5,3*13,5-5,3*2,5-5,3
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\(A=\left(3,1-2,5\right)-\left(-2,5+3,1\right)\)
\(=\left(3,1-2,5\right)-\left(3,1-2,5\right)\)
\(=3,1-2,5-3,1+2,5\)
\(=\left(3,1-3,1\right)+\left(2,5-2,5\right)\)
\(=0+0=0\)
\(B=\left(5,3-2,8\right)-\left(4+5,3\right)\)
\(=5,3-2,8-4-5,3\)
\(=\left(5,3-5,3\right)-\left(2,8+4\right)\)
\(=0-\left(2,8+4\right)\)
\(=-2,8-4=-6,8\)
a) \(A=\left(3,1-2,5\right)-\left(-2,5+3,1\right)\)
\(A=0,6-0,6\)
\(A=0\)
b) \(B=\left(5,3-2,8\right)-\left(4+5,3\right)\)
\(B=2,5-7,3\)
\(B=-6,8\)
c) \(C=-\left(25-3+2,81\right)+3,251-\left(1-2,8\right)\)
\(C=-24,81+3,251+1,8\)
\(C=-19,759\)
`@` `\text {Ans}`
`\downarrow`
`a,`
`A =(3,1 - 2,5) - (-2,5 + 3,1)`
`= 3,1 - 2,5 + 2,5 - 3,1`
`= (3,1 - 3,1) + (-2,5+2,5)`
`= 0`
Vậy, `A = 0`
`b,`
`B = (5,3 - 2,8) - (4+5,3)`
`= 5,3 - 2,8 - 4 - 5,3`
`= (5,3 - 5,3) + (-2,8-4)`
`= -6,8`
Vậy, `B = -6,8`
`c,`
`C = -(25 - 3 + 2,81) + 3,251 - (1 - 2,8)` `?`
`= -25 + 3 - 2,81 + 3,251 - 1 + 2,8`
`= (-25 + 3 - 1) + (-2,81 + 2,8) + 3,251`
`= -23 - 0,01 + 3,251`
`= -19,759`
a,(-35,8)+(-17,2) + 16,4 + 4,6
= [ (-35,8)+(-17,2)]+(16,4 + 4,6 )
= (-53)+21
= -32
b, (5,3 - 2,8) -( 4+ 5,3 )
=5,3 -2,8 -4-5,3
=5,3 +(-2,8)+ (-4)+(-5,3 )
= [5,3 +(-5,3 )]+[(-2,8)+ (-4)]
= 0+(-6,8)
=-6,8
c, (34:72 + 32,28): 5 -(57,25 - 36,05):2
ko biết
d, 2,5.(-4,68)+2,5.(-5,32)
=2,5 .[(-4,68)+(-5,32)]
= 2,5 . (-10)
=-25
e, 5,36.12,34+(-5,36).2,34
= 5,36.12,34+5,36.(-2,34)
= 5,36.[12,34+(-2,34)]
=5,36 . 10
= 53,6
\(a,\left(-38,5\right)+\left(-17,2\right)+16,4+4,6\\ =\left[\left(-35,8\right)+\left(-17,2\right)\right]+\left(16,4+4,6\right)\\ =-53+21\\ =-32\)
\(b,\left(5,3-2,8\right)-\left(4+5,3\right)=2,5-9,3=-6,8\)
\(c,\left(34,72+32,28\right):5-\left(57,25-36,05\right):2\\ =77:5-21,2:2\\ =15,4-10,5\\ =4,9\) (là 34,72 đúng không ah?)
\(d,2,5.\left(-4,68\right)+2,5.\left(-5,32\right)\\ =2,5.\left[\left(-4,68\right)+\left(-5,32\right)\right]\\ =2,5.10\\ =25\)
\(5,36.12,34+\left(-5,36\right).2,34\\ =66,1424+-12,5424\\ =53,6\) (thay vì bê cái khác vào tk thì tôi tự tính tay:'))
A = (3,1 – 2,5) – (-2,5 + 3,1) = 3,1 – 2,5 + 2,5 – 3,1 = 0
B = (5,3 – 2,8) – (4 + 5,3) = 5,3 – 2,8 – 4 – 5,3
A=(3,1-2,5)-(-2,5+3,1)=3,1-2,5+2,5-3,1=0
B=(5,3-2,8)-(4+5,3)=5,3-2,8-4-5,3=-6,8
a,
5,3 - (-5,1)+(-5,3) + 4,9;
\(\begin{array}{l}= 5,3 + 5,1 +(-5,3)+4,9 = \left[ {5,3 + \left( { - 5,3} \right)} \right] + \left( {5,1 + 4,9} \right)\\ = 0 + 10 = 10\end{array}\)
b,
(2,7 - 51,4) - (48,6 - 7,3)
\(\begin{array}{l} = 2,7 - 51,4 - 48,6 + 7,3\\ = \left( {2,7 + 7,3} \right) - \left( {51,4 + 48,6} \right)\\ = 10 - 100 = - 90\end{array}\)
c,
2,5. (-0,124) + 10, 124 . 2,5
= 2,5.(-0,124+10,124)
= 2,5.10
= 25
a) (-35,8) + (-17,2) + 16,4 + 4,6
= [ (-35,8) + (-17,2) ] + (16,4 + 4,6)
= -53 + 21
= -32
b) (5,3 - 2,8) - (4 + 5,3)
= 2,5 - 9,3
= -6,8
c) (34,72 + 32,28):5 - (57,25 - 36,05):2
= 67:5 - 21,2:2
= 13,4 - 10,6
= 2,8
d) 2,5.(-4,68) + 2,5.(-5,32)
= 2,5.[ (-4,68) + (-5,32) ]
= 2,5. (-10)
= -25
e) 5,36. 12,34 + (-5,36). 2,34
= 5,36. 12,34 - 5,36. 2,34
= 5,36. (12,34 - 2,34)
= 5,36. 10
= 53,6
a,-35,8+(-17,2)+16,4+4,6=(-35,8-17,2)+(16,4+4,6=-53+21=-32
b,(5,3-2,8)-(4+5,3)=5,3-2,8-4-5,3=(5,3-5,3)+(-2,8-4)=0-6,8=-6,8.
c,(34,72+32,28):5-(57,25-36,05):2=67:5-21,2:2=13.4-10.6=2,8
d,2,5(-4,68)+2,5(-5,32)=2,5(-4,68-5,32)=2,5x(-10)=-25
e,5,36x12,34+(-5,36)x2,34=5,36(12,34-2,34)=5,36x10=53,6
a: =5,3+5,1-5,3+4,9=10
b: =2,7-51,4-48,6+7,3
=10-100=-90
c: =2,5(-0,124+10,124)=2,5x10=25
d: =6,3-6,3+4.9=4,9
e: =15,3-21,5-4,5=-10,7
\(5,3\div25\%+5,3\times7-5,3 \)
\(=5,3\div\dfrac{25}{100}+5,3\times7-5,3\)
\(=5,3\div\dfrac{1}{4}+5,3\times7-5,3\)
\(=5,3\times4+5,3\times7-5,3\times1\)
\(=5,3\times\left(7+4+1\right)\)
\(=5,3\times10\)
\(=53\)
5,3: 25% + 5,3 \(\times\) 7 - 5,3
= 5,3 \(\times\) 4 + 5,3 \(\times\) 7 - 5,3 \(\times\) 1
= 5,3 \(\times\) ( 4 + 7 - 1)
= 5,3 \(\times\) ( 11 - 1)
= 5,3 \(\times\) 10
= 53
= 5,3 x (13,5 - 2,5 - 1)
= 5,3 x 10
= 53