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1. 2x=16\(\Rightarrow\)X=4
2. 22x-1=27
\(\Rightarrow\)27=22.4-1
Vậy x =4
\(2^x+2^{x+2}=32.\left(2^2+1\right)\)
\(\Rightarrow2^x+2^{x+2}=32.5\)
\(\Rightarrow2^x+2^{x+2}=160\)
\(\Rightarrow2^x\left(1+4\right)=160\)
\(\Rightarrow2^x.5=160\)
\(\Rightarrow2^x=160:5=32\)
\(\Rightarrow2^x=2^5\)
\(\Rightarrow x=5\)
Vậy x = 5
Các bạn giúp mk nha gấp lắm luôn đó nha🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗🤗
\(2^{x+1}-2^x=32\\ \Rightarrow2^x\cdot2^1-2^x=32\\ \Rightarrow2^x\left(2-1\right)=32\\ \Rightarrow2^x=32:1\\ \Rightarrow2^x=32\\ \Rightarrow2^x=2^5\\ \Rightarrow x=5\)
Bài 1:
2\(x\) = 4
2\(^x\) = 22
\(x=2\)
Vậy \(x=2\)
Bài 2:
2\(^x\) = 8
2\(^x\) = 23
\(x=3\)
Vậy \(x=3\)
a) \(\frac{3}{7}-\frac{1}{7}x=\frac{2}{3}\)
=> \(\frac{1}{7}x=\frac{3}{7}-\frac{2}{3}=-\frac{5}{21}\)
=> \(x=-\frac{5}{21}:\frac{1}{7}=-\frac{5}{21}\cdot7=-\frac{5}{3}\)
b) \(3x^2-2=72\)=> 3x2 = 74 => x2 = 74/3 => x không thỏa mãn
c) \(\left(19x+2\cdot5^2\right):14=\left(13-8\right)^2-4^2\)
=> \(\left(19x+2\cdot25\right):14=5^2-4^2=9\)
=> \(\left(19x+50\right):14=9\)
=> \(19x+50=126\)
=> \(19x=76\)
=> x = 4
d) \(x:\frac{1}{2}+x:\frac{1}{4}+x:\frac{1}{8}+x:\frac{1}{16}+x:\frac{1}{32}=343\)
=> \(x\cdot2+x\cdot4+x\cdot8+x\cdot16+x\cdot32=343\)
=> \(x\left(2+4+8+16+32\right)=343\)
=> x . 62 = 343
=> x = 343/62
\(\left(X-1\right)^2=16\)
\(\left(X-1\right)^2=4^2\)
X -1 =4
X=5
\(2^{X-1}=32\)
\(2^{X-1}=2^{6-1}\)
X=6
H NHA
a.\(x-1^2=16\) b.\(2^{x-1}=32\)
\(\Leftrightarrow x-1=16\) \(\Leftrightarrow2^{x-1}=2^5\)
\(\Leftrightarrow x=16-1\) \(\Leftrightarrow x-1=5\)
\(\Leftrightarrow x=15\) \(\Leftrightarrow x=5+1\)
Vậy x = 15 \(\Leftrightarrow x=6\)
Vậy x= 6
Cho mk xin 1 tk nhé!
\(5^{x+1}=125\)
\(5^{x+1}=5^3\)
\(x+1=3\)
\(x=2\)
b, \(5^{2x-3}-2.5^2=5^2.3\)
\(5^{2x-3}=5^2.\left(3+2\right)\)
\(5^{2x-3}=5^3\)
\(2x-3=3\)
\(x=3\)
c, \(2^x=32\)
\(2^x=2^5\)
\(x=5\)
Chúc em học tốt.
Nguyễn Khánh Phương
Bài 1 :
a) 149 - ( 35 : x + 3 ) x 17 = 13
( 35 : x + 3 ) x 17 = 149 - 13
( 35 : x + 3 ) x 17 = 136
( 35 : x + 3 ) = 136 : 17
( 35 : x + 3 ) = 8
35 - x = 8 - 3
35 - x = 5
x = 35 - 5
x = 30
b, 121 : 11 − ( 4x + 5 ) : 3 = 4
11 − 4x + 5 : 3 = 4
4x + 5 : 3 = 11 − 4
4x + 5 : 3 = 7
4x + 5 = 7 x 3
4x + 5 = 21
4x = 21 − 5
4x = 16
x = 16 : 4
x = 4
a) \(2^{x+1}-2^x=32\)
\(\Rightarrow2^x\left(2-1\right)=2^5\)
\(\Rightarrow2^x.1=2^5\)
\(\Rightarrow x=5\)
b) \(2^{x+1}=2\)
\(\Rightarrow2^{x+1}=2^1\)
\(\Rightarrow x+1=1\)
\(\Rightarrow x=0\)
\(2^{x+1}-2^x=32\)
\(2^x.2-2^x=32\)
\(2^x\left(2-1\right)=32\)
\(2^x=32\)
\(x=5\)