phan tich da thuc thanh nhan tu : a) 3x^2 - 22xy + 4x + 8y + 7x^2 + 1 ; b) 12x^2 + 5x - 12y^2 + 12y - 10xy - 3 ; c)x^4 + 6x^3 + 11x^2 + 6x + 1
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a) x^2+4x+3=x^2+x+3x+3=x(x+1)+3(x+1)=(x+1)(x+3)
b) 4x^2+4x-3=4x^2+4x+1-4=(2x+1)^2-4=(2x+1-2)(2x+1+2)=(2x-1)(2x+3)
c) x^2-x-12=x^2-4x+3x-12=x(x-4)+3(x-4)=(x-4)(x+3)
d) 4x^4+4x^2y^2-8y^4=4(x^4+x^2y^2-2y^4)=4(x^4-x^2y^2+2x^2y^2-2y^4)=4(x^2-y^2)(x^2+2y^2)=4(x-y)(x+y)(x^2+2y^2)
a) \(x^2+4x+3\)
\(=x^2+x+3x+3\)
\(=\left(x^2+x\right)+\left(3x+3\right)\)
\(=x\left(x+1\right)+3\left(x+1\right)\)
\(=\left(x+1\right)\left(x+3\right)\)
c) \(x^2-x-12\)
\(=x^2-4x+3x-12\)
\(=\left(x^2-4x\right)+\left(3x-12\right)\)
\(=x\left(x-4\right)+3\left(x-4\right)\)
\(=\left(x-4\right)\left(x+3\right)\)
\(a.x^3+3x^2+4x+2\)
\(=x^3+x^2+2x^2+2x+2\)
\(=x^2\left(x+1\right)+2x\left(x+1\right)+2\left(x+1\right)\)
\(=\left(x+1\right)\left(x^2+2x+2\right)\)
\(b.6x^4-x^3-7x^2+x+1\)
\(=6x^4-6x^3+5x^3-5x^2-2x^2+2x-x+1\)
\(=6x^3\left(x-1\right)+5x^2\left(x-1\right)-2x\left(x-1\right)-\left(x-1\right)\)
\(=\left(x-1\right)\left(6x^3+5x^2-2x-1\right)\)
\(=\left(x-1\right)\left(6x^3+6x^2-x^2-x-x-1\right)\)
\(=\left(x-1\right)\left[6x^2\left(x+1\right)-x\left(x+1\right)-\left(x+1\right)\right]\)
\(=\left(x-1\right)\left(x+1\right)\left(6x^2-x-1\right)\)
\(=\left(x-1\right)\left(x+1\right)\left(6x^2-3x+2x-1\right)\)
\(=\left(x-1\right)\left(x+1\right)\left[3x\left(2x-1\right)+\left(2x-1\right)\right]\)
\(=\left(x-1\right)\left(x+1\right)\left(2x-1\right)\left(3x+1\right)\)
k giùm cái cho đỡ buồn!
b ( x^2 + 3x + 2)( x^2 + 7x + 12) - 24
= [ x^2 +x + 2x + 2) ( x^2 +3x + 4x + 12) - 24
= [x(x+1) + 2 (x + 1) [x(x+3) + 4(x+3) ] - 24
= ( x + 1)(x+2) (x+3)(x+4) - 24
= ( x + 1).(x+4) (x+2)(x+3) - 24
=(x^2 + 5x + 4)(x^2+5x+6) - 24
Đặt x^2 + 5x +4 =y ta có:
= y(y+2) - 24
= y^2 + 2y - 24
= y^2 + 2y + 1 - 25
= ( y + 1)^2 - (5)^2
= ( y + 1 - 5 )( y + 1 + 5)
= ( y- 4)(y +6)
Thay y trở lại là đc
đúng nha
3x2 - 7x - 10
= 3x2 + 3x - 10x - 10
= (3x2 + 3x) - (10x + 10)
= 3x(x + 1) - 10(x + 1)
= (3x - 10)(x + 1)
5x3 - 5x2y - 10x2 + 10xy
= 5x(x2 - xy - 2x + 2y)
= 5x[(x2 - xy) - (2x - 2y)]
= 5x[x(x - y) - 2(x - y)]
= 5x(x - 2)(x - y)
chúc bn hok tốt
nhớ ủng hộ tik cho mik nhé! ko lần sau mik ko giúp đâu
có j ko hiểu thì bn cứ bình luận ở dưới nhé
x^2 + 7x -15
= x^2 + 7x +12,25 -27,25
= (x+3,5)^2 - 27, 25
= ( x+3,5 - \(\sqrt{27,25}\))(x+3,5+\(\sqrt{27,25}\))