tính
3/7+(-18)/5+18/7+23/5
K
Khách
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20 tháng 2 2023
Ai rảnh mà làm hộ mày, ngu như con chó mới không biết làm
GC
9
MN
2
H9
HT.Phong (9A5)
CTVHS
15 tháng 3 2023
\(\dfrac{3}{5}-\dfrac{20}{9}:\dfrac{5}{18}+\dfrac{2}{4}\)
\(=\dfrac{3}{5}-\dfrac{20}{9}\times\dfrac{18}{5}+\dfrac{1}{2}\)
\(=\dfrac{3}{5}-\dfrac{360}{45}+\dfrac{1}{2}\)
\(=\dfrac{3}{5}-8+\dfrac{1}{2}\)
\(=-\dfrac{37}{5}+\dfrac{1}{2}\)
\(=-\dfrac{69}{10}\)
KV
15 tháng 3 2023
\(\dfrac{3}{5}-\dfrac{20}{9}:\dfrac{5}{18}+2,4\)
\(=\dfrac{3}{5}-8+\dfrac{7}{5}\)
\(=\left(\dfrac{3}{5}+\dfrac{7}{5}\right)-8\)
\(=2-8\)
\(=-6\)
LC
12 tháng 8 2015
7/23.5/29+7/29.18/23-7/29
=(7.5)/(23.29)+7/29.18/23-7/29
=7/29.5/23+7/29.18/23-7/29.1
=7/29.(5/23+18/23-1)
=7/29.(1-1)
=7/29.0
=0
12 tháng 8 2015
\(\frac{7}{23}\cdot\frac{5}{29}+\frac{7}{29}\cdot\frac{18}{23}-\frac{7}{29}\)
\(=\frac{7}{29}\cdot\frac{5}{23}+\frac{7}{29}\cdot\frac{18}{23}-\frac{7}{29}\)
\(=\frac{7}{29}\cdot\left(\frac{5}{23}+\frac{18}{23}-1\right)\)
\(=\frac{7}{29}\cdot0\)
\(=0\)
CL
10 tháng 8 2016
\(\frac{7}{25}+\frac{18}{25}+\frac{4}{23}+\frac{5}{7}+\frac{19}{23}\)
\(=\left(\frac{7}{25}+\frac{18}{25}\right)+\left(\frac{4}{23}+\frac{19}{23}\right)+\frac{5}{7}\)
\(=1+1+\frac{5}{7}\)
\(=2+\frac{5}{7}=\frac{19}{7}\)
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
19 tháng 1
Bài 1:
a; \(\dfrac{5}{18}\) + \(\dfrac{8}{19}\) - \(\dfrac{7}{21}\) + (- \(\dfrac{10}{36}\) + \(\dfrac{11}{19}\) + \(\dfrac{1}{3}\)) - \(\dfrac{5}{8}\)
= \(\dfrac{5}{18}\) + \(\dfrac{8}{19}\) - \(\dfrac{1}{3}\) -\(\dfrac{10}{36}\) + \(\dfrac{11}{19}\) + \(\dfrac{1}{3}\) - \(\dfrac{5}{8}\)
= (\(\dfrac{5}{18}\) - \(\dfrac{10}{36}\)) + (\(\dfrac{8}{19}\) + \(\dfrac{11}{19}\)) - (\(\dfrac{1}{3}\) - \(\dfrac{1}{3}\)) - \(\dfrac{5}{8}\)
= (\(\dfrac{5}{18}\) - \(\dfrac{5}{18}\)) + \(\dfrac{19}{19}\) - 0 - \(\dfrac{5}{8}\)
= 0 + 1 - \(\dfrac{5}{8}\)
= \(\dfrac{3}{8}\)
b; \(\dfrac{1}{13}\) + (\(\dfrac{-5}{18}\) - \(\dfrac{1}{13}\) + \(\dfrac{12}{17}\)) - (\(\dfrac{12}{17}\) - \(\dfrac{5}{18}\) + \(\dfrac{7}{5}\))
= \(\dfrac{1}{13}\) - \(\dfrac{5}{18}\) - \(\dfrac{1}{13}\) + \(\dfrac{12}{17}\) - \(\dfrac{12}{17}\) + \(\dfrac{5}{18}\) - \(\dfrac{7}{5}\)
= (\(\dfrac{1}{13}\) - \(\dfrac{1}{13}\)) + (\(\dfrac{12}{17}\) - \(\dfrac{12}{17}\)) + (-\(\dfrac{5}{18}\) + \(\dfrac{5}{18}\)) - \(\dfrac{7}{5}\)
= 0 + 0 + 0 - \(\dfrac{7}{5}\)
= - \(\dfrac{7}{5}\)
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
19 tháng 1
Bài 1 c;
\(\dfrac{15}{14}\) - (\(\dfrac{17}{23}\) - \(\dfrac{80}{87}\) + \(\dfrac{5}{4}\)) + (\(\dfrac{17}{23}\) - \(\dfrac{15}{14}\) + \(\dfrac{1}{4}\))
= \(\dfrac{15}{14}\) - \(\dfrac{17}{23}\) + \(\dfrac{80}{87}\) - \(\dfrac{5}{4}\) + \(\dfrac{17}{23}\) - \(\dfrac{15}{14}\) + \(\dfrac{1}{4}\)
= (\(\dfrac{15}{14}-\dfrac{15}{14}\)) + (\(-\dfrac{17}{23}+\dfrac{17}{23}\)) - (\(\dfrac{5}{4}\) - \(\dfrac{1}{4}\)) + \(\dfrac{80}{87}\)
= 0 + 0 - 1 + \(\dfrac{80}{87}\)
= - \(\dfrac{7}{87}\)
KT
20 tháng 1 2018
\(\frac{7}{25}+\frac{-18}{25}+\frac{4}{23}+\frac{5}{7}+\frac{19}{23}\)
\(=\left(\frac{7}{25}-\frac{11}{25}\right)+\left(\frac{4}{23}+\frac{19}{23}\right)+\frac{5}{7}\)
\(=\frac{-4}{25}+1+\frac{5}{7}\)
\(=\frac{-28}{175}+\frac{175}{175}+\frac{125}{175}\)
\(=\frac{272}{175}\)
PT
1
CM
26 tháng 8 2018
a) 5 x 5 + 18
= 25 + 18
= 43
b) 5 x 7 + 23
= 35 + 23
= 58
c) 7 x 7 x 2
= 49 x 2
= 98
d) 15 – 6 x 2
= 15 – 12
= 3
= 4
= 4