Tìm x biết x : 4 + x = 3,75
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1). 7,5 x X + X x 3,5 = 39,93
X x (7,5 + 3,5) = 39,93
X x 11 = 39,93
X = 39,93 : 11
X = 3,63
2) x : 4 + x = 3,75
x : 4 + x : 1 = 3,75
x : (4 + 1) = 3,75
x : 5 = 3,75
x = 3,75 : 5 = 0,75
x ; 4 + x = 3,75
x * 0,25 + x = 3,75
x * (0,25 + 1) = 3,75
x * 1,25 = 3,75
x = 3,75/1,25
x = 3
\(\left|x+\dfrac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)
\(\Leftrightarrow\left|x+\dfrac{4}{15}\right|=-2,15+3,75\)
\(\Leftrightarrow\left|x+\dfrac{4}{15}\right|=\dfrac{8}{5}\)
\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{4}{15}=\dfrac{8}{5}\\x+\dfrac{4}{15}=-\dfrac{8}{5}\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{4}{3}\\x=-\dfrac{28}{15}\end{matrix}\right.\)
\(\Rightarrow\left|x+\dfrac{4}{15}\right|-3,75=-2,15\\ \Rightarrow\left|x+\dfrac{4}{15}\right|=1,6=\dfrac{8}{5}\\ \Rightarrow\left[{}\begin{matrix}x+\dfrac{4}{15}=\dfrac{8}{5}\\x+\dfrac{4}{15}=-\dfrac{8}{5}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{4}{3}\\x=-\dfrac{28}{15}\end{matrix}\right.\)
/x+4/15/-/-3,75/=-/-2,15/
/x+4/15/-15/4=-\(\frac{43}{20}\)
x+4/15=\(\frac{43}{20}+\frac{15}{4}\)
x+4/15=59/10
x=59/10-4/15
x=\(5\frac{19}{30}\)
\(x\div4+x=3,75\)
\(\Leftrightarrow\frac{x}{4}+x=3,75\)
\(\Leftrightarrow x\left(\frac{1}{4}+1\right)=3,75\)
\(\Leftrightarrow x\left(\frac{1}{4}+\frac{4}{4}\right)=3,75\)
\(\Leftrightarrow\frac{5}{4}x=3,75\)
\(\Leftrightarrow x=3,75\div\frac{5}{4}\)
\(\Leftrightarrow x=3,75\times\frac{4}{5}\)
\(\Leftrightarrow x=3\)
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=> 0,25X + X = 3,75
=> 1,25X = 3,75
=> X = 3,75 : 1,25
=> X = 3