10 - {[( x : 3 + 17) : 10 + 3 . \(2^4\)] : 10 } = 5
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(10-\left\{\left[3^x+1:\left(3+17\right):10+3\cdot2^4\right]:10\right\}=5\)
\(\Rightarrow\left(3^x+1:20:10+3\cdot16\right):10=10-5\)
\(\Rightarrow\left(3^x+\dfrac{1}{200}+48\right):10=5\)
\(\Rightarrow3^x+\dfrac{9601}{200}=5\cdot10\)
\(\Rightarrow3^x+\dfrac{9601}{200}=50\)
\(\Rightarrow3^x=50-\dfrac{9601}{200}\)
\(\Rightarrow3^x=\dfrac{399}{200}\)
Xem lại đề
\(10-\left\{\left[\left(x:3+17\right):10+3.2^4\right]:10\right\}=5\)
\(\Leftrightarrow10-\left\{\left[\left(x:3+17\right):10+3.16\right]:10\right\}=5\)
\(\Leftrightarrow10-\left\{\left[\left(x:3+17\right):10+78\right]:10\right\}=5\)
\(\Leftrightarrow\left[\left(x:3+17\right):10+78\right]:10=5\)
\(\Leftrightarrow\left[\left(x:3+17\right):10+78\right]=50\)|
\(\Leftrightarrow\left(x:3+17\right):10=-28\)
\(\Leftrightarrow x:3+17=-280\)
\(\Leftrightarrow x:3=-297\)
\(\Leftrightarrow x=-99\)
Vậy \(x=-99\) thì \(10-\left\{\left[\left(x:3+17\right):10+3.2^4\right]:10\right\}=5\)
\(10-\left\{\left[\left(x:3+17\right):10+3.2^4\right]:10\right\}=5\)
\(\Leftrightarrow\left[\left(x:3+17\right):10+3.2^4\right]:10=5\)
\(\Leftrightarrow\left(x:3+17\right):10+3.16=50\)
\(\Leftrightarrow\left(x:3+17\right):10+48=50\)
\(\Leftrightarrow\left(x:3+17\right):10=2\)
\(\Leftrightarrow x:3+17=20\Leftrightarrow x:3=3\)
\(\Leftrightarrow x=9\)
mk làm gọn bn làm chi tiết hơn nha
c) 10 . {[(x : 3 + 17) : 10 + 3 . 2^2] : 10} = 5
[(x : 3 + 17) : 10 + 3 . 4] : 10 = 5 : 10
[(x : 3 + 17) : 10 + 12] : 10 = 1/2
(x : 3 + 17) : 10 + 12 = 1/2 . 10
(x : 3 + 17) : 10 + 12 = 5
(x : 3 + 17) : 10 = 5 - 12
(x : 3 + 17) : 10 = -7
=> x : 3 + 17 = -7 . 10
x : 3 + 17 = -70
x : 3 = -70 - 17
x : 3 = -87
x = -87 . 3
x = -261
a ) \(\left(4x+5\right):3-121:1=4\)
\(\Leftrightarrow\left(4x+5\right):3-11=4\)
\(\Leftrightarrow\left(4x+5\right):3=15\)
\(\Leftrightarrow\left(4x+5\right)=45\)
\(\Leftrightarrow4x=40\)
\(\Leftrightarrow x=10\)
Tiếp tịch như z là đc
\(\Leftrightarrow\left\{\left[\left(x:3+17\right):10+48\right]:10\right\}=5\)
=>(x:3+17):10+48=50
=>(x:3+17):10=2
=>x:3+17=20
=>x:3=3
hay x=9