Question

[Tsubasa Sakura]

Tính

\(A=10.\left(\frac{1}{1.2}+\frac{5}{2.3}+...+\frac{89}{9.10}\right)\)

Giải cả bài nha

Answer 1

[Dũng Nguyễn Đình]

Ta có :\(A=10\left(\frac{1}{1.2}+\frac{5}{2.3}+...+\frac{89}{9.10}\right)\)

\(\Rightarrow10\left(\frac{1}{2}+\frac{5}{6}+...+\frac{89}{90}\right)\)

\(\Rightarrow10\left[\left(1-\frac{1}{2}\right)+\left(1-\frac{1}{6}\right)+...+\left(1-\frac{1}{90}\right)\right]\)

\(\Rightarrow10\left[9-\left(\frac{1}{2}+\frac{1}{6}+...+\frac{1}{90}\right)\right]\)

\(\Rightarrow10\left[9-\left(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{9.10}\right)\right]\)

\(\Rightarrow10\left[9-\left(1-\frac{1}{10}\right)\right]\)

\(\Rightarrow\)\(10\left[9-\frac{9}{10}\right]\)

\(\Rightarrow10.\frac{81}{10}\)

\(\Rightarrow A=81\)

Làm rờ đó sai thì thôi nha.