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TL
\(5\frac{1}{5}=5,2\)
HT Ạ
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\(2\dfrac{3}{4}=\dfrac{2\times4+3}{4}=\dfrac{11}{4}\\ 3\dfrac{4}{5}=\dfrac{3\times5+4}{5}=\dfrac{19}{5}\\ 4\dfrac{3}{5}=\dfrac{4\times5+3}{5}=\dfrac{23}{5}\\ 11\dfrac{12}{13}=\dfrac{11\times13+12}{13}=\dfrac{155}{13}\\ 12\dfrac{11}{13}=\dfrac{12\times13+11}{13}=\dfrac{167}{13}\\ 3\dfrac{3}{5}=\dfrac{3\times5+3}{5}=\dfrac{18}{5}\)
2\(\dfrac{3}{4}\)=\(\dfrac{11}{4}\)
3\(\dfrac{4}{5}\)=\(\dfrac{19}{5}\)
4\(\dfrac{3}{5}\)=\(\dfrac{23}{5}\)
11\(\dfrac{12}{13}\)=\(\dfrac{155}{13}\)
12\(\dfrac{11}{13}\)=\(\dfrac{167}{13}\)
3\(\dfrac{3}{5}\)=\(\dfrac{18}{5}\).
Bài 1:
a) \(2\frac{1}{4}+1\frac{1}{2}-1\frac{4}{5}\)
=\(\frac{9}{4}\)+\(\frac{3}{2}\)-\(\frac{9}{5}\)
=\(\frac{45}{20}+\frac{30}{20}-\frac{36}{20}\)
=\(\frac{39}{20}\)
b) \(2\frac{2}{3}\times3\frac{1}{4}:2\frac{3}{4}\)
\(\frac{8}{3}\times\frac{13}{4}:\frac{11}{4}\)
=\(\frac{8}{3}\times\frac{13}{4}\times\frac{4}{11}\)
=\(\frac{104}{33}\)
Bài 2:
a) \(\frac{7}{9}+\frac{4}{5}+\frac{11}{9}+\frac{6}{5}\)
=\(\left(\frac{7}{9}+\frac{11}{9}\right)+\left(\frac{4}{5}+\frac{6}{5}\right)\)
=2+2
=4
b) \(\frac{21}{36}\times\frac{39}{14}\times\frac{54}{13}\)
=\(\frac{21\times39\times54}{36\times14\times13}\)
=\(\frac{675}{100}\)
4,25=4\(\dfrac{1}{4}\);7,82=7\(\dfrac{41}{50}\);24,102=24\(\dfrac{51}{500}\);27,012=27\(\dfrac{3}{250}\)
a)\(\frac{7}{3}=2\frac{1}{3},\frac{53}{17}=3\frac{2}{17},\frac{60}{21}=2\frac{6}{7},\frac{76}{15}=5\frac{1}{15},\frac{45}{14}=3\frac{3}{14}\)
b)\(\frac{22}{3}=7\frac{1}{3},\frac{57}{8}=7\frac{1}{8},\frac{123}{11}=11\frac{2}{11},\frac{139}{13}=10\frac{9}{13},\frac{9}{2}=4\frac{1}{2}\)
Bài 1:
\(\dfrac{14}{5}=\dfrac{10+4}{5}=2+\dfrac{4}{5}=2\dfrac{4}{5}\)
\(\dfrac{29}{7}=\dfrac{28+1}{7}=4+\dfrac{1}{7}=4\dfrac{1}{7}\)
\(\dfrac{100}{24}=\dfrac{25}{6}=\dfrac{24+1}{6}=4+\dfrac{1}{6}=4\dfrac{1}{6}\)
\(\dfrac{32}{7}=\dfrac{28+4}{7}=4+\dfrac{4}{7}=4\dfrac{4}{7}\)
\(\dfrac{315}{100}=\dfrac{63}{20}=\dfrac{60+3}{20}=3+\dfrac{3}{20}=3\dfrac{3}{20}\)