-17-(-37).4
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= (-5/12 + 17/12) + ( 4/37 - 41/37)
= 12/12 + (-37/37)
=1 + (-1)
=0
a ) 5 x 216 x 25 x 4 = 1080 x 100 = 108000
b ) 37 x 16 x 25 x 4 = 592 x 100 = 59200
c ) 36 x ( 28 + 82 ) + 64 x ( 69 + 41 ) = 36 x 110 + 64 x 110 = ( 36 + 64 ) x 110 = 100 x 110 = 11000
d ) 42 x ( 53 + 36 + 11 ) = 42 x 100 = 4200
e) 37 x 45 + 56 x 37 - 37 x 1 = 37 x ( 45 + 56 - 1 ) = 37 x 100 = 3700
h) 17 x 1 + 17 x 81 + 18 x 17 = 17 x ( 1 + 81 + 18 ) = 17 x 100 = 1700
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a) 5 x 25 x 216 x 4
= ( 5 x 216 ) x ( 25 x 4 )
= 1080 x 100
= 108000
b) 4 x 37 x 25 x 16
= ( 4 x 25 ) x ( 37 x 16 )
= 100 x 592
= 59200
tui ko viet dc kiểu p/số nên viết cái gạch ngang giữa kết quả nha
\(A=\frac{8+\frac{8}{17}+\frac{8}{37}}{4+\frac{4}{17}+\frac{4}{37}}\)
\(A=\frac{8\cdot\left(1+\frac{1}{17}+\frac{1}{37}\right)}{4\cdot\left(1+\frac{1}{17}+\frac{1}{37}\right)}\)
\(A=\frac{8}{4}\)
\(A=2\)
37(-4) + (-4).17.(-25) + (-4).15
= 37(-4) + (-4) . (-425) + (-4) . 15
= (37 + (-425) + 15) .(-4)
= (-373) . (-4)
= 1492
\(=\left(\dfrac{3}{4}+\dfrac{1}{4}\right)+\left(-\dfrac{17}{25}-\dfrac{8}{25}\right)+\left(\dfrac{13}{37}+\dfrac{24}{37}\right)=1\)
\(2575+37-2576-29\)
\(=2612-2576-29\)
\(=36-29=7\)'
\(35+35+36+37-14-15-16-17\)
\(=70+\left(36-16\right)+\left(37-17\right)-14-15\)
\(=70+20+20-14-15\)
\(=90+6-15\)
\(=96-15=81\)
\(13\cdot\left(-12\right)+87.\left(-12\right)\)
\(=\left(-12\right)\cdot\left(13+87\right)\)
\(=\left(-12\right)\cdot100=-1200\)
\(26\cdot17+17\cdot74\)
\(=\left(26+74\right)\cdot17\)
\(=100\cdot17=1700\)
\(25\cdot\left(-18\right)+25\left(-82\right)\)
\(=25\cdot\left[\left(-18\right)+\left(-82\right)\right]\)
\(=25\cdot\left(-100\right)=\left(-2500\right)\)
\(25+37-48-25-37\)
\(=\left(25-25\right)+\left(37-37\right)-48\)
\(=0+0-48\)
\(=0-48=\left(-48\right)\)
\(\left(-16\right)+24+16-34\)
\(=\left[\left(-16\right)+16\right]+\left(24-34\right)\)
\(=0+\left(-10\right)=\left(-10\right)\)
\(-1\dfrac{1}{5}.\dfrac{12+\dfrac{4}{3}-\dfrac{12}{37}-\dfrac{12}{35}}{3+\dfrac{1}{3}-\dfrac{3}{37}-\dfrac{3}{35}}:\dfrac{4+\dfrac{4}{17}+\dfrac{4}{19}+\dfrac{4}{2003}}{5+\dfrac{5}{17}+\dfrac{5}{19}+\dfrac{5}{2003}}\)
\(=\dfrac{-6}{5}.\dfrac{4\left(3+\dfrac{1}{3}-\dfrac{3}{37}-\dfrac{3}{35}\right)}{3+\dfrac{1}{3}-\dfrac{3}{37}-\dfrac{3}{35}}:\dfrac{4\left(1+\dfrac{1}{17}+\dfrac{1}{19}+\dfrac{1}{2003}\right)}{5\left(1+\dfrac{1}{17}+\dfrac{1}{19}+\dfrac{1}{2003}\right)}\)
\(=\dfrac{-6}{5}.4:\dfrac{4}{5}\)
\(=\dfrac{-6.4.5}{5.4}=-6\)
-17 - (-37) × 4 = 131
-17 - (-37).4
= -17 + 37.4
= -17 + 148
= -17 + 148
= 131