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\(M=\dfrac{5^4\cdot50}{5^3\cdot15}=\dfrac{50}{3}>\dfrac{50}{4}=N\)
\(4n+1⋮2n-1\)
\(\Leftrightarrow2\left(2n-1\right)+3⋮2n-1\)
\(\Leftrightarrow3⋮2n-1\)
\(\Leftrightarrow2n-1\in\left\{1;3;-1;-3\right\}\)
\(\Leftrightarrow2n\in\left\{2;4;0;-2\right\}\)
\(\Leftrightarrow n\in\left\{1;2;0;-1\right\}\)
a, 2x-1 = 64
=> 2x-1 = 26
=> x - 1 = 6
=> x = 6 + 1
=> x = 7
b, 32x-10 = 81
=> 32x-10 = 34
=> 2x - 10 = 4
=> 2x = 14
=> x = 7
c, 22x+3 = 1024
=> 22x+3 = 210
=> 2x + 3 = 10
=> 2x = 7
=> x = \(\frac{7}{2}\)
a) \(=\left(278+622\right)+\left(809-209\right)=900+600=1500\)
b) \(=64.57+64.43-2300=64\left(57+43\right)-2300=54.100-2300=5400-2300=3100\)
a) 278+809+622-209
= (278+622)+(809-209)
= 900 + 600
= 1500
b) 64.57+64.43-2300
= 64(57+43)-2300
= 64.100-2300
= 6400-2300=4100
c) 24.5-[131-(13-4)2]
= 24.5-(131-9.2)
= 120-113= 7
tính nhanh mình k nhanh nhé nhưng phải đúng mk sắp muộn rồi
a: \(3^7\cdot27^5\cdot81^3=3^7\cdot3^{15}\cdot3^{12}=3^{34}\)
b: \(36^5:18^5=\left(\dfrac{36}{18}\right)^5=2^5=32\)
c: \(24\cdot5^2+5^2\cdot5^3=24\cdot25+25\cdot125=25\cdot149=3725\)
d: \(\dfrac{125^4}{5^8}=\dfrac{5^{12}}{5^8}=5^4=625\)
a) \(3^7.27^5.81^3\)
\(=3^7.\left(3^3\right)^5.\left(3^4\right)^3\)
\(=3^7.3^{15}.3^{12}\)
\(=3^{34}\)
b) \(36^5:18^5\)
\(=\left(\dfrac{36}{18}\right)^5\)
\(=2^5\)
c) \(24.5^5+5^2.5^3\)
\(=24.5^5+5^5\)
\(=5^5.\left(24+1\right)\)
\(=5^5.25\)
\(=5^5.5^2=5^7\)
d) \(125^4:5^8\)
\(=\left(5^3\right)^4:5^8\)
\(=5^{12}:5^8\)
\(=5^4\)
\(3^{x-1}-2^4.5=1\\ 3^{x-1}-16.5=1\\ 3^{x-1}-80=1\\ \Rightarrow3^{x-1}=1+80\\ 3^{x-1}=81\\ \Rightarrow3^{x-1}=3^4\\ \Rightarrow x-1=4\\ \Rightarrow x=4+1\\ x=5\)
\(3^{x-1}-2^4.5=1\)
\(\Leftrightarrow3^x.3-16.5=1\)
\(\Leftrightarrow3^x.3=81\)
\(\Leftrightarrow3^x=27\)
\(\Leftrightarrow x=3\)