128+36
ai nhanh cho 1 like
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16x = 1284 = > ( 24 )x = ( 27)4 = > 24x = 228 = > 4x =28= > x= 7
\(16^x=128^4=>\left(2^4\right)^x=\left(2^7\right)^4=>2^{4x}=2^{28}=>4x=28=>x=7\)
vậy x=7
tick nhé
A = \(\dfrac{1}{2}\) + \(\dfrac{1}{4}\) + \(\dfrac{1}{8}\) + \(\dfrac{1}{16}\)+ \(\dfrac{1}{32}\)+\(\dfrac{1}{64}\)+\(\dfrac{1}{128}\)
A\(\times\) 2 = 1 + \(\dfrac{1}{2}\) + \(\dfrac{1}{4}\) + \(\dfrac{1}{8}\) + \(\dfrac{1}{16}\)+ \(\dfrac{1}{32}\)+ \(\dfrac{1}{64}\)
A \(\times\) 2 - A = 1 - \(\dfrac{1}{128}\)
A\(\times\)(2-1) = \(\dfrac{128-1}{128}\)
A = \(\dfrac{127}{128}\)
Gọi \(\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}+\dfrac{1}{32}+\dfrac{1}{64}+\dfrac{1}{128}\) là B
\(B=\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}+\dfrac{1}{32}+\dfrac{1}{64}+\dfrac{1}{128}\)
\(2\cdot B=1+\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{12}+\dfrac{1}{32}+\dfrac{1}{64}\)
\(2\cdot B-B=1+\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{12}+\dfrac{1}{32}+\dfrac{1}{64}-\left(\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}+\dfrac{1}{32}+\dfrac{1}{64}+\dfrac{1}{128}\right)\)
\(B=1+\left(\dfrac{1}{2}-\dfrac{1}{2}+\dfrac{1}{4}-\dfrac{1}{4}+.....+\dfrac{1}{64}-\dfrac{1}{64}\right)-\dfrac{1}{128}\)
\(B=1+0-\dfrac{1}{128}\)
\(B=1-\dfrac{1}{128}\)
\(B=\dfrac{128}{128}-\dfrac{1}{128}\)
\(B=\dfrac{127}{128}\)
A = 2014 x ( 128 x 68 - 64 x 136 ) + 2015
A = 2014 x 0 + 2015
A = 0 + 2015
A = 2015
Chúc bạn học tốt !
= 2014 x ( 8704 - 8704 ) + 2015
= 2014 x 0 + 2015
A = 0 + 2015 = 2015
= 128/256 + 64/256 + 32/256 + 16/256 + 8/256 + 4/256 + 2/256 + 1/256
= 255/256
#)Giải :
\(\left[\left(-\frac{56}{64}\right)--\left(\frac{1}{9}\div\frac{8}{27}\right)-\frac{1}{3}\right]\div-\frac{81}{128}\)
\(\Leftrightarrow\left[\left(-\frac{7}{8}\right)-\left(-\frac{3}{8}\right)-\frac{1}{3}\right]\div\left(-\frac{81}{128}\right)\)
\(\Leftrightarrow\left(-\frac{5}{6}\right)\div\left(-\frac{81}{128}\right)\)
\(\Leftrightarrow\frac{320}{243}\)
128 + 36
= 164
nha bn
128 + 36 = 164
cho bạn