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18 tháng 9 2018

a) \(\left(4n^2-6nm+9m^2\right)\left(2n+3m\right)\)

\(=\left(2n+3m\right)\left[\left(2n\right)^2-2n.3m+\left(3m\right)^2\right]\)

\(=\left(2n\right)^3+\left(3m\right)^3\)

\(=8n^3+27m^3\)

b) Sửa đề \(\left(7+2b\right)\left(4b^2-14b+49\right)\)

\(=\left(7+2b\right)\left[\left(2b\right)^2-2b.7+7^2\right]\)

\(=7^3+\left(2b\right)^3\)

\(=343+8b^3\)

c) \(\left(25a^2+10ab+4b^2\right)\left(5a-2b\right)\)

\(=\left(5a-2b\right)\left[\left(5a\right)^2+5a.2b+\left(2b\right)^2\right]\)

\(=\left(5a\right)^3-\left(2b\right)^3\)

\(=125a^3-8b^3\)

d) \(\left(x^2+x+2\right)\left(x^2-x-2\right)\)

\(=\left[x^2+\left(x+2\right)\right]\left[x^2-\left(x+2\right)\right]\)

\(=x^4-\left(x+2\right)^2\)

6 tháng 10 2018

a ) \(\left(a^6-3a^3+9\right)\left(a^3+3\right)=a^9+27\)

b ) Đặt \(a-y=t\) , ta có :

\(\left(t-x\right)^3-\left(t+x\right)^3\)

\(=\left(t-x-t-x\right)\left[\left(t-x\right)^2+\left(t-x\right)\left(t+x\right)+\left(t+x\right)^2\right]\)

\(=-2x\left[t^2-2tx+x^2+t^2-x^2+t^2+2tx+x^2\right]\)

\(=-2x\left[\left(t^2+t^2+t^2\right)+\left(x^2-x^2+x^2\right)+\left(2tx-2tx\right)\right]\)

\(=-2x\left(3t^2+x^2\right)\)

\(=-2x\left[3\left(a-y\right)^2+x^2\right]\)

\(=-2x\left(3a^2-6ay+3y^2+x^2\right)\)

c ) \(\left(4n^2-6mn+9m^2\right)\left(2n+3m\right)=8n^3+27m^3\)

d ) \(\left(25a^2+10ab+4b^2\right)\left(5a-2b\right)=125a^3-8b^3\)

6 tháng 10 2018

a, ( a6 - 3a3 + 9 )(a3+ 3) = (a3)3 - 33 = a9 - 27

b, ( a-x-y)3 - (a+x-y)3 = (a-x-y-a+x-y)(a-x-y+a+x-y)

= (-2y)(2a-2y) = -2y.2(a-y)

c, (4n2- 6mn + 9m2)(2n + 3m) = (2n)3 + (3m)3

= 8n3 + 27m3

d, (25a2 + 10ab +4b2)( 5a - 2b ) = 125a3 - 8b3

a) ( 4n2 - 6mn + 9m2 ) . ( 2n + 3m ) = 

=  ( 2n + 3m ) . ( 4n2 - 6mn + 9m2 )

=          8n3 + 27m3 

b) ( 7 + 2b ) . ( 4b2 - 14b + 49 ) = 

=  ( 2b + 7 ) . ( 4b2 - 14b + 49 )

=            8b3 + 343 

MÌnh nghĩ là chỗ - 4b phải viết là -14b

c) ( 25a2 + 10ab + 4b2 ) . ( 5a - 2b ) = 

= ( 5a - 2b ) . ( 25a2 + 10ab + 4b2 )

=            125a3 - 8b3 

HOk tốt!!!!!!!!!!!!

13 tháng 9 2021

dấu ^ là mũ nha mn

 

18 tháng 10 2020

1, \(16x^2-9=\left(4x\right)^2-3^2=\left(4x-3\right)\left(4x+3\right)\)

2,\(x^2-4+\left(x+2\right)^2=\left(x-2\right)\left(x+2\right)\left(x+2\right)^2=\left(x-2\right)\left(x+2\right)^3\)

3,\(5a\left(a-2\right)-a+2=5a\left(a-2\right)-1\left(a-2\right)=\left(5a-1\right)\left(a-2\right)\)

4,\(7\left(a-5\right)+8a\left(5-a\right)=7\left(a-5\right)-8a\left(a-5\right)=\left(7-8a\right)\left(a-5\right)\)

5, \(25a^2-4b^2+4b-1=25a^2-\left(4b^2-4b+1\right)=\left(5a\right)^2-\left(2b-1\right)^2=\left(5a-2b+1\right)\left(5a+2b-1\right)\)

18 tháng 10 2020

1) (4x-3)(4x+3)

2) (x-2)(x+2)+(x+2)2 = (x+2)(x-2+x+2) = 2x(x+2)

3) 5a(a-2)-(a-2) = (a-2)(5a-1)

4) 7(a-5)-8a(a-5) = (a-5)(7-8a)

5) (25a2-1)+(-4b2+4b) = (5a-1)(5a+1)-4b(b-1)

26 tháng 12 2023

\(\left(2x+1\right)^2-2\left(2x+1\right)\left(3-x\right)+\left(x-3\right)^2\)

\(=\left(2x+1\right)^2+2\left(2x-1\right)\left(x-3\right)+\left(x-3\right)^2\)

\(=\left(2x+1+x-3\right)^2\)

\(=\left(3x-2\right)^2\)

------------------------------------

\(a^3+3a^2-6a-8\)

\(=a^3+4a^2-a^2-4a-2a-8\)

\(=\left(a^3+4a^2\right)-\left(a^2+4a\right)-\left(2a+8\right)\)

\(=a^2\left(a+4\right)-a\left(a+4\right)-2\left(a+4\right)\)

\(=\left(a+4\right)\left(a^2-a-2\right)\)

\(=\left(a+4\right)\left(a^2-2a+a-2\right)\)

\(=\left(a+4\right)\left[\left(a^2-2a\right)+\left(a-2\right)\right]\)

\(=\left(a+4\right)\left[a\left(a-2\right)+\left(a-2\right)\right]\)

\(=\left(a+4\right)\left(a-2\right)\left(a+1\right)\)

---------------------------------

\(2x^2-5x+2\)

\(=2x^2-4x-x+2\)

\(=\left(2x^2-4x\right)-\left(x-2\right)\)

\(=2x\left(x-2\right)-\left(x-2\right)\)

\(=\left(x-2\right)\left(2x-1\right)\)

-----------------------------------------

\(x^2-2x-4y^2-4y\)

\(=\left(x^2-4y^2\right)-\left(2x-4y\right)\)

\(=\left(x-2y\right)\left(x+2y\right)-2\left(x-2y\right)\)

\(=\left(x-2y\right)\left(x+2y-2\right)\)

-------------------------------------

\(a^2-1+4b-4b^2\)

\(=a^2-\left(1-4b+4b^2\right)\)

\(=a^2-\left(1-2b\right)^2\)

\(=\left(a-1+2b\right)\left(a+1-2b\right)\)

----------------------------------------

\(a^4+6a^2b+9b^2-1\)

\(=\left(a^4+6a^2b+9b^2\right)-1\)

\(=\left(a^2+3b\right)^2-1\)

\(=\left(a^2+3b-1\right)\left(a^2+3b+1\right)\)

---------------------------------

\(2x^3+16y^3\)

\(=2\left(x^3+8y^3\right)\)

\(=2\left(x+2y\right)\left(x^2-2xy+4y^2\right)\)

26 tháng 12 2023

Lần sau ghi đề tách riêng từng câu ra nhé em. Ghi dính chùm vậy khó nhìn lắm. Sẽ ít ai giải cho em

31 tháng 8 2019

a) (x - 1)(x + 1)(x2 + 1)(x4 + 1)(x8 + 1)

= (x2 - 1)(x2 + 1)(x4 + 1)(x8 + 1)

= (x4 - 1)(x4 + 1)(x8 + 1)

= (x8 - 1)(x8 + 1)

= x16 - 1

b) (a2 - 2b)(a2 + 2b)(a4 + 4b2)(a8 + 16b4)

= (a4 - 4b2)(a4 + 4b2)(a8 + 16b4)

= (a8 - 16b4)(a8 + 16b4)

= a16 - 256b8