M=1x2+3x4...+212x213 là .................
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Ta có : M = 1.2 + 2.3 + 3.4 + ..... + 212.213
=> 3M = 1.2.3 - 1.2.3 + 2.3.4 - 2.3.4 + ...... + 212.213.214
=> 3M = 212.213.214
=> M = 212.213.214/3
=> M = 3221128
3M = 1.2.3 + 2.3.(4-1) +..+ 99.100.(101-98)
3M = 1.2.3 + 2.3.4 - 1.2.3 + .... + 99.100.101 - 98.99.100
3M = 99.100.101 = 999900
M = 333300
\(\dfrac{1}{1\times2}+\dfrac{1}{2\times3}+\dfrac{1}{3\times4}+....+\dfrac{1}{24\times25}\)
\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{24}-\dfrac{1}{25}\)
\(=1-\dfrac{1}{25}\)
\(=\dfrac{24}{25}\)
\(\Rightarrow3M=1.2.3+2.3.3+...+201.202.3\)
\(=1.2.3+2.3.\left(4-1\right)+...+201.202.\left(203-200\right)\)
\(=1.2.3+2.3.4-1.2.3+...+201.202.203-200.201.202\)
\(=201.202.203\)
\(\Rightarrow M=\frac{201.202.203}{3}\)
\(M=\frac{1}{1\times2}+\frac{1}{2\times3}+\frac{1}{3\times4}+...+\frac{1}{99\times100}\)
\(M=\left(\frac{1}{1}-\frac{1}{2}\right)+\left(\frac{1}{2}-\frac{1}{3}\right)+\left(\frac{1}{3}-\frac{1}{4}\right)+...+\left(\frac{1}{99}-\frac{1}{100}\right)\)
\(M=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{99}-\frac{1}{100}\)
\(M=\frac{1}{1}-\frac{1}{100}\)
\(M=\frac{100}{100}-\frac{1}{100}\)
\(M=\frac{99}{100}\)
\(M=\frac{1}{1\times2}+\frac{1}{2\times3}+\frac{1}{3\times4}+...+\frac{1}{99\times100}\)
\(M=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+....+\frac{1}{100}-\frac{1}{100}\)
\(M=1-\frac{1}{100}\)
\(M=\frac{99}{100}\)
ta có công thức:1x2+2x3+3x4...+Nx(N+1)=(Nx(N+1)x(N+2)):3
suy ra M=(212x(212+1)x(212+2)):3=3221128