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\(\text{}\text{}\)\(=\frac{27}{43}.\frac{34}{58}-\frac{21}{41}.\frac{1}{2}+\frac{9}{58}:\frac{43}{37}-\frac{6}{29}:\frac{41}{21}\\ =\frac{27}{43}.\frac{34}{58}-\frac{21}{41}.\frac{1}{2}+\frac{9}{58}.\frac{37}{43}-\frac{6}{29}.\frac{21}{41}\)
a) -90/189 + 45/84 - 78/126
= -10/21 + 15/28 - 13/21
= (-10/21 - 13/21) + 15/28
= -24/21 + 15/28
= -17/28
\(A=\frac{-5}{12}+\frac{4}{37}+\frac{17}{12}-\frac{41}{37}=(\frac{-5}{12}+\frac{17}{12})+(\frac{4}{37}-\frac{41}{37})=\frac{12}{12}+\frac{-37}{37}=1+(-1)=0\)
\(B=\frac{1}{2}-\frac{43}{101}+\frac{-1}{3}-\frac{1}{6}=\frac{-43}{101}+(\frac{1}{2}+\frac{-1}{3}-\frac{1}{6})=\frac{-43}{101}+(\frac{3}{6}+\frac{-2}{6}-\frac{1}{6})=\frac{-43}{101}+0=\frac{-43}{101}\)
\(A=\frac{-5}{12}+\frac{4}{37}+\frac{17}{12}-\frac{41}{37}.\)
\(A=\left(\frac{-5}{12}+\frac{17}{12}\right)-\left(\frac{41}{37}-\frac{4}{37}\right)\)
\(A=1-1=0\)
\(B=\frac{1}{2}-\frac{43}{101}+\left(\frac{-1}{3}\right)-\frac{1}{6}\)
\(B=\left(\frac{1}{2}+\left(\frac{-1}{3}\right)-\frac{1}{6}\right)-\frac{43}{101}\)
\(A=0-\frac{43}{101}=\frac{-43}{101}\)
\(C=\frac{-5}{6}\cdot\frac{12}{-7}\cdot-\frac{21}{15}\)
\(C=\frac{-5}{2.3}\cdot\frac{3.2.2}{-7}\cdot\frac{3.\left(-7\right)}{3.5}\)
\(C=\frac{-2}{1}=-2\)
\(E=\frac{\frac{-6}{7}+\frac{6}{13}-\frac{6}{29}}{\frac{9}{7}-\frac{9}{13}+\frac{9}{29}}=\frac{-6.\left(\frac{1}{7}-\frac{1}{13}+\frac{1}{29}\right)}{9.\left(\frac{1}{7}-\frac{1}{13}+\frac{1}{29}\right)}=\frac{-6}{9}=\frac{-2}{3}\)
\(F=\frac{\frac{2}{15}-\frac{2}{21}+\frac{2}{39}}{0,25-\frac{5}{28}+\frac{5}{52}}=\frac{\frac{2}{3}.\left(\frac{1}{5}-\frac{1}{7}+\frac{1}{13}\right)}{\frac{1}{4}-\frac{5}{28}+\frac{5}{52}}\)
\(=\frac{\frac{2}{3}.\left(\frac{1}{5}-\frac{1}{7}+\frac{1}{13}\right)}{\frac{5}{4}.\left(\frac{1}{5}-\frac{1}{7}+\frac{1}{13}\right)}=\frac{2}{3}:\frac{5}{4}=\frac{2}{3}.\frac{4}{5}=\frac{8}{15}\)
Bạn soyeon ơi! Hình như câu đầu bạn làm sai rồi thì phải. Họ ra đề là + đến - nhưng bạn làm - đến +.