khó quá,giúp
K
Khách
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giúp với,khó quá
5 tháng 9 2021
\(A=\sqrt{2-\sqrt{3}}+\sqrt{2+\sqrt{3}}\\ \Rightarrow A^2=2-\sqrt{3}+2\sqrt{2-\sqrt{3}}\sqrt{2+\sqrt{3}}+2+\sqrt{3}\\ \Rightarrow A^2=4+2\sqrt{\left(2-\sqrt{3}\right)\left(2+\sqrt{3}\right)}\\ \Rightarrow A^2=4+2\sqrt{2^2-\sqrt{3^2}}\\ \Rightarrow A^2=4+2\sqrt{1}\\ \Rightarrow A^2=6\\ \Rightarrow A=\pm\sqrt{6}\)
Mà \(A>0\Rightarrow A=\sqrt{6}\)
6 tháng 11 2021
a: Xét tứ giác AKCI có
AK//CI
AK=CI
Do đó: AKCI là hình bình hành
20 tháng 2 2022
hơi mờ và còn nhiều ,mik nghĩ bạn nên cắt ra đi
DT
Đỗ Thanh Hải
CTVVIP
21 tháng 8 2021
1 not going on holiday with you
2 such easy questions that all the students got them right
3 we had had time, we would have visited the museum
4 to Daisy for breaking her vase
5 studying ENglish 5 years ago
6 are thought to be the most popular dance in Brazil
7 sooner had she received the exam result than she phoned her mom
8 It was the absence of leadership that caused most of the problems on the committee
9 you have any complants about the product, return it to the shop
10 The more fondness for the game increased , the more proficiency he has
11 been a dramatical rise in house prices this year
12 believed to have escaped in a stolen car
13 gone out with him for 2 years
14 he was going to meet his sister in front of the station
18 tháng 1 2022
đk x khác 1 ; y khác -2
\(\left\{{}\begin{matrix}\dfrac{8}{x-1}+\dfrac{15}{y+2}=1\\\dfrac{1}{x-1}+\dfrac{1}{y+2}=1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}\dfrac{8}{x-1}+\dfrac{15}{y+2}=1\\\dfrac{8}{x-1}+\dfrac{8}{y+2}=8\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}\dfrac{7}{y+2}=-7\\\dfrac{1}{x-1}+\dfrac{1}{y+2}=1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}y+2=-1\\\dfrac{1}{x-1}+\dfrac{1}{y+2}=1\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}y=-3\\\dfrac{1}{x-1}=2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}y=-3\\1=2x-2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}y=-3\\x=\dfrac{3}{2}\end{matrix}\right.\)