Tính: \(\sqrt{\frac{6^5}{2^3.3^5}}\) . trình bày nha mn
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LT
0
16 tháng 7 2019
a = 48
b = \(\frac{1}{5}\)
c = 2
d \(\approx0,3904413457\)
TN
9 tháng 9 2017
CÁi này easy mà .-.
\(\frac{\sqrt[3]{7-x}-\sqrt[3]{x-5}}{\sqrt[3]{7-x}+\sqrt[3]{x-5}}=6-x\)
\(\Leftrightarrow\frac{\frac{\left(7-x\right)-\left(x-5\right)}{\left(\sqrt[3]{7-x}\right)^2+\left(\sqrt[3]{x-5}\right)^2+\sqrt[3]{7-x}\sqrt[3]{x-5}}}{\sqrt[3]{7-x}+\sqrt[3]{x-5}}+\left(x-6\right)=0\)
\(\Leftrightarrow\frac{\frac{-2\left(x-6\right)}{\left(\sqrt[3]{7-x}\right)^2+\left(\sqrt[3]{x-5}\right)^2+\sqrt[3]{7-x}\sqrt[3]{x-5}}}{\sqrt[3]{7-x}+\sqrt[3]{x-5}}+\left(x-6\right)=0\)
\(\Leftrightarrow\left(x-6\right)\left(\frac{\frac{-2}{\left(\sqrt[3]{7-x}\right)^2+\left(\sqrt[3]{x-5}\right)^2+\sqrt[3]{7-x}\sqrt[3]{x-5}}}{\sqrt[3]{7-x}+\sqrt[3]{x-5}}+1\right)=0\)
\(\Rightarrow x-6=0\Rightarrow x=6\)
20 tháng 6 2016
a)\(\left(\frac{5}{2}-\frac{4}{3}\right).\frac{6}{7}+\left(-\frac{3}{2}\right)^5:\left(-\frac{3}{2}\right)^3=\left(\frac{15}{6}-\frac{8}{6}\right).\frac{6}{7}+\left(-\frac{3}{2}\right)^2=\frac{7}{6}.\frac{6}{7}+\frac{9}{4}=\frac{9}{4}\)
H
11 tháng 2 2023
\(a,\dfrac{1}{2}-\dfrac{1}{3}-\left(-\dfrac{5}{4}\right)=\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{5}{4}=\dfrac{1\times6-1\times4+5\times3}{12}=\dfrac{6-4+15}{12}=\dfrac{17}{12}\\ b,\dfrac{5}{4}-\dfrac{1}{2}-\dfrac{7}{8}=\dfrac{5\times2-1\times4-7}{8}=\dfrac{10-4-7}{8}=-\dfrac{1}{8}\\ c,\dfrac{1}{5}-\dfrac{1}{2}+\dfrac{9}{10}=\dfrac{1\times2-1\times5+9}{10}=\dfrac{2-5+9}{10}=\dfrac{6}{10}=\dfrac{3}{5}\\ d,\dfrac{5}{4}-\dfrac{1}{3}+\dfrac{7}{6}=\dfrac{5\times3-1\times4+7\times2}{12}=\dfrac{15-4+14}{12}=\dfrac{25}{12}\)
DN
25 tháng 1 2022
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\(\sqrt{\frac{6^5}{2^3.3^5}}=\sqrt{\frac{6^5}{2^3.3^3.3^2}=}\sqrt{\frac{6^5}{6^3.3^2}}=\sqrt{\frac{6^2}{3^2}}=\sqrt{\left(\frac{6}{3}\right)^2}=\frac{6}{3}=2\)
=\(\sqrt{\frac{\left(2.3\right)^5}{2^3.3^5}}\)= \(\sqrt{\frac{2^5.3^5}{2^3.3^5}}\)= 2