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27 tháng 7 2021

1, \(12x^2+7x-12=12x^2+16x-9x-12=\left(3x+4\right)\left(4x-3\right)\)

2, \(2m^2+10m+8=2m^2+2m+8m+8=\left(2m+8\right)\left(m+1\right)\)

NV
27 tháng 7 2021

\(12x^2+7x-12=12x^2-9x+16x-12\)

\(=3x\left(4x-3\right)+4\left(4x-3\right)=\left(3x+4\right)\left(4x-3\right)\)

\(2m^2+10m+8=2m^2+2m+8m+8\)

\(=2m\left(m+1\right)+8\left(m+1\right)=2\left(m+4\right)\left(m+1\right)\)

23 tháng 8 2023

1)

\(y^2-4y+4-x^2\\ =\left(y-2\right)^2-x^2\\ =\left(y-2-x\right)\left(y-2+x\right)\)

2)

\(8x^3-12x^2+6x-2\\ =2\left(4x^3-6x^2+3x-1\right)\\ =2\left(4x^3-4x^2-2x^2+2x+x-1\right)\\ =2\left(4x^2\left(x-1\right)-2x\left(x-1\right)+\left(x-1\right)\right)\\ =2\left(x-1\right)\left(4x^2-2x+1\right)\)

23 tháng 8 2023

1) \(y^2-4y+4-x^2\)

\(=\left(y^2-4y+4\right)-x^2\)

\(=\left(y-2\right)^2-x^2\)

\(=\left(y-2-x\right)\left(y-2+x\right)\)

2) \(8x^3-12x^2+6x-1\)

\(=\left(2x\right)^3-3\cdot\left(2x\right)^2\cdot1+3\cdot2x\cdot1^2-1^3\)

\(=\left(2x-1\right)^3\)

\(=\left(2x-1\right)\left(2x-1\right)\left(2x-1\right)\)

21 tháng 8 2021

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1: \(x^2-3x+2=\left(x-1\right)\left(x-2\right)\)

2: \(x^2-x-6=\left(x-3\right)\left(x+2\right)\)

3: \(x^2+7x+12=\left(x+3\right)\left(x+4\right)\)

21 tháng 8 2021

1) \(x^2-3x+2=\left(x^2-x\right)-\left(2x-2\right)=x\left(x-1\right)-2\left(x-1\right)=\left(x-1\right)\left(x-2\right)\)

2) \(x^2-x-6=\left(x^2-3x\right)+\left(2x-6\right)=x\left(x-3\right)+2\left(x-2\right)=\left(x-2\right)\left(x-3\right)\)

3) \(x^2+7x+12=\left(x^2+3x\right)+\left(4x+12\right)=x\left(x+3\right)+4\left(x+3\right)=\left(x+3\right)\left(x+4\right)\)

1: \(x^2-3x+2=\left(x-1\right)\left(x-2\right)\)

2: \(x^2-x-6=\left(x-3\right)\left(x+2\right)\)

3: \(x^2+7x+12=\left(x+3\right)\left(x+4\right)\)

Ta có: \(1+6x-6x^2-x^3\)

\(=-x^3-6x^2+6x+1\)

\(=\left(-x^3+1\right)-6x\left(x-1\right)\)

\(=-\left(x-1\right)\left(x^2+x+1\right)-6x\cdot\left(x-1\right)\)

\(=\left(x-1\right)\left(-x^2-x-1-6x\right)\)

\(=-\left(x-1\right)\left(x^2+7x+1\right)\)

17 tháng 8 2021

\(1+6x-6x^2-x^3\)

= (1-x^3)+(6x-6x^2)

=(1-x)(1+x+x^2)+6x(1-x)

=(1-x)( 1+ x+ x^2 + 6x)

=(1-x)(1+x^2 +7x)

Đây bạn ơi!

31 tháng 7 2023

\(\dfrac{1}{2}x^3+4\)

\(=\dfrac{1}{2}\left(x^3+8\right)\)

\(=\dfrac{1}{2}\left(x^3+2^3\right)\)

\(=\dfrac{1}{2}\left(x+2\right)\left(x^2-2\cdot x+2^2\right)\)

\(=\dfrac{1}{2}\left(x+2\right)\left(x^2-2x+4\right)\)

=1/2(x^3+8)

=1/2(x+2)(x^2-2x+4)

1: =(a+b)^3+c^3-3ab(a+b)-3acb

=(a+b+c)[(a+b)^2-c(a+b)+c^2]-3ab(a+b+c)

=(a+b+c)(a^2+2ab+b^2-ac-bc+c^2-3ab)

=(a+b+c)(a^2+b^2+c^2-ab-bc-ac)

 

2: \(=\left(1-2x\right)\left(1+2x\right)\)

 

13: =x(a^3-1)-b(a-1)

=x(a-1)(a^2+a+1)-b(a-1)

=(a-1)(a^2x+a*x+x-b)

12: =(x-y)(x+y)-(x-y)

=(x-y)(x+y-1)

10: =3(x^2-4y^2)

=3(x-2y)*(x+2y)

7: =x^2-x-5x+5=(x-1)(x-5)

8: =x^2+3x+4x+12=(x+3)(x+4)

9: =2x^2-6x-x+3=(x-3)(2x-1)