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\(\frac{2.3.4.5+4.6.8.10+6.9.12.15}{2.3.4.5+6.8.10.12+9.12.15.18}\)
= \(\frac{2.3.4.5+2.3.4.5.16+2.3.4.5.81}{2.3.4.5+2.3.4.5.48+2.3.4.5.243}\)
= \(\frac{2.3.4.5.\left(1+16+81\right)}{2.3.4.5.\left(1+48+243\right)}\)
= \(\frac{98}{292}\)
= 49/146
=2.3.4.5+4.6.8.10+6.9.15/2.3.4.5+6.8.10.3.4+9.12.15.6.3
=2.3.4.5+4.6.8.10+6.9.15/3.(2.3.4.5+9.12.15.6)
=1/3
chúc bạn học tốt !
Đặt S=1.2.3.4+2.3.4.5+...+97.98.99.100
5S=1.2.3.4.5+2.3.4.5.5+...+97.98.99.100.5
5S=1.2.3.4.(5 - 0)+2.3.4.5.(6 - 1)+...+97.98.99.100.(101 - 96)
5S=1.2.3.4.5-0.1.2.3.4+2.3.4.5.6-1.2.3.4.5+...+97.98.99.100.101-96.97.98.99
5S=97.98.99.100.101
S=97.98.99.20.101
=>S=1901009880
Đặt A = 1.2.3.4 + 2.3.4.5 + ... + 97.98.99.100
5A = 1.2.3.4.5 + 2.3.4.5.5 + ... + 97.98.99.100.5
5A = 1.2.3.4.5 + 2.3.4.( 6 - 1 ) + ... + 97.98.99.100.( 101 - 96 )
5A = 1.2.3.4.5 + 2.3.4.5.6 - 1.2.3.4.5 + ... + 97.98.99.100.101 - 96.97.98.99.100
5A = 97.98.99.100.101
A = 97.98.99.100.101 : 5
A = 97.98.20.101
A = 19202120
\(A=\dfrac{2.3.4.5+4.6.8.10+6.9.12.15}{2.3.4.5+6.8.10.12+9.12.15.18}\)
\(A=\dfrac{2.3.4.5+2.2.2.3.2.4.2.5.+3.2.3.3.3.4.3.5}{2.3.4.5+2.2.2.3.2.4.2.5+3.3.3.4.3.5.3.6}\)
\(A=\dfrac{2.3.4.5+2^4.2.3.4.5.+3^4.2.3.4.5}{2.3.4.5+2^4.2.3.4.5+3^4.3.4.5.6}\)
\(A=\dfrac{\left(1+2^4+3^4\right)2.3.4.5}{\left(2+2^5+3^4.6\right)3.4.5}\)
\(A=\dfrac{\left(1+2^4+3^4\right)2}{\left(1+2^4+3^5\right).2}\)
\(A=\dfrac{1+2^4+3^4}{1+2^4+3^5}=\dfrac{1+16+81}{1+16+243}=\dfrac{49}{130}\)
\(\dfrac{2.3.4.5+4.6.8.10+6.9.12.15}{2.3.4.5+6.8.10.12+9.12.15.18}\)
\(=\dfrac{4.6.8.10+6.9.12.15}{6.8.10.12+9.12.15.18}\)
\(=\dfrac{1}{3}\)
Kết quả là \(\dfrac{1}{3}\)vì: \(6.8.10.12:4.6.8.10=12:4=3\)
\(9.12.15.18:6.9.12.15=18:6=3\)
Khi cộng vào thì thương không thay đổi và bằng \(\dfrac{1}{3}\)