5/4.7 + 5/7.10 + ... + 5/73.76
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A=\(\frac{1}{4.7}+\frac{1}{7.10}+\frac{1}{10.13}+...+\frac{1}{73.76}\)
3A=3(\(\frac{1}{4.7}+\frac{1}{7.10}+\frac{1}{10.13}+...+\frac{1}{73.76}\))
3A=\(\frac{3}{4.7}+\frac{3}{7.10}+\frac{3}{10.13}+...+\frac{3}{73.76}\)
3A=\(\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+\frac{1}{10}-\frac{1}{13}+...+\frac{1}{73}+\frac{1}{76}\)
3A=\(\frac{1}{4}-\frac{1}{76}\)
3A=\(\frac{9}{38}\)
A=\(\frac{9}{38}\):3
A=\(\frac{3}{38}\)
đặt A=1/4.7+1/7.10+...+1/73.76
3A=1/4-1/7+1/7-1/10+...+1/ 73 -1/ 76
Ta có : A = 2/ 4.7 + 2/ 7.10 + ... + 2/ 73.76 .
⇒ 3/2 A = 3/2 . ( 2/ 4.7 + 2/ 7.10 + ... + 2/ 73.76 ) .
⇒ 3/2 A = 3/ 4.7 + 3/ 7.10 + ... + 3/ 73.76 .
= 1/4 - 1/7 + 1/7 - 1/10 + ... + 1/ 73 - 1/76 .
= 1/4 - 1/76 .
= 19/76 - 1/76 .
= 9/38 .
Do đó : A = 9/38 : 3/2 .
= 9/38 . 2/3 .
= 3/19 .
Vậy A = 3/19 .
\(A=\frac{2}{4.7}+\frac{2}{7.10}+\frac{2}{10.13}+.....+\frac{2}{73.76}\)
\(=\frac{2}{3}\left(\frac{3}{4.7}+\frac{3}{7.10}+\frac{3}{10.13}+....+\frac{3}{73.76}\right)\)
\(=\frac{2}{3}\left(\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+....+\frac{1}{73}-\frac{1}{76}\right)\)
\(=\frac{2}{3}\left(\frac{1}{4}-\frac{1}{76}\right)\)
\(=\frac{2}{3}.\frac{9}{38}=\frac{3}{19}\)
A=6/4.7+6/7.10+6/10.13+...+6/73.76
\(=2.\left(\frac{3}{4.7}+\frac{3}{7.10}+\frac{3}{10.13}+...+\frac{3}{73.76}\right)\)
\(=2.\left(\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+\frac{1}{10}-\frac{1}{13}+...+\frac{1}{73}-\frac{1}{76}\right)\)
\(=2.\left(\frac{1}{4}-\frac{1}{76}\right)=2.\frac{9}{38}=\frac{9}{19}\)
3/4.7 + 3/7.10 + ...+ 3/73.76
=1/4 - 1/7 +1/7 - 1/10 + ... + 1/73 - 1/76
=1/4 - 1/76
=18/76
=9/38
\(\frac{3}{4x7}+\frac{3}{7x10}+.......+\frac{3}{73x76}\)
=\(\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{73}-\frac{1}{76}\)
\(=\frac{1}{4}-\frac{1}{76}\)
\(=\frac{9}{38}\)
Đáp số :\(\frac{9}{38}\)
\(=>C=\frac{3}{4}-\frac{3}{7}+\frac{3}{7}-\frac{3}{10}+....+\frac{3}{73}-\frac{3}{76}\)
\(=>C=\frac{3}{4}-\frac{3}{76}\)
\(=>C=\frac{54}{76}\)
\(=>C=\frac{27}{38}\)
\(C=\frac{3}{4.7}+\frac{3}{7.10}+\frac{3}{10.13}+....+\frac{3}{73.76}\)
=> Cộng vế với vế , ta được :
\(C=\frac{3}{3}\left(\frac{1}{4.7}+\frac{1}{7.10}+\frac{1}{10.13}+....+\frac{1}{73.76}\right)\)
\(\Rightarrow C=1\left(\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+....+\frac{1}{73}-\frac{1}{76}\right)\)
\(\Rightarrow C=1\left(\frac{1}{4}-\frac{1}{76}\right)\)
\(\Rightarrow C=1\left(\frac{19}{76}-\frac{1}{76}\right)=1\frac{18}{76}\)
\(\dfrac{5}{4\cdot7}+\dfrac{5}{7\cdot10}+\dots+\dfrac{5}{73\cdot76}\)
\(=\dfrac{5}{3}\cdot\left(\dfrac{3}{4\cdot7}+\dfrac{3}{7\cdot10}+\dots+\dfrac{3}{73\cdot76}\right)\)
\(=\dfrac{5}{3}\cdot\left(\dfrac{1}{4}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{10}+\dots+\dfrac{1}{73}-\dfrac{1}{76}\right)\)
\(=\dfrac{5}{3}\cdot\left(\dfrac{1}{4}-\dfrac{1}{76}\right)\)
\(=\dfrac{5}{3}\cdot\dfrac{9}{38}\)
\(=\dfrac{15}{38}\)
\(\dfrac{5}{4.7}\) + \(\dfrac{5}{7.10}\) + ... + \(\dfrac{5}{73.76}\)
= \(\dfrac{5}{3}\).( \(\dfrac{3}{4.7}\) + \(\dfrac{3}{7.10}\) + ... + \(\dfrac{3}{73.76}\))
= \(\dfrac{5}{3}\). ( \(\dfrac{1}{4}\) - \(\dfrac{1}{7}\) + \(\dfrac{1}{7}\) - \(\dfrac{1}{10}\) + ... + \(\dfrac{1}{73}\) - \(\dfrac{1}{76}\))
= \(\dfrac{5}{3}\). ( \(\dfrac{1}{4}\) - \(\dfrac{1}{76}\))
= \(\dfrac{5}{3}\). \(\dfrac{9}{38}\)
= \(\dfrac{15}{38}\)