Tìm x biết: x + 1/5 = 5/x+1
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suy ra3.(5x-1) - 4.(5x-1) + 6(5x-1) =15
suy ra 5.(5x-1) = 15
suy ra 5x-1=3
suy ra x=4/5
\(\Leftrightarrow3\left(5x-1\right)-4\left(5x-1\right)+6\left(5x-1\right)=15\)
\(\Leftrightarrow\left(3-4+6\right)\left(5x-1\right)=15\)
\(\Leftrightarrow5\left(5x-1\right)=15\)
\(\Leftrightarrow5x-1=\frac{15}{5}=3\)
\(\Leftrightarrow5x=3+1=4\)
\(\Leftrightarrow x=\frac{4}{5}\)
Vậy \(x=\frac{4}{5}\)
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1a) \(\frac{x}{5}\) = \(\frac{5}{x}\)
Vì\(\frac{x}{5}\) = \(\frac{5}{x}\) nên x. x= 5. 5
x\(^2\) = 25
x\(^2\) = 5\(^2\)
-> x\(^2\) = 5\(^2\) hoặc x= -5\(^2\)
=> x= 5 hoặc x= -5
Chúc bn học tốt!
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\(\left|2\dfrac{1}{5}-x\right|\)\(+\left|x-\dfrac{1}{5}\right|\)\(+8\dfrac{1}{5}\)\(=1,2\)
\(\Rightarrow\left|2\dfrac{1}{5}-x\right|+\left|x-\dfrac{1}{5}\right|=\dfrac{6}{5}-\dfrac{41}{5}\)
\(\Rightarrow\left|2\dfrac{1}{5}-x\right|+\left|x-\dfrac{1}{5}\right|=\dfrac{-36}{5}\) (vô lý vì \(\left|2\dfrac{1}{5}-x\right|+\left|x-\dfrac{1}{5}\right|\ge0\))
Vậy: Không tìm được giá trị x thoả mãn.
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a. 2x+\(\dfrac{4}{5}\)=0 hoặc 3x-\(\dfrac{1}{2}\)=0
2x=- 4/5 hoặc 3x=1/2
x=-2/5 hoặc x=\(\dfrac{1}{6}\)
b. x-\(\dfrac{2}{5}\)=0 hoặc x+\(\dfrac{4}{7}\)=0
x=2/5 hoặc x=-\(\dfrac{4}{7}\)
d. x(1+5/8-12/16)=1
\(\dfrac{7}{8}\)x=1=> x=8/7