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\(M=\left(2\frac{1}{3}+3,5\right):\left(-4\frac{1}{6}+3\frac{1}{7}\right)+7,5\)
\(=\left(\frac{7}{3}+\frac{7}{2}\right):\left(\frac{-25}{6}+\frac{22}{7}\right)+\frac{15}{2}\)
\(=\left(\frac{14}{6}+\frac{21}{6}\right):\left(\frac{-175}{42}+\frac{132}{42}\right)+\frac{15}{2}\)
\(=\frac{14+21}{6}:\frac{-175+132}{42}+\frac{15}{2}\)
\(=\frac{35}{6}:\frac{-43}{42}+\frac{15}{2}=\frac{35}{6}.\frac{-42}{43}+\frac{15}{2}\)
\(=\frac{-245}{43}+\frac{15}{2}=\frac{-490}{86}+\frac{645}{86}\)
\(=\frac{-490+645}{86}=\frac{155}{86}\)
\(A=\left(2\frac{1}{3}+3,5\right):\left(-4\frac{1}{6}+3\frac{1}{7}\right)+7,5\)
\(A=\left(\frac{7}{3}+3,5\right):\left(\frac{-25}{6}+\frac{22}{7}\right)+7,5\)
\(A=\frac{35}{6}:\frac{-43}{42}+7,5\)
\(A=\frac{-245}{43}+7,5\)
\(A=\frac{155}{86}\)
a: \(=\dfrac{5}{3}\left(-16-\dfrac{2}{7}+28+\dfrac{2}{7}\right)=\dfrac{5}{3}\cdot12=20\)
b: \(=\left(4\cdot\dfrac{3}{4}-\dfrac{1}{2}\right)\cdot\dfrac{6}{5}-17=\dfrac{1}{2}\cdot\dfrac{6}{5}-17=\dfrac{3}{5}-17=-\dfrac{82}{5}\)
c: \(=-\left(\dfrac{1}{3}\right)^{50}\cdot3^{50}-\dfrac{2}{3}\cdot\dfrac{1}{4}=-1-\dfrac{1}{6}=-\dfrac{7}{6}\)
e: \(=5.7\left(-6.5-3.5\right)=-5.7\cdot10=-57\)
\(M=\left(2\frac{1}{3}+3,5\right):\left(-4\frac{1}{6}+3\frac{1}{7}\right)+7,5\)
\(M=\left(\frac{7}{3}+\frac{7}{2}\right):\left(-\frac{25}{6}+\frac{22}{7}\right)+\frac{15}{2}\)
\(M=\frac{35}{6}:\left(-\frac{43}{42}\right)+\frac{15}{2}\)
\(M=\frac{35}{6}\cdot\left(-\frac{42}{43}\right)+\frac{15}{2}\)
\(M=\frac{35}{1}\cdot\left(-\frac{7}{43}\right)+\frac{15}{2}=-\frac{245}{43}+\frac{15}{2}=\frac{155}{86}\)
\(m=\left(\frac{7}{3}+3,5\right):\left(-\frac{25}{6}+\frac{22}{7}\right)+7,5\)
\(m=\frac{35}{6}:-\frac{25}{6}+7,5\)
\(m=\frac{35}{6}.-\frac{6}{25}+7,5\)
\(m=-\frac{7}{5}+7,5\)
\(m=\frac{61}{10}\)