012+1=???????????????
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LH
21 tháng 7 2021
\(2,4-0,12-x=0,09\)
\(\Rightarrow2,28-x=0,09\)\(\Rightarrow x=2,28-0,09=2,19\)
~~ HT ~~
20 tháng 10 2023
11: |2x-3|-1/3=0
=>|2x-3|=1/3
=>\(\left[{}\begin{matrix}2x-3=\dfrac{1}{3}\\2x-3=-\dfrac{1}{3}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=\dfrac{10}{3}\\2x=\dfrac{8}{3}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{5}{3}\\x=\dfrac{4}{3}\end{matrix}\right.\)
12: \(\dfrac{5}{6}-\left|x+\dfrac{1}{4}\right|=\dfrac{1}{4}\)
=>\(\left|x+\dfrac{1}{4}\right|=\dfrac{5}{6}-\dfrac{1}{4}=\dfrac{10}{12}-\dfrac{3}{12}=\dfrac{7}{12}\)
=>\(\left[{}\begin{matrix}x+\dfrac{1}{4}=\dfrac{7}{12}\\x+\dfrac{1}{4}=-\dfrac{7}{12}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{3}\\x=-\dfrac{11}{12}\end{matrix}\right.\)
13: \(\left|x-1\right|-2x=\dfrac{1}{2}\)
=>\(\left|x-1\right|=2x+\dfrac{1}{2}\)
=>\(\Leftrightarrow\left\{{}\begin{matrix}x>=-\dfrac{1}{4}\\\left(2x+\dfrac{1}{2}\right)^2=\left(x-1\right)^2\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}x>=-\dfrac{1}{4}\\\left(2x+\dfrac{1}{2}-x+1\right)\left(2x+\dfrac{1}{2}+x-1\right)=0\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}x>=-\dfrac{1}{4}\\\left(x+\dfrac{3}{2}\right)\left(3x-\dfrac{1}{2}\right)=0\end{matrix}\right.\Leftrightarrow x=\dfrac{1}{6}\)
14: \(3x-\left|x+15\right|=\dfrac{5}{4}\)
=>\(\left|x+15\right|=3x-\dfrac{5}{4}\)
=>\(\left\{{}\begin{matrix}x>=\dfrac{5}{12}\\\left(3x-\dfrac{5}{4}\right)^2=\left(x+15\right)^2\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}x>=\dfrac{5}{12}\\\left(3x-\dfrac{5}{4}-x-15\right)\left(3x-\dfrac{5}{4}+x+15\right)=0\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}x>=\dfrac{5}{12}\\\left(2x-16.25\right)\left(4x+\dfrac{55}{4}\right)=0\end{matrix}\right.\)
=>\(x=8.125\)
VH
29 tháng 8 2018
2002 x 20012001 = ( 2001 + 1 ) . 20012001 = 2001 x 20012001 + 20012001
2001 x 20022002 = 2001 x ( 20012001 + 10001 ) = 2001 x 20012001 + 2001 x 10001
Ta có 2001 x 20012001 + 20012001 - ( 2001 x 20012001 + 2001 x 10001 )
= 2001 x 20012001 + 20012001 - 2001 x 20012001 - 2001 x 10001
= ( 2001 x 20012001 - 2001 x 20012001 ) + ( 20012001 - 2001 x 10001 )
= 0 + ( 20012001 - 20012001 )
= 0 + 0
= 0
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
18 tháng 1
A = 1 + 22 + 23 + ...+ 22012
2.A = 2 + 23+ 24 +...+ 22013
2A - A = 2 + 22+ 23 + 24 +...+ 22013 - (1 + 22 + 23 + ... + 22012)
A = 2 + 22 + 24 + .. + 22013 - 1 - 22 - 23 -...- 22012
A = (2 - 22) + (23 - 23) + (24 - 24) + (25 - 25) + (22012 - 22012) + (22013 - 1)
A = -2 + 0 +...+ 0 + 22013 - 1
A = 22013 - 3
QT
1
012+1=013
tk nhé
012+1=13
k nha!