x + 20 = - ( - 23 )
15 - x + 17 = - ( - 6 ) + | -12 |
3 - | 2x + 1 | = ( - 5 )
giups e vs ajk e ddang caanf gaapa
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A
16 tháng 2 2021
1. Are there forty classrooms in Phong's school ?
2, Phuong is Nam's sister.
3. My father usually goes to work by car.
4. It is a small house.
5. The toystore is to the left of the bookstore.
15 tháng 2 2021
+) Ta có: \(15-x+17=-\left(-6\right)+\left|-12\right|\)
\(\Leftrightarrow-x+32=6+12\)
\(\Leftrightarrow-x=18-32\)
\(\Leftrightarrow x=14\)
Vậy......
+) Ta có: \(x+20=-\left(-23\right)\)
\(\Leftrightarrow x+20=23\)
\(\Leftrightarrow x=3\)
Vậy........
+) Ta có: \(-\left|-5\right|-\left(-x\right)+4=3-\left(-25\right)\)
\(\Leftrightarrow-5+x+4=3+25\)
\(\Leftrightarrow x=29\)
Vậy.....
Chúc e hok tốt và giữ lời hứa nhá ^_^
1 tháng 4 2020
a) -(-x)+14=12
x+14=12
x=12-14
x=-2
Vậy x=-2
b) x+20=-(-23)
x+20=23
x=23-20
x=3
Vậy x=3
c) 15-x+17=-(-6)+|-12|
15-x+17=6+12
15-x+17=18
15-x=18-17
15-x=1
x=15-1
x=14
Vậy x=14
d) |x|=5
=>x thuộc {-5;5}
Vậy x thuộc {-5;5}
e) |x-3|=1
=>x-3 thuộc {1;-1}
vậy ta sẽ xét 2 TH:
TH1:x-3=1
x=1+3
x=4
TH2:x-3=-1
x=-1+3
x=2
Vậy x thuộc {2;4}
f) |x+2|=4
=>x+2 thuộc {4;-4}
vậy ta sẽ xét 2 TH:
TH1:x+2=4
x=4-2
x=2
TH2:x+2=-4
x=-4-2
x=6
Vậy x thuộc {2;6}
MT
1 tháng 4 2020
a, -(-x)+14=12
=>x+14=12
x=12-14
x=-2
b,x+20=-(-23)
x+20=23
x=23-20
x=3
c,15-x+17=-(-6)+\(|-12|\)
15-x+17=6+12
32-x=18
x=32-18
x=14
d,\(|x|=5\)
\(TH1:x=5\)
\(TH2:x=-5\)
e,\(|x-3|=1\)
\(TH1:x-3=1\)
\(x=1+3\)
\(x=4\)
\(TH2:x-3=-1\)
\(x=-1+3\)
\(x=2\)
f,\(|x+2|=4\)
\(TH1:x+2=4\)
\(x=4-2\)
\(x=2\)
\(TH2:x+2=-4\)
\(x=-4-2\)
\(x=-6\)
#CHÚC_CẬU_HỌC_TỐT_NHÉ!
9 tháng 7 2023
`@` `\text {Ans}`
`\downarrow`
`c)`
`( 34 - 2x ) . ( 2x - 6 ) = 0`
`=>`\(\left[{}\begin{matrix}34-2x=0\\2x-6=0\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}2x=34\\2x=6\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=34\div2\\x=6\div2\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=17\\x=3\end{matrix}\right.\)
Vậy, `x \in {17; 3}`
`d)`
`( 2019 - x ) . ( 3x - 12 ) =0` `?`
`=>`\(\left[{}\begin{matrix}2019-x=0\\3x-12=0\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=2019-0\\3x=12\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=2019\\x=12\div3\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=2019\\x=4\end{matrix}\right.\)
Vậy, `x \in {2019; 4}`
`e) `
`57 . ( 9x - 27 ) = 0`
`=>`\(9x-27=0\div57\)
`=> 9x - 27 = 0`
`=> 9x = 27`
`=> x = 27 \div 9`
`=> x = 3`
Vậy, `x = 3`
`f)`
`25 + ( 15 - x ) = 30`
`=> 15 - x = 30 - 25`
`=> 15 - x = 5`
`=> x = 15 -5 `
`=> x = 10`
Vậy, `x = 10`
`g) `
`43 - ( 24 - x ) = 20`
`=> 24 - x = 43 - 20`
`=> 24 - x = 23`
`=> x = 24 - 23`
`=> x = 1`
Vậy, `x = 1`
`h) `
`2 . ( x - 5 ) - 17 = 25`
`=> 2 ( x - 5) = 25+17`
`=> 2 ( x - 5) = 42`
`=> x - 5 = 42 \div 2`
`=> x - 5 = 21`
`=> x = 21 + 5`
`=> x = 26`
Vậy, `x = 26`
`i)`
`3 . ( x + 7 ) - 15 = 27`
`=> 3(x + 7) = 27 + 15`
`=> 3(x + 7) = 42`
`=> x +7 = 42 \div 3`
`=> x + 7 = 14`
`=> x = 14 - 7`
`=> x = 7`
Vậy, `x = 7`
`j)`
`15 + 4 . ( x - 2 ) = 95`
`=> 4(x - 2) = 95 - 15`
`=> 4(x - 2) = 80`
`=> x - 2 = 80 \div 4`
`=> x - 2 = 20`
`=> x = 20 + 2`
`=> x = 22`
Vậy, `x = 22`
`k)`
`20 - ( x + 14 ) = 5`
`=> x + 14 = 20 - 5`
`=> x + 14 = 15`
`=> x = 15 - 14`
`=> x = 1`
Vậy, `x = 1`
`l) `
`14 + 3 . ( 5 - x ) = 27`
`=> 3(5 - x) = 27 - 14`
`=> 3(5 - x) = 13`
`=> 5 - x = 13 \div 3`
`=> 5 - x = 13/3`
`=> x = 5- 13/3`
`=> x = 2/3`
Vậy, `x = 2/3.`
`@` `\text {Kaizuu lv uuu}`
N
3
14 tháng 2 2020
2x+20=-22
=> 2x = -22 - 20
=> 2x = -42
=> x = -42 : 2
=> x = -21
Vậy x = -21
14 tháng 2 2020
2x+20=-22
2x=-22-20
2x=-42
x=-42:2
x=-21
-(-30)-(-x)=13
30+x=13
x=13-30
x=-17
-(-x)+14=12
x+14=12
x=12-14
x=-2
x+20=-(-23)
x+20=23
x=23-20
x=3
15-x+17=-(-6)+|-12|
15+17+x=6+12
32+x=18
x=18-32
x=-14
-|-5|-(-x)+4=3-(-25)
-5+x+4=3+25
-5+4+x=28
-1x=28
x=28:(-1)
x=-28
2 tháng 6 2017
a) \(\dfrac{x}{5}+\dfrac{1}{2}=\dfrac{6}{10}\\ \dfrac{x}{5}+\dfrac{1}{2}=\dfrac{3}{5}\\ \dfrac{x}{5}=\dfrac{3}{5}-\dfrac{1}{2}\\ \dfrac{x}{5}=\dfrac{6}{10}-\dfrac{5}{10}\\ \dfrac{x}{5}=\dfrac{1}{10}\\ \dfrac{2x}{10}=\dfrac{1}{10}\\ \Rightarrow2x=1\\ x=1:2\\ x=0,5=\dfrac{1}{2}\)
b) \(x+\dfrac{3}{15}=\dfrac{1}{3}\\ x=\dfrac{1}{3}-\dfrac{3}{15}\\ x=\dfrac{5}{15}-\dfrac{3}{15}\\ x=\dfrac{2}{15}\)
c) \(x-\dfrac{12}{4}=\dfrac{1}{2}\\ x-3=\dfrac{1}{2}\\ x=\dfrac{1}{2}+3\\ x=\dfrac{1}{2}+\dfrac{6}{2}\\ x=\dfrac{7}{2}\)
d) \(\dfrac{1}{2}x+\dfrac{1}{2}=\dfrac{5}{2}\\ \dfrac{1}{2}x=\dfrac{5}{2}-\dfrac{1}{2}\\ \dfrac{1}{2}x=2\\ x=2:\dfrac{1}{2}\\ x=4\)
NC
2 tháng 6 2017
a. \(\dfrac{2x+5}{10}=\dfrac{6}{10}\Leftrightarrow2x=1\Leftrightarrow x=\dfrac{1}{2}\)
b. \(\dfrac{15x+3}{15}=\dfrac{5}{15}\Leftrightarrow15x=2\Leftrightarrow x=\dfrac{2}{15}\)
c. \(\dfrac{4x-12}{4}=\dfrac{2}{4}\Leftrightarrow4x=14\Leftrightarrow x=\dfrac{7}{2}\)
d. \(\dfrac{1+x}{2x}=\dfrac{5x}{2x}\Leftrightarrow-4x=-1\Leftrightarrow x=\dfrac{1}{4}\)
e. \(\dfrac{-4\left(2x-5\right)}{6\left(2x-5\right)}-\dfrac{2}{6\left(2x-5\right)}=\dfrac{9\left(2x-5\right)}{6\left(2x-5\right)}\)
\(\Leftrightarrow-8x+20-2=18x-45\)
\(\Leftrightarrow-26x=-63\Leftrightarrow x=\dfrac{63}{26}\)
1) x = 23-20
=>x= 3
2)32-x=18
=>x=32-18
=>x=14
3)/2x+1/=8
=>2x+1=8
hoặc 2x+1=-8
=>x=7/2
hoặc x=-9/2
1/ Ta có: \(x+20=-\left(-23\right)\)
\(\Leftrightarrow x+20=23\)
\(\Leftrightarrow x=3\)
Vậy...
2/ Ta có: \(15-x+17=-\left(-6\right)+\left|-12\right|\)
\(\Leftrightarrow-x+32=18\)
\(\Leftrightarrow x=32-18=14\)
Vậy...
3/ Ta có: \(3-\left|2x+1\right|=\left(-5\right)\)
\(\Leftrightarrow\left|2x+1\right|=3-\left(-5\right)\)
\(\Leftrightarrow\left|2x+1\right|=8\)
\(\Leftrightarrow\orbr{\begin{cases}2x+1=8\\2x+1=-8\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{7}{2}\\x=-\frac{9}{2}\end{cases}}\)
Vậy...