(x+3/5)2+41/25=9% : 4,5%
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Khách
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22 tháng 7 2017
a)
\(3:\left(\dfrac{9}{4}\right)=\dfrac{3}{4}:\left(6.x\right)\\ \Rightarrow3.6.x=\dfrac{3}{4}.\dfrac{9}{4}\\ x=\dfrac{3}{4}.\dfrac{9}{4}.\dfrac{1}{3}.\dfrac{1}{6}\\ x=\dfrac{3}{4.4.2}\\ x=\dfrac{3}{32}\)
b)
\(4,5:0,3=\left(5.0,09\right):\left(0,01.x\right)\\ 0,01.x.4,5=5.0,09.0,3\\ x=5.\dfrac{9}{100}.\dfrac{3}{10}.100.\dfrac{10}{45}\\ x=3\)
d)
\(\left(\dfrac{1}{9}.x\right)=\dfrac{7}{4}:\dfrac{2}{25}\\ \left(\dfrac{1}{9}.x\right)=\dfrac{7}{4}.\dfrac{25}{2}\\ x:\dfrac{7}{4}=\dfrac{25}{2}:\dfrac{1}{9}\\ x=\dfrac{25}{2}.9.\dfrac{7}{4}\\ x=\dfrac{1575}{8}\\ x=196\dfrac{7}{8}\)
e)
\(\dfrac{-2}{x}=\dfrac{-x}{\dfrac{8}{25}}\\ -x.x=-2.\dfrac{8}{25}\\ -x^2=-\dfrac{16}{25}=-\dfrac{4^2}{5^2}\\ -x^2=-\left(\dfrac{4}{5}\right)^2\\ \Rightarrow x=\dfrac{4}{5}\)
Chúc bạn học tốt 
TN
2
8 tháng 8 2019
\(\left(x+\frac{3}{5}\right)^2+1\frac{16}{25}=9\%:4,5\%\)
\(\left(x+\frac{3}{5}\right)^2+1\frac{16}{25}=2\)
\(\left(x+\frac{3}{5}\right)^2=2-1\frac{16}{25}\)
\(\left(x+\frac{3}{5}\right)^2=\frac{9}{25}=\frac{3}{5}^2\)
\(x+\frac{3}{5}=\frac{3}{5}\)
\(x=\frac{3}{5}-\frac{3}{5}\)
\(x=0\)
8 tháng 8 2019
\(\left(x+\frac{3}{5}\right)^2+1\frac{16}{25}=9\%:4,5\%\)
\(\left(x+\frac{3}{5}\right)^2+1\frac{16}{25}=2\)
\(\left(x+\frac{3}{5}\right)^2=2-1\frac{16}{25}\)
\(\left(x-\frac{3}{5}\right)^2=\frac{3^2}{5}\)
\(x=\frac{3}{5}-\frac{3}{5}\)
\(x=0\)
23 tháng 5 2022
b,
= (4,5 x16 - 1,7) : (4,5 x 15 - 1,7)
= 1
c,
= ( 82 - 82 ) : 36 x ( 32 + 17 + 99 - 81 + 1 )
= 0 : 36 x ( 32 + 17 + 99 - 81 + 1 )
= 0 x ( 32 + 17 + 99 - 81 + 1 )
= 0
d,
= (30 : 7,5 + 0,5 x 3 - 1,5) x (4,5 - 4,5)
= (30 : 7,5 + 0,5 x 3 - 1,5) x 0
= 0
KL
1
KL
1 tháng 8 2017
(x + \(\dfrac{3}{5}\))2 + 1\(\dfrac{16}{25}=9\%:4,5\%\)
<=> x2 + (\(\dfrac{3}{5}\))2 + 1\(\dfrac{16}{25}=2\)
<=> x2 + \(\dfrac{9}{25}+\dfrac{41}{25}=2\)
<=> x2 + 2 = 2
<=> x2 = 0
<=> x = 0
@Khánh Linh
7 tháng 7 2018
a) 58 × 75 + 58 × 50 - 58 × 25
= 58 x ( 75 + 50 - 25 )
= 58 x 100 = 5800
b) 13,6 + 14,5 + 15,4 - 4,5 - 3,6 - 5,4
= ( 13,6 - 3.6 ) + ( 14,5 - 4,5 ) + ( 15,4 - 5,4 )
= 10 + 10 + 10 = 30
c) Bạn ghi sai đề. Sửa lại.
0,2 x 17 x 9 + 0,18 x 540 + 29 x 1,8
= 1,8 x 17 + 1,8 x 540 : 10 + 29 x 1,8
= 1,8 x ( 17 + 54 + 29 )
= 1,8 x 100 = 180
d) 5 + 8 + 11 + 14 +...... + 41
Số số hạng:
( 41 - 5 ) : 3 + 1 = 13 ( số )
S = ( 5 + 41 ) x 13 : 2 = 299
6 tháng 5 2019
1.
a) \(\frac{13}{8}:\frac{13}{4}=\frac{1}{2}=0,5=50\%\)
b) \(12,5:2,5=5=500\%\)
~ Hok tốt ~
6 tháng 5 2019
2.
\(\left(\frac{37}{9}+\frac{13}{4}\right).\frac{9}{4}+\frac{11}{4}\)
\(=\frac{265}{36}.\frac{9}{4}+\frac{11}{4}\)
\(=\frac{265}{16}+\frac{11}{4}\)
\(=\frac{309}{16}\)
\(1+\left(\frac{9}{10}-\frac{4}{5}\right):\frac{19}{6}\)
\(=1+\frac{1}{10}:\frac{19}{6}\)
\(=1+\frac{3}{95}\)
\(=\frac{98}{95}\)
\(\left(-7+\left|13\right|\right)-\left(13-\left|-7\right|-25\right)-\left(25+\left|-10\right|-9\right)\)
\(=\left(-7+13\right)-\left(13-7-25\right)-\left(25+10-9\right)\)
\(=-7+13-13+7+25-25-10+9\)
\(=\left(-7+7\right)+\left(13-13\right)+\left(25-25\right)-10+9\)
\(=0+0+0-10+9\)
\(=-10+9\)
\(=-1\)
~ Hok tốt ~
29 tháng 7 2019
Tìm x thuoc z:
1) \(26-\left|x+9\right|=-13\)
\(\Leftrightarrow\left|x+9\right|=26-\left(-13\right)\)
\(\Leftrightarrow\left|x+9\right|=39\)
\(\Leftrightarrow\left[{}\begin{matrix}x+9=39\\x+9=-39\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=39-9=30\\x=-39-9=-48\end{matrix}\right.\)
Vậy: \(x\in\left\{30;-48\right\}\)
2) \(\left|x+7\right|-13=25\)
\(\Leftrightarrow\left|x+7\right|=25+13=38\)
\(\Leftrightarrow x+7\in\left\{38;-38\right\}\)
\(\Leftrightarrow x\in\left\{31;-45\right\}\)
Vậy:.................
tim x biet
\(1)123-3.\left(x+4\right)=23\)
\(\Leftrightarrow3\left(x+4\right)=123-23\)
\(\Leftrightarrow3\left(x+4\right)=100\)
\(\Leftrightarrow x+4=\frac{100}{3}\)
\(\Leftrightarrow x=\frac{100}{3}-4=\frac{100-12}{3}=\frac{88}{3}\)
Vậy:................
2) Tương tự
giải nữa. bạn ơi
(\(x\) + \(\dfrac{3}{5}\))2 + \(\dfrac{41}{25}\) = 9%: 4,5%
(\(x\) + \(\dfrac{3}{5}\))2 + \(\dfrac{41}{25}\) = 2
(\(x\) + \(\dfrac{3}{5}\))2 = 2 - \(\dfrac{41}{25}\)
(\(x\) + \(\dfrac{3}{5}\))2 = \(\dfrac{9}{25}\)
\(\left[{}\begin{matrix}x+\dfrac{3}{5}=\dfrac{3}{5}\\x+\dfrac{3}{5}=-\dfrac{3}{5}\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=\dfrac{3}{5}-\dfrac{3}{5}\\x=-\dfrac{3}{5}-\dfrac{3}{5}\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=0\\x=-\dfrac{6}{5}\end{matrix}\right.\)
Vậy \(x\in\) {-1; \(\dfrac{1}{5}\)}