cho A = 2005/2007 ; B = 2007/2009
So sánh A và B
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\(2005^{2007}+2007^{2005}\)
\(=\left(2005^{2017}+1^{2017}\right)+\left(2007^{2005}-1^{2005}\right)\)
Vì \(2005^{2007}+1^{2007}⋮2005+1=2006;2007^{2005}-1^{2005}⋮2007-1=2006\)
\(\Rightarrow\)\(\left(2005^{2007}+1^{2007}\right)+\left(2007^{2005}-1^{2005}\right)⋮2016\)
\(\Rightarrow\)\(2005^{2007}+2007^{2005}⋮2006\)( đpcm )
2005/2006 + 2006/2007 + 2007/2008 + 2008/2005
= 4,000001491
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\(2005^{2007}+2007^{2005}\)
\(=(2005^{2007}+1)+(2007^{2005}-1)\)
\(=(2005^{2007}+1^{2007})+(2007^{2005}-1^{2005})\)
Vì\(2005^{2007}+1^{2007}⋮(2005+1)\)
\(2007^{2005}-1^{2005}⋮(2007-1)\)
Nên \(2005^{2007}+1^{2007}⋮2006\)
\(2007^{2005}-1^{2005}⋮2006\)
\(\Rightarrow(2005^{2007}+1^{2007})+(2007^{2005}-1^{2005})⋮2006\)
\(\Rightarrow2005^{2007}+2007^{2005}⋮2006\)
Ta có: \(A=\dfrac{2005}{2006}+\dfrac{2006}{2007}+\dfrac{2007}{2005}=\dfrac{2006-1}{2006}+\dfrac{2007-1}{2007}+\dfrac{2005}{2005}+\dfrac{1}{2005}+\dfrac{1}{2005}\)\(=1+1+1+\left(\dfrac{1}{2005}-\dfrac{1}{2006}+\dfrac{1}{2005}-\dfrac{1}{2007}\right)\)
\(=3+\left(\dfrac{1}{2005}-\dfrac{1}{2006}+\dfrac{1}{2005}-\dfrac{1}{2007}\right)\)
Ta thấy: \(\dfrac{1}{2005}>\dfrac{1}{2006};\dfrac{1}{2005}>\dfrac{1}{2007}\) \(\Rightarrow\dfrac{1}{2005}-\dfrac{1}{2006}+\dfrac{1}{2005}-\dfrac{1}{2007}>0\)
\(\Rightarrow A>3\)
\(A=\frac{2005}{2007}=1-\frac{2}{2007};B=\frac{2007}{2009}=1-\frac{2}{2009}.\)
\(\frac{1}{2007}>\frac{1}{2009}\Rightarrow1-\frac{2}{2007}< 1-\frac{2}{2009}\Rightarrow A< B\)