Bài 2: Tìm X:
a) X x 12,5 = 6 x 2,5 b) X x 2,3 + X x 5,7 + 2 x X = 234,7
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\(x\times12,5=15\\ x=15:12,5=1,2\\ x-1,27=3\\ x=3+1,27=4,27\)
a)|3x|-12,5=|-2,5|
3x-12,5=2,5
3x=2,5+12,5
3x=15
x=15:3
x=5
vậy x=5
b)
x – 5,7 = 7,25
x = 7,25 + 5,7
x = 12,95
x x 1,4 = 5,6
x = 5,6 : 1,4
x = 4.
x + 14,28 = 12,5 x 3,6
x + 14,28 = 45
x = 45 – 14,28
x = 30,72
x : 2,75 = 37,6 – 18,62
x : 2,75 = 18,98
x = 18,98 x 2,75
x = 52,195.
\(a.32,5-3\cdot0,87=32,5-2,61=29,89\)
\(8,5\cdot\left(1\dfrac{1}{2}+\dfrac{4}{4}\right):5=8,5\cdot\left(\dfrac{3}{2}+\dfrac{4}{4}\right):5\\ =8,5\cdot\left(\dfrac{6}{4}+\dfrac{4}{4}\right):5\\ =8,5\cdot\dfrac{10}{4}:5\\ =\dfrac{85}{4}:5\\ =\dfrac{17}{4}\)
\(b.30,96-6,45+14,4:3=30,96-6,45+4,8\\ =29,31\)
\(\dfrac{2}{5}\cdot\left(\dfrac{4}{5}-\dfrac{1}{2}\right)=\dfrac{2}{5}\cdot\left(\dfrac{8}{10}-\dfrac{5}{10}\right)\\ =\dfrac{2}{5}\cdot\dfrac{3}{10}=\dfrac{3}{25}\)
bài 2
\(a.2,5\cdot12,5\cdot8\cdot0,4=\left(2,5\cdot0,4\right)\left(12,5\cdot8\right)\\ =1\cdot100=100\)
b,\(\dfrac{12}{15}\cdot\dfrac{5}{6}\cdot\dfrac{3}{20}\cdot\dfrac{32}{5}=\dfrac{12\cdot5\cdot3\cdot32}{15\cdot6\cdot20\cdot5}\\ =\dfrac{3\cdot4\cdot5\cdot3\cdot4\cdot8}{3\cdot5\cdot2\cdot3\cdot5\cdot4\cdot5}=\dfrac{16}{25}\)
Bài 1:
a) \(32.5-3\cdot0.87=32.5-2.61=29.89\)
\(8.5\cdot\left(1\dfrac{1}{2}+\dfrac{4}{4}\right):5=8.5\cdot\dfrac{5}{2}:5=\dfrac{17}{2}\cdot\dfrac{5}{2}:5=\dfrac{85}{4}\cdot\dfrac{1}{5}=\dfrac{17}{4}\)
mình có việc gấp
\(a,x\times12,5=15\\ x=15:12,5\\ x=1,2\\ b,x\times\left(2,3+5,7+2\right)=234,7\\ x\times10=234,7\\ x=23,47\)