{15}-\dfrac{23}{4}\)
\(=-8\dfrac{19}{55}\)
10 tháng 8 2016
a)\(3-\left(\frac{1}{4}+\frac{2}{3}\right)-\left(5+\frac{1}{3}-\frac{6}{5}\right)-\left(6-\frac{7}{4}+\frac{3}{2}\right)\)
=\(3-\frac{1}{4}-\frac{2}{3}-5-\frac{1}{3}+\frac{6}{5}-6+\frac{7}{4}-\frac{3}{2}\)
=\(\left(3-5-6\right)+\left(\frac{-1}{4}+\frac{7}{4}\right)+\left(\frac{-2}{3}-\frac{1}{3}\right)+\left(\frac{6}{5}-\frac{3}{2}\right)\)
=\(-8+\frac{3}{2}-1-\frac{3}{10}\)
=\(\left(-8-1\right)+\left(\frac{3}{2}-\frac{3}{10}\right)\)
=-9+\(\frac{6}{5}\)
=\(\frac{-39}{5}\)
21 tháng 8 2016
(7 - 3/4 + 1/3) - (6 + 5/4 - 4/3) - (5 - 7/4 + 5/3)
= 7 - 3/4 + 1/3 - 6 - 5/4 + 4/3 - 5 + 7/4 - 5/3
= (7 - 6 - 5) - (3/4 + 5/4 - 7/4) + (1/3 + 4/3 - 5/3)
= -4 - 1/4 + 0
= -16/4 - 1/4
= -17/4
9 tháng 7 2018
= \(\frac{1}{2}\)- \(\frac{2}{3}\)+ (\(\frac{3}{4}\)- \(\frac{3}{4}\)) + ( -\(\frac{4}{5}\)+ \(\frac{4}{5}\)) + ( \(\frac{5}{6}-\frac{5}{6}\)) - \(\frac{6}{7}\)
= \(\frac{1}{2}-\frac{2}{3}-0-0-0-\frac{6}{7}\)
= \(\frac{1}{2}-\frac{2}{3}-\frac{6}{7}\)
=\(\frac{21}{42}-\frac{28}{42}-\frac{36}{42}\)
= \(\frac{-43}{42}\)
5 tháng 7 2023
1: =1/8*9/4=9/32
2: =8/27*243/32=9/4
3: =(5/4*4/5)^5*(4/5)^2=16/25
4: \(=\left(-\dfrac{5}{6}\cdot\dfrac{6}{5}\right)^2\cdot\left(\dfrac{6}{5}\right)^2=\dfrac{36}{25}\)
5: \(=\left(-\dfrac{4}{3}\right)^3\cdot\left(\dfrac{3}{4}\right)^{10}=\left(-1\right)\left(\dfrac{3}{4}\right)^7=-\left(\dfrac{3}{4}\right)^7\)
6: \(=\left(\dfrac{1}{3}\cdot\dfrac{-9}{2}\right)^4\left(-\dfrac{9}{2}\right)^2=\left(-\dfrac{3}{2}\right)^4\cdot\dfrac{81}{4}=\dfrac{9}{4}\cdot\dfrac{81}{4}=\dfrac{729}{16}\)
8: =(0,2*5)^4*5^2=25
10: =-0,5^5*2^10
=-0,5^5*2^5*2^5
=-32
13: =(0,5*2)^2*2^2=4
LN
1
TN
30 tháng 8 2018
\(\left(3-\dfrac{1}{4}+\dfrac{2}{3}\right)-\left(5-\dfrac{1}{3}-\dfrac{6}{5}\right)-\left(6-\dfrac{7}{4}+\dfrac{3}{2}\right)\)
= \(3-\dfrac{1}{4}+\dfrac{2}{3}-5+\dfrac{1}{3}+\dfrac{6}{5}-6+\dfrac{7}{4}-\dfrac{3}{2}\)
= \(\left(3-5-6\right)+\left(\dfrac{-1}{4}+\dfrac{7}{4}\right)+\left(\dfrac{2}{3}+\dfrac{1}{3}\right)+\left(\dfrac{6}{5}-\dfrac{3}{2}\right)\)
= \(\left(-8\right)+2+1+\dfrac{-3}{10}\)
= \(\left(-5\right)+\dfrac{-3}{10}\)
= \(\dfrac{-53}{10}\) = \(-5,3\)
