Giúp mình với ạ, cảm ơn nhiều ạ💕
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\(PTK_{Cu\left(OH\right)_2}=64+\left(16+1\right).2=98\left(đvC\right)\)
\(\%m_{Cu}=\dfrac{64}{98}.100=65,30\%\)
\(\%m_O=\dfrac{16.2}{98}.100=32,65\%\)
\(\%m_H=\dfrac{1.2}{98}.100=2,04\%\)
\(PTK_{H_2SO_4}=2.1+32+4.16=98\left(đvC\right)\)
\(\%m_H=\dfrac{2.1}{98}.100=2,04\%\)
\(\%m_S=\dfrac{32}{98}.100=32,65\%\)
\(\%m_O=\dfrac{4.16}{98}.100=65,30\%\)
các ý còn lại làm tương tự
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I love to imagine.It is quite fun.I don't really like the way my school is now,so I have an idea about my dream school.My dream school will be pretty llarge.It will be just like a town.Here,students will be like sisters or brothers.They will share and help each other.My dream school will also have teachers,but they won't teach us difficult things much.Instead,they will do exercises,have fun with students.My dream school won't use notebooks or books,because ipads and computers will be used much.We can learn more and play in freetime.The playground will have:slides,swings,...like other regular schools.Just a bit odd by having dancing floor,karaoke rooms,...It sound fun,isn't it.I like my dream school,alot.
TK :
Hello. Today, I will talk about my dream school. When my child was in elementary school I always wanted to go to a modern school. I watch movies and I see a lot of modern and convenient schools. The school has many classes. Specialized subjects will have their own rooms. The school will have vending machines. My school will have a gym room. We will have healthy sports such as basketball, badminton, … the campus will be planted with flowers and trees. What is your dream school? Please share to let me know!
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1. bag
2. bunch
3. slice
4. box
5. piece
6. carton
7. can
8. bowl
9. jar
10. bottle
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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
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Bài 1:
a. $-27+(-154)-(-27)+54$
$=(-27)-(-27)+(-154)+54=0-154+54=0-(154-54)=0-100=-100$
b.
$-35.127+(-35).(-27)+700$
$=(-35)(127-27)+700=-35.100+700=-3500+700=-2800$
c.
$-3^4-2[(-2023)^0+(-5)^2]=-81-2(1+25)=-81-2.26=-81-52$
$=-(81+52)=-133$
Bài 2:
a. $-34-2(7-x)=-10$
$2(7-x)=-34-(-10)=-24$
$7-x=-24:2=-12$
$x=7-(-12)=19$
b.
$x=ƯC(36,54,90)$
$\Rightarrow ƯCLN(36,54,90)\vdots x$
$\Rightarrow 18\vdots x$
$\Rightarrow x\in \left\{\pm 1; \pm 2; \pm 3; \pm 6; \pm 9; \pm 18\right\}$
Mà $x>5$ nên $x\in \left\{6; 9; 18\right\}$
a: Xét ΔABC vuông tại A và ΔHBA vuông tại H có
góc B chung
Do đó:ΔABC\(\sim\)ΔHBA
Suy ra: AB/HB=BC/BA
hay \(AB^2=HB\cdot BC\)
b: Xét ΔHAC vuông tại H và ΔHBA vuông tại H có
\(\widehat{HAC}=\widehat{HBA}\)
Do đó; ΔHAC\(\sim\)ΔHBA
SUy ra: HA/HB=HC/HA
hay \(HA^2=HB\cdot HC\)
a) Xét ∆ABC(<A=90 ° ) và ∆HBA(<H=90 ° ), ta có:
<B chung ⟹∆ABC~ ∆HBA(g.g)
⟹AB/HB=BC/AB⟹AB*AB=HB*BC hay AB2=BH*BC
b)Xét ∆HAC(<H=90 °) và ∆HBA(<H=90 ° ), ta được:
<B=<HAC( vì cùng phụ với <BAH do <B+<BAH =90°; <HAC+<BAH =90°)
⟹∆HAC~∆HBA(g.g)
⟹HA/HB=HC/HA⟹HA*HA=HB*HC hayHA2=BH*CH