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\(\left(\dfrac{2}{5}-\dfrac{1}{4}\right):\dfrac{3}{4}x\dfrac{5}{2}=\dfrac{3}{20}:\dfrac{3}{4}x\dfrac{5}{2}=\dfrac{3}{20}x\dfrac{4}{3}x\dfrac{5}{2}=\dfrac{3x4x5}{20x3x2}=\dfrac{1}{2}\)
\(x:3\dfrac{1}{15}\) - \(\dfrac{3}{4}\) = 2\(\dfrac{1}{4}\)
\(x\): \(\dfrac{46}{15}\) - \(\dfrac{3}{4}\) = \(\dfrac{9}{4}\)
\(x\) : \(\dfrac{46}{15}\) = \(\dfrac{9}{4}\) + \(\dfrac{3}{4}\)
\(x\) : \(\dfrac{46}{15}\) = \(\dfrac{12}{4}\)
\(x\) : \(\dfrac{46}{15}\) = \(3\)
\(x\) = 3 \(\times\) \(\dfrac{46}{15}\)
\(x\) = \(\dfrac{46}{5}\)
\(x\) \(\times\) 3\(\dfrac{2}{3}\) - 1\(\dfrac{2}{3}\) = 2\(\dfrac{1}{3}\)
\(x\) \(\times\) \(\dfrac{11}{3}\) - \(\dfrac{5}{3}\) = \(\dfrac{7}{3}\)
\(x\) \(\times\) \(\dfrac{11}{3}\) = \(\dfrac{7}{3}\) + \(\dfrac{5}{3}\)
\(x\) \(\times\) \(\dfrac{11}{3}\) = \(\dfrac{12}{3}\)
\(x\times\dfrac{11}{3}\) = 4
\(x\) = 4 : \(\dfrac{11}{3}\)
\(x\) = \(\dfrac{12}{11}\)
Lời giải:
$x-\frac{x}{3}\times \frac{3}{2}=2-\frac{1}{2}$
$x-x\times \frac{1}{2}=\frac{3}{2}$
$x\times (1-\frac{1}{2})=\frac{3}{2}$
$x\times \frac{1}{2}=\frac{3}{2}$
$x=\frac{3}{2}: \frac{1}{2}=3$
Ta có \(\frac{2}{5}x+\frac{1}{3}x=\frac{3}{5}\)
\(\Rightarrow x.\left(\frac{2}{5}+\frac{1}{3}\right)=\frac{3}{5}\)
\(\Rightarrow x.\frac{8}{15}=\frac{3}{5}\)
\(\Rightarrow x=\frac{9}{8}\)
\(\Rightarrow x+\dfrac{1}{6}=\dfrac{3}{4}\\ \Rightarrow x=\dfrac{7}{12}\)
A) \(x-\dfrac{2}{3}=\dfrac{4}{5}\\ x=\dfrac{4}{5}+\dfrac{2}{3}\)
\(x=\dfrac{22}{15}\)
b)\(\dfrac{7}{9}-x=\dfrac{1}{3}\\ x=\dfrac{7}{9}-\dfrac{1}{3}\\ x=\dfrac{4}{9}\)
C)\(x:\dfrac{2}{3}=\dfrac{9}{8}\\ x=\dfrac{9}{8}x\dfrac{2}{3}\\ x=\dfrac{3}{4}\)
\(x-\dfrac{1}{3}=\dfrac{2}{3}.\dfrac{9}{14}+\dfrac{3}{7}\)
\(x-\dfrac{1}{3}=\dfrac{1}{7}+\dfrac{3}{7}\)
\(x-\dfrac{1}{3}=\dfrac{4}{7}\)
\(x=\dfrac{19}{21}\)
1/3 + x = 3/2 x 3
1/3 + x = 9/2
x = 9/2 - 1/3 = 25/6
Kết quả là 25/6