Rút gọn
N=4^6.9^5+6^9.120:8^4.3^12-6^11
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\(\dfrac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
\(=\dfrac{2^{12}.3^{10}+2^9.3^9.2^3.3.5}{2^{12}.3^{12}-2^{11}.3^{11}}\)
\(=\dfrac{2^{12}.3^{10}+2^{12}.3^{10}.5}{2^{11}.3^{11}\left(2.3-1\right)}\)
\(=\dfrac{2^{12}.3^{10}\left(1+5\right)}{2^{11}.3^{11}.5}\)
\(=\dfrac{2^{12}.3^{10}.6}{2^{11}.3^{11}.5}=\dfrac{2.6}{3.5}=\dfrac{4}{5}\)
\(N=\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}=\frac{2^{12}.3^{15}+2^9.3^9.2^3.3.5}{2^{12}.3^{12}-2^{11}.3^{11}}=\frac{2^{12}.3^{15}+2^{12}.3^{10}.5}{2^{12}.3^{12}-2^{11}.3^{11}}=\frac{2^{12}.3^{10}\left(3^5+5\right)}{2^{11}.3^{11}\left(2.3-1\right)}\)
cho mk sửa lại xíu:
\(\frac{2^{12}.3^{10}\left(1+5\right)}{2^{11}.3^{11}.5}=\frac{2.6}{3.5}=\frac{12}{15}=\frac{4}{5}\)
mk sai xíu. hihi, học tốt nhé !
\(\frac{2^{12}.3^{10}+2^9.3^9.2^3.3.5}{2^{12}.3^{12}-2^{11}.3^{11}}=\frac{2^{12}.3^{10}+2^{12}.3^{10}.5}{2^{12}.3^{12}-2^{11}.3^{11}}=\frac{2^{12}.3^{10}.\left(1+5\right)}{2^{11}.3^{11}.\left(6-1\right)}=\frac{2.6}{3.5}=\frac{4}{5}\)
\(\frac{\left(2^2\right)^6.\left(3^2\right)^5+2^9.3^9.120}{\left(2^3\right)^4.3^{12}-2^{11}.3^{11}}\)=\(\frac{2^{12}.3^{10}+2^9.3^9.120}{2^{12}.3^{12}-2^{11}.3^{11}}\)=\(\frac{120}{3^2-2^3.3^3}\)=\(\frac{120}{9-8.27}\)=\(\frac{120}{-207}\)=\(\frac{-40}{69}\)
tk cho mk nhe
A=(2^2)^6.(3^2)^5+2^9.3^9.2^3.5.3/2^12.3^10+2^11.3^11
=2^12.3^10+2^12.3^10.5/2^12.3^10+2^11.3.3^10
=2^12.3^10.(1+5)/2^11.3^10.(2+3)
=2^11.2.6/2^11.5
=12/5
\(=\dfrac{-2^{12}\cdot3^{10}-2^{12}\cdot3^{10}\cdot5}{-2^{12}\cdot3^{12}-2^{11}\cdot3^{11}}=\dfrac{2^{12}\cdot3^{10}\cdot6}{2^{11}\cdot3^{11}\cdot7}=\dfrac{2\cdot6}{3\cdot7}=\dfrac{12}{21}=\dfrac{4}{7}\)
ket qua bang 29 nha ban
ket qua bang -4/3 nha ban