(\(2\frac{1}{3}\)+3,5) :\(\left(-4\frac{1}{6}+3\frac{1}{7}\right)\)+7,5
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N
2
14 tháng 8 2020
\(M=\left(2\frac{1}{3}+3,5\right):\left(-4\frac{1}{6}+3\frac{1}{7}\right)+7,5\)
\(M=\left(\frac{7}{3}+\frac{7}{2}\right):\left(-\frac{25}{6}+\frac{22}{7}\right)+\frac{15}{2}\)
\(M=\frac{35}{6}:\left(-\frac{43}{42}\right)+\frac{15}{2}\)
\(M=\frac{35}{6}\cdot\left(-\frac{42}{43}\right)+\frac{15}{2}\)
\(M=\frac{35}{1}\cdot\left(-\frac{7}{43}\right)+\frac{15}{2}=-\frac{245}{43}+\frac{15}{2}=\frac{155}{86}\)
14 tháng 8 2020
\(m=\left(\frac{7}{3}+3,5\right):\left(-\frac{25}{6}+\frac{22}{7}\right)+7,5\)
\(m=\frac{35}{6}:-\frac{25}{6}+7,5\)
\(m=\frac{35}{6}.-\frac{6}{25}+7,5\)
\(m=-\frac{7}{5}+7,5\)
\(m=\frac{61}{10}\)
T
1
15 tháng 12 2017
\(A=\left(2\frac{1}{3}+3,5\right):\left(-4\frac{1}{6}+3\frac{1}{7}\right)+7,5\)
\(A=\left(\frac{7}{3}+3,5\right):\left(\frac{-25}{6}+\frac{22}{7}\right)+7,5\)
\(A=\frac{35}{6}:\frac{-43}{42}+7,5\)
\(A=\frac{-245}{43}+7,5\)
\(A=\frac{155}{86}\)
HV
0
V
2
MT
7 tháng 6 2015
\(M=\left(2\frac{1}{3}+3,5\right):\left(-4\frac{1}{6}+3\frac{1}{7}\right)+7,5\)
\(=\left(\frac{7}{3}+\frac{7}{2}\right):\left(\frac{-25}{6}+\frac{22}{7}\right)+\frac{15}{2}\)
\(=\left(\frac{14}{6}+\frac{21}{6}\right):\left(\frac{-175}{42}+\frac{132}{42}\right)+\frac{15}{2}\)
\(=\frac{14+21}{6}:\frac{-175+132}{42}+\frac{15}{2}\)
\(=\frac{35}{6}:\frac{-43}{42}+\frac{15}{2}=\frac{35}{6}.\frac{-42}{43}+\frac{15}{2}\)
\(=\frac{-245}{43}+\frac{15}{2}=\frac{-490}{86}+\frac{645}{86}\)
\(=\frac{-490+645}{86}=\frac{155}{86}\)
B
30 tháng 4 2019
\(\left(\frac{3}{8}+-\frac{3}{4}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)
\(=\left(\frac{9}{24}+-\frac{18}{24}+\frac{14}{24}\right):\frac{5}{6}+\frac{1}{2}\)
\(=\frac{5}{24}:\frac{5}{6}+\frac{1}{2}\)
\(=\frac{5}{24}.\frac{6}{5}+\frac{1}{2}\)
\(=\frac{1}{4}+\frac{1}{2}\)
\(=\frac{1}{4}+\frac{2}{4}\)
\(=\frac{3}{4}\)
B
30 tháng 4 2019
\(\frac{1}{2}+\frac{3}{4}-\left(\frac{3}{4}-\frac{4}{5}\right)\)
\(=\frac{1}{2}+\frac{3}{4}-\left(\frac{15}{20}-\frac{16}{20}\right)\)
\(=\frac{1}{2}+\frac{3}{4}-\frac{-1}{20}\)
\(=\frac{10}{20}+\frac{15}{20}-\frac{-1}{20}\)
\(=\frac{25}{20}-\frac{-1}{20}\)
\(=\frac{26}{20}\)
\(=\frac{13}{10}\)
8 tháng 4 2022
a: \(=\dfrac{5}{3}\left(-16-\dfrac{2}{7}+28+\dfrac{2}{7}\right)=\dfrac{5}{3}\cdot12=20\)
b: \(=\left(4\cdot\dfrac{3}{4}-\dfrac{1}{2}\right)\cdot\dfrac{6}{5}-17=\dfrac{1}{2}\cdot\dfrac{6}{5}-17=\dfrac{3}{5}-17=-\dfrac{82}{5}\)
c: \(=-\left(\dfrac{1}{3}\right)^{50}\cdot3^{50}-\dfrac{2}{3}\cdot\dfrac{1}{4}=-1-\dfrac{1}{6}=-\dfrac{7}{6}\)
e: \(=5.7\left(-6.5-3.5\right)=-5.7\cdot10=-57\)
28 tháng 5 2020
1) \(\left(\frac{7}{8}-\frac{3}{4}\right).1\frac{1}{3}-\frac{2}{7}.\left(3,5\right)^2\)
= \(\frac{1}{8}.\frac{4}{3}-\frac{2}{7}.\frac{49}{4}\) = \(\frac{-10}{3}\)
2) \(\frac{5}{4}:\frac{1}{2}-\frac{3}{4}\) = \(\frac{7}{4}\)
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