Question

[Trafalgar]

tìm x: (1/2+..+1/2014).x =1/2013+1/2012+........+2012/2+2013/1

Answer 1

[soyeon_Tiểu bàng giải]

\(\left(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{2014}\right).x=\frac{1}{2013}+\frac{2}{2012}+...+\frac{2012}{2}+\frac{2013}{1}\)

\(\left(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{2014}\right).x=\left(\frac{1}{2013}+1\right)+\left(\frac{2}{2012}+1\right)+...+\left(\frac{2012}{2}+1\right)+1\)

\(\left(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{2014}\right).x=\frac{2014}{2013}+\frac{2014}{2012}+...+\frac{2014}{2}+\frac{2014}{2014}\)

\(\left(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{2014}\right).x=2014.\left(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{2014}\right)\)

=> x = 2014

Đề bài bn chép sai 1 chút nên mk sửa lại và lm như trên

Answer 2

[Trafalgar]

cam on ban