Tìm x
(X×28) +45×67=8911
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(x:23+45):67=8911
x:23+45=8911x67
x:23+45=597037
x:23=597037-45
x:23=596992
x=596992x23
=13730816
( x : 23 + 45 ) . 67 = 8911
=> x : 23 + 45 = 133
=> x : 23 = 88
=> x = 2024
( x : 23 + 45 ) . 67 = 8911
=> x : 23 + 45 = 133
=> x : 23 = 88
=> x = 2024
# ~Hok tốt~
( \(\frac{x}{23}\) + 45 ) .67 = 8911
x : 23 + 45 = 8911:67
x : 23 + 45 = 133
x : 23 = 133 - 45
x : 23 = 88
x = 88 . 23
x = 2024
vậy x = 2024
\(\left(x:23+45\right).67=8911\)
\(\Rightarrow x:23+45=8911:67\)
\(\Rightarrow x:23+45=133\)
\(\Rightarrow x:23=133-45\)
\(\Rightarrow x:23=88\)
\(\Rightarrow x=23.88\)
\(\Rightarrow x=2024\)
Vậy \(x=2024\)
\((x-17)+52=158\)
\(\Rightarrow x-17=158-52\)
\(\Rightarrow x-17=106\)
\(\Rightarrow x=106-17\)
\(\Rightarrow x=89\)
( x- 17 ) + 52 = 158
x - 17 = 158 - 52
x - 17 = 106
x = 106 + 7
x = 113
Vậy x = 113
( x : 23 + 45 ) : 67 = 8911
x : 23 + 45 = 8911 x 67
x : 23 + 45 = 597037
x : 23 = 597037 - 45
x : 23 = 596992
x = 596992 x 23
x = 13730816
Vậy x = 13730876
(x:23+45)x67=8911
x:23+45=8911:67
x:23+45=133
x:23=133-45
x:23=88
x=88x23
x=2024
vậy x=2024
\(\left(\frac{x}{23}+45\right).67=8911\)
\(\frac{x}{23}+45=133\)
\(\frac{x}{23}=133-45\)
\(\frac{x}{23}=88\)
\(x=88.23\)
\(x=2024\)
Vậy x = 2024
a/ \(3636\div\left(12x-91\right)=36\)
\(12x-91=3636\div36\)
\(12x-91=101\)
\(12x=101+91\)
\(12x=192\)
\(x=192\div12\)
\(x=16\)
b/ \(\left(x\div23+45\right)\times67=8911\)
\(x\div23+45=8911\div67\)
\(x\div23+45=133\)
\(x\div23=133+45\)
\(x\div23=178\)
\(x=178\times23\)
\(x=4094\)
5 . ( x-3 ) -18 = 2
5x - 15 = 2 + 18
5x - 15 = 20
5x = 20 + 15
5x = 35
x= 7
Vậy x= 7
\(5x^2-15x-18=2\)
\(5x^2-15x-20=0\)
\(5\left(x^2-3x-4\right)\)\(=0\)
\(5\left(x^2-2xX\frac{3}{2}+\frac{9}{4}-\frac{9}{4}-4\right)=0\)
\(5\) {\(\left(x-\frac{3}{2}\right)^2-\frac{25}{4}\)} \(=0\)
\(\left(x-\frac{3}{2}\right)^2\) \(=\frac{25}{4}\)
\(x=\frac{\sqrt{25}}{2}+\frac{3}{2}\) hoặc \(x=\frac{-\sqrt{25}}{2}+\frac{3}{2}\)
\(\frac{x}{23}+45=597037\)
\(\frac{x}{23}=596992\)
\(x=13730816\)
\(\left(x.28\right)+45.67=8911\)
\(\left(x.28\right)+3015=8911\)
\(x.28=8911-3015\)
\(x.28=5896\)
\(x=5896:28\)
\(x=\frac{1474}{7}\)
Vậy \(x=\frac{1474}{7}\)