2 mũ x+1 =32
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a) \(2^{x+1}-2^x=32\)
\(\Rightarrow2^x\left(2-1\right)=2^5\)
\(\Rightarrow2^x.1=2^5\)
\(\Rightarrow x=5\)
b) \(2^{x+1}=2\)
\(\Rightarrow2^{x+1}=2^1\)
\(\Rightarrow x+1=1\)
\(\Rightarrow x=0\)
\(2^{x+1}-2^x=32\)
\(2^x.2-2^x=32\)
\(2^x\left(2-1\right)=32\)
\(2^x=32\)
\(x=5\)
1. 2x=16\(\Rightarrow\)X=4
2. 22x-1=27
\(\Rightarrow\)27=22.4-1
Vậy x =4
\(2^{x+1}-2^x=32\\ \Rightarrow2^x\cdot2^1-2^x=32\\ \Rightarrow2^x\left(2-1\right)=32\\ \Rightarrow2^x=32:1\\ \Rightarrow2^x=32\\ \Rightarrow2^x=2^5\\ \Rightarrow x=5\)
\(2^x+2^{x+2}=32.\left(2^2+1\right)\)
\(\Rightarrow2^x+2^{x+2}=32.5\)
\(\Rightarrow2^x+2^{x+2}=160\)
\(\Rightarrow2^x\left(1+4\right)=160\)
\(\Rightarrow2^x.5=160\)
\(\Rightarrow2^x=160:5=32\)
\(\Rightarrow2^x=2^5\)
\(\Rightarrow x=5\)
Vậy x = 5
\(\left(X-1\right)^2=16\)
\(\left(X-1\right)^2=4^2\)
X -1 =4
X=5
\(2^{X-1}=32\)
\(2^{X-1}=2^{6-1}\)
X=6
H NHA
a.\(x-1^2=16\) b.\(2^{x-1}=32\)
\(\Leftrightarrow x-1=16\) \(\Leftrightarrow2^{x-1}=2^5\)
\(\Leftrightarrow x=16-1\) \(\Leftrightarrow x-1=5\)
\(\Leftrightarrow x=15\) \(\Leftrightarrow x=5+1\)
Vậy x = 15 \(\Leftrightarrow x=6\)
Vậy x= 6
Cho mk xin 1 tk nhé!
\(2^{x+1}-2^x=32\)
\(\Leftrightarrow2^x.2-2^x=2^5\)
\(\Leftrightarrow2^x.\left(2-1\right)=2^5\)
\(\Leftrightarrow2^x.1=2^5\)
\(\Leftrightarrow x=5\)
Vậy : \(x=5\)
\(2^{x+1}-2^x=32\)
\(\Leftrightarrow2^x.2-2^x=2^5\)
\(\Leftrightarrow2^x.\left(2-1\right)=2^5\)
\(\Leftrightarrow2^x=2^5\)
\(\Rightarrow x=5\)
Các bạn giúp mk nha gấp lắm luôn đó nha🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗
\(2^{x+1}-2^x=32\)
\(\Rightarrow2^x.2-2^x=32\)
\(\Rightarrow2^x\left(2-1\right)=32\)
\(\Rightarrow2^x=32\)
\(\Rightarrow2^x=2^5\)
\(\Rightarrow x=5\)
Vậy x=5
Hok tốt !!!!!!!!!!!!!!!!!
2x+1 - 2x = 32
⇔ 2x( 2 - 1 ) = 32
⇔ 2x . 1 = 32
⇔ 2x = 32
⇔ 2x = 25
⇔ x = 5
Vậy x = 5
a;2 mu x =2 mu 6 .Vậy x=6
- b,7 mu x=49
- 7mu x -1x=7 mu 2
- 7mu x=2-1
- x=1
- c,(x+1)mu 5=2 mu 5
- x+1=2
- x=2+1
- x=3
\(2^{x+1}=32=2^5\)
\(\Rightarrow x+1=5\)
\(\Rightarrow x=5-1=4\)
2x+1=32
=>2x+1=25
=>x+1=5
=>x=4