d) 1/ 2.3.4 + 1 /3.4.5 + 1/ 4.5.6 +...+ 1 /18.19 20
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Em nói thật em mới học lớp 6 Màu em đã phải làm bài này rồi thật đấu không phải đùa đâu
Đặt \(A=\frac{1}{1.2.3}+\frac{1}{2.3.4}+\frac{1}{3.4.5}+\frac{1}{4.5.6}+\frac{1}{5.6.7}+\frac{1}{6.7.8}+\frac{1}{7.8.9}+\frac{1}{8.9.10}\)
\(2A=\frac{2}{1.2.3}+\frac{2}{2.3.4}+\frac{2}{3.4.5}+\frac{2}{4.5.6}+\frac{2}{5.6.7}+\frac{2}{6.7.8}+\frac{2}{7.8.9}+\frac{2}{8.9.10}\)
\(2A=\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+\frac{1}{3.4}-\frac{1}{4.5}+\frac{1}{4.5}-\frac{1}{5.6}+...+\frac{1}{8.9}-\frac{1}{9.10}\)
\(2A=\frac{1}{1.2}-\frac{1}{9.10}=\frac{22}{45}\)
\(A=\frac{22}{45}:2=\frac{11}{45}\)
1/ 1.2.3 + 1/ 2.3.4 + 1/ 3.4.5+1/4.5.6+1/5.6.7+1/6.7.8+1/7.8.9+1/8.9.10
= 1 - 1/2 - 1/3 + 1/2 - 1/3 - 1/4 + 1/3 - 1/4 - 1/5 + 1/5 - 1/6 - 1/7 + 1/6 - 1/7 - 1/8 + 1/7 - 1/8 - 1/9 + 1/8 - 1/9 - 1/10
= 1 - 1/10
= 9/10
4N = 1.2.3.(4-0) + 2.3.4.(5-1) + 3.4.5.(6-2) + ... + 2015.2016.2017.(2018-2014)
4N = 1.2.3.4 - 0.1.2.3 + 2.3.4.5 - 1.2.3.4 + 3.4.5.6 - 2.3.4.5 + ... + 2015.2016.2017.2018 - 2014.2015.2016.2017
4N = (1.2.3.4 + 2.3.4.5 + 3.4.5.6 + ... + 2015.2016.2017.2018) - (0.1.2.3 + 1.2.3.4 + 2.3.4.5 + ... + 2014.2015.2016.2017)
4N = 2015.2016.2017.2018 - 0.1.2.3
4N = 2015.2016.2017.2018
N = 2015.2016.504.2018 (kq hơi to nên bn tự tính nhé)
Tính:
S = \(\frac{1}{1.2.3}+\frac{1}{2.3.4}+\frac{1}{3.4.5}+\frac{1}{4.5.6}+...+\frac{1}{98.99.100}\)
\(2S=\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+...+\frac{1}{99.100}\)
\(2S=\frac{1}{2}-\frac{1}{9900}\)
\(2S=\frac{4949}{9900}\)
\(S=\frac{4949}{19800}\)
Ta xét : \(\frac{1}{1.2}-\frac{1}{2.3}=\frac{2}{1.2.3}\)
\(\frac{1}{2.3}-\frac{1}{3.4}=\frac{2}{2.3.4}\)
...
\(\frac{1}{98.99}-\frac{1}{99.100}=\frac{2}{98.99.100}\)
Ta có : 2S = \(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+...+\frac{1}{98.99}-\frac{1}{99.100}\)
=> 2S = \(\frac{1}{1.2}-\frac{1}{99.100}\)
=> 2S = \(\frac{4949}{9900}\)
=> S = \(\frac{4949}{19800}\)
Đặt
\(A=1\cdot2\cdot3+2\cdot3\cdot4+3\cdot4\cdot5+4\cdot5\cdot6+.......+n\left(n+1\right)\left(n+2\right)\)\(4A=1\cdot2\cdot3\cdot4+2\cdot3\cdot4\cdot4+3\cdot4\cdot5\cdot4+.......+n\left(n+1\right)\left(n+2\right)\cdot4\)\(4A=1\cdot2\cdot3\cdot\left(4-0\right)+2\cdot3\cdot4\cdot\left(5-1\right)+3\cdot4\cdot5\cdot\left(6-2\right)+........+n\left(n+1\right)\left(n+2\right)\left(n+3-n-1\right)\)\(4A=1\cdot2\cdot3\cdot4-0+2\cdot3\cdot4\cdot5-1\cdot2\cdot3\cdot4+....+n\left(n+1\right)\left(n+2\right)\left(n+3\right)-\left(n-1\right)n\left(n+1\right)\left(n+2\right)\)\(4A=n\left(n+1\right)\left(n+2\right)\left(n+3\right)\)
\(A=\dfrac{n\left(n+1\right)\left(n+2\right)\left(n+3\right)}{4}\)
Vậy \(A=\dfrac{n\left(n+1\right)\left(n+2\right)\left(n+3\right)}{4}\)
A = 1/2 - 1/3 - 1/4 + 1/3 - 1/4 - 1/5 + 1/4 - 1/5 - 1/6
A = 1/2 - 1/6
A = 1/3
k mk nha. ths bn nhìu nha
A = 1/2.3 - 1/ 3.4 + 1/3.4 - 1/4.5 + 1/4.5 -1/5.6
= 1/2.3 - 1/5.6
= 1/6 - 1/30
= 2/15
Vậy A = 1/15
\(=\dfrac{1}{2}\left(\dfrac{2}{2\cdot3\cdot4}+\dfrac{2}{3\cdot4\cdot5}+...+\dfrac{2}{18\cdot19\cdot20}\right)\)
\(=\dfrac{1}{2}\left(\dfrac{1}{2\cdot3}-\dfrac{1}{3\cdot4}+\dfrac{1}{3\cdot4}-\dfrac{1}{4\cdot5}+...+\dfrac{1}{18\cdot19}-\dfrac{1}{19\cdot20}\right)\)
\(=\dfrac{1}{2}\left(\dfrac{1}{6}-\dfrac{1}{380}\right)\)
\(=\dfrac{187}{2280}\)