a) 5x-18=72
b) (x-36)-32=0
c) 156 -(x+6)=82
d) 2 mủ x =16
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\(a,x\left(x+9\right)=0\Rightarrow\left[{}\begin{matrix}x=0\\x=-9\end{matrix}\right.\\ b,\Rightarrow x\left(x^2+4x+4\right)=0\\ \Rightarrow x\left(x+2\right)^2=0\Rightarrow\left[{}\begin{matrix}x=0\\x=-2\end{matrix}\right.\\ c,\Rightarrow\left(x-5-4\right)\left(x-5+4\right)=0\\ \Rightarrow\left(x-9\right)\left(x-1\right)=0\Rightarrow\left[{}\begin{matrix}x=1\\x=9\end{matrix}\right.\\ d,\Rightarrow3\left(x+2\right)-x\left(x+2\right)=0\\ \Rightarrow\left(x+2\right)\left(3-x\right)=0\Rightarrow\left[{}\begin{matrix}x=3\\x=-2\end{matrix}\right.\\ e,\Rightarrow x^3+6x^2+12x+8-x^3-6x^2=4\\ \Rightarrow12x=-4\Rightarrow x=-\dfrac{1}{3}\\ g,\Rightarrow\left(x+2\right)\left(x+3\right)=0\Rightarrow\left[{}\begin{matrix}x=-2\\x=-3\end{matrix}\right.\)
a) x = 25 - 16
x = 9
b) 2x = 156-82
2x = 74
x = 74 : 2
x = 37
c) 150 : (18-x) = 150-125
150 : (18-x) = 25
18-x = 150 : 25
18-x = 6
x =18-6
x= 12
d) 6.6 :x = 8-4
36 : x = 4
x =36:4
x = 9
e)(99x-x) : 2+1= 50x
Ta có:
50x + (1+3+5+7+9+.....+99)=75.10.10
50x + (99+1).50:2 =7500
50x + 2500=7500
50x=7500-2500
50x=5000
x =5000:50
x = 100
Tim x € N biet :
a / x + 16 = 25
=> x = 25 - 16
=> x = 9
b / 156 - 2x = 82
=> 2x = 156 - 82
=> 2x = 74
=> x = 37
c / 150 -150 : ( 18 - x ) = 125
=> 150 : ( 18 - x ) = 125 -150
=> 150 : ( 18 - x ) = - 25
=> 18 - x = -6
=> x = 18 - ( -6 )
=> x = 24
d / 62 : x = 23 - 4
=> 36 : x = 8 - 4
=> 36 : x = 4
=> x = 36 : 4
=> x = 9
e / x + 3x + 5x + ................. +99x = 75 × 102
=> x + 3x + 5x +....+ 99x = 7500
=> x. ( 1 + 3 + 5 +....+ 99 ) = 7500
Số các số hạng là : ( 99 - 1 ) : 2 + 1 = 50
=> Số cặp là : 50 : 2 = 25
Ta có:
x. ( 1 + 3 + 5 +....+ 99 ) = 7500
=> x. [ ( 1 + 99 ) + ( 2 + 98 ) +.... ] = 7500
=> x. 100 .25 =7500
=> x. 2500 = 7500
=> x = 7500 : 2500
=> x = 3
\(a,\Leftrightarrow2x^2+10x-2x^2=12\Leftrightarrow x=\dfrac{12}{10}=\dfrac{6}{5}\\ b,\Leftrightarrow\left(5-2x-4\right)\left(5-2x+4\right)=0\\ \Leftrightarrow\left(1-2x\right)\left(9-2x\right)=0\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=\dfrac{9}{2}\end{matrix}\right.\\ c,\Leftrightarrow3x^2-3x^2+6x=36\Leftrightarrow x=6\\ d,\Leftrightarrow2\left(x+5\right)-x\left(x+5\right)=0\\ \Leftrightarrow\left(2-x\right)\left(x+5\right)=0\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-5\end{matrix}\right.\\ e,\Leftrightarrow4x^2-4x+1-4x^2+196=0\\ \Leftrightarrow-4x=-197\Leftrightarrow x=\dfrac{197}{4}\)
\(f,\Leftrightarrow x^2+8x+16-x^2+1=16\Leftrightarrow8x=-1\Leftrightarrow x=-\dfrac{1}{8}\\ g,Sửa:\left(3x+1\right)^2-\left(x+1\right)^2=0\\ \Leftrightarrow\left(3x+1-x-1\right)\left(3x+1+x+1\right)=0\\ \Leftrightarrow2x\left(4x+2\right)=0\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-\dfrac{1}{2}\end{matrix}\right.\\ h,\Leftrightarrow x^2+8x-x-8=0\\ \Leftrightarrow\left(x+8\right)\left(x-1\right)=0\Leftrightarrow\left[{}\begin{matrix}x=1\\x=-8\end{matrix}\right.\\ i,\Leftrightarrow2x^2-13x+15=0\\ \Leftrightarrow2x^2+2x-15x-15=0\\ \Leftrightarrow\left(x+1\right)\left(2x-15\right)=0\Leftrightarrow\left[{}\begin{matrix}x=-1\\x=\dfrac{15}{2}\end{matrix}\right.\)
Bài 1:
a: \(\Leftrightarrow x^2-5x+6< =0\)
=>(x-2)(x-3)<=0
=>2<=x<=3
b: \(\Leftrightarrow\left(x-6\right)^2< =0\)
=>x=6
c: \(\Leftrightarrow x^2-2x+1>=0\)
\(\Leftrightarrow\left(x-1\right)^2>=0\)
hay \(x\in R\)
Bài 1:
a) \(\Rightarrow3x^2+3x-2x^2-4x+x+1=0\)
\(\Rightarrow x^2=-1\left(VLý\right)\Rightarrow S=\varnothing\)
b) \(\Rightarrow\left(x-2020\right)\left(2x-1\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=2020\\x=\dfrac{1}{2}\end{matrix}\right.\)
c) \(\Rightarrow\left(x-10\right)\left(x+2\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=10\\x=-2\end{matrix}\right.\)
d) \(\Rightarrow\left(x+4\right)^2=0\Rightarrow x=-4\)
e) \(\Rightarrow\left(x+6\right)\left(x-7\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=-6\\x=7\end{matrix}\right.\)
f) \(\Rightarrow\left(5x-4\right)\left(5x+4\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{4}{5}\\x=-\dfrac{4}{5}\end{matrix}\right.\)
Bài 2:
a) \(\Rightarrow3x\left(x^2-4\right)=0\Rightarrow3x\left(x-2\right)\left(x+2\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\x=2\\x=-2\end{matrix}\right.\)
b) \(\Rightarrow x\left(x-2\right)+5\left(x-2\right)=0\Rightarrow\left(x-2\right)\left(x+5\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=2\\x=-5\end{matrix}\right.\)
a) 576 + 678 + 780 - 475 - 577 - 679
= 780 - 475 + ( 576 - 577) - ( 678 - 679)
= 305 - 1 - 1
= 303
b) (126 + 32)\(\times\)(18 - 16 - 2)
= (126 + 32) \(\times\)0
= 0
c) 36 * 17 * 12 * 34 + 6 * 30
= 36 * 17 * 6 * 2 * 34 + 6 * 30
= 6 * (36 + 17 + 2 + 34 + 30)
= 6 * 119
= 714
a) \(5x-18=72\)
\(5x=72+18\)
\(5x=100\)
\(x=100\div5\)
\(x=20\)
b) \(\left(x-36\right)-32=0\)
\(x-36=32\)
\(x=32+36\)
\(x=68\)
c) \(156-\left(x+6\right)=82\)
\(x+6=156-82\)
\(x-6=74\)
\(x=74+6\)
\(x=80\)
d) \(2^x=16\)
\(2^x=2^4\)
=> x = 4