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Bài 1 :
a = 1 ; b = 3
hoặc a = 2 ; b = 8
Bài 2:
a = 0 ; b = 5
hoặc a = 5 ; b = 0
Bài 3 :
a = 1 ; b = 0
#ht
\(\overline{a01b}-1⋮30\Rightarrow\overline{a01b}-1\) đồng thời chia hết cho 3 và cho 10
\(\overline{a01b}-1=\overline{a010}+b-1⋮10\Rightarrow b-1⋮10\Rightarrow b=1\)
\(\Rightarrow\overline{a01b}-1=\overline{a010}⋮3\Rightarrow a+1⋮3\) theo đề bài \(\overline{a01b}\) nhỏ nhất nên a nhỏ nhất => a=2
Số cần tìm là 2011
a: =2/5+3/5=1
b: =1/3+2/3=1
c: =7/8+5/8=12/8=3/2
d: =2/7+3/7=5/7
\(a,\dfrac{2}{5}+\dfrac{3}{5}=\dfrac{5}{5}=1\\ b,\dfrac{1}{3}+\dfrac{2}{3}=\dfrac{3}{3}=1\\ c,\dfrac{7}{8}+\dfrac{5}{8}=\dfrac{12}{8}=\dfrac{3}{2}\\ d,\dfrac{1}{7}+\dfrac{3}{7}=\dfrac{4}{7}\)
12/23 x 9/28 + 11/12 x 9/28
= ( 12/23 + 11/23 ) x 9/28
= 1 x 9/28 = 9/28
3 + 1/9 + 3/9 + 2 + 5/9 + 3 + 2
= ( 3 + 2 + 3 + 2 ) + ( 1/9 + 3/9 + 5/9 )
= 10 + 1
= 11
Câu 1:\(\frac{12}{23}\times\frac{9}{28}+\frac{11}{23}\times\frac{9}{28}\)
\(=\frac{9}{28}\times\left(\frac{12}{23}+\frac{11}{23}\right)\)
\(=\frac{9}{28}\times\frac{23}{23}\)
\(=\frac{9}{28}\times1\)
\(=\frac{9}{28}\)
Câu 2:
\(3+\frac{1}{9}+\frac{3}{9}+2+\frac{5}{9}+3+2\)
\(=\left(3+2+2+3\right)+\left(\frac{1}{9}+\frac{3}{9}+\frac{5}{9}\right)\)
\(=10+\frac{9}{9}\)
\(=10+1\)
\(=11\)
\(\frac{12}{23}x\frac{9}{28}+\frac{11}{23}x\frac{9}{28}=\)\(\left(\frac{12}{23}+\frac{11}{23}\right)x\frac{9}{28}\)\(=\) \(1x\frac{9}{28}=\frac{9}{28}\)
\(3+\frac{1}{9}+\frac{3}{9}+2+\frac{5}{9}+3+2\)\(=\) \(\left(\frac{1}{9}+\frac{3}{9}+\frac{5}{9}\right)+\left(3+2+3+2\right)\)\(=\) \(1+3+2+3+2=\)\(11\)
( \(\dfrac{2}{15}\) - \(\dfrac{1}{20}\) + \(\dfrac{3}{15}\) - \(\dfrac{9}{28}\) + \(\dfrac{2}{3}\)) : \(\dfrac{3}{4}\)
= { (\(\dfrac{2}{15}\) + \(\dfrac{3}{15}\)) + \(\dfrac{2}{3}\) - (\(\dfrac{1}{20}\) + \(\dfrac{9}{28}\))} : \(\dfrac{3}{4}\)
= { \(\dfrac{1}{3}\) + \(\dfrac{2}{3}\) - \(\dfrac{13}{35}\)) : \(\dfrac{3}{4}\)
= ( 1 - \(\dfrac{13}{35}\)): \(\dfrac{3}{4}\)
= \(\dfrac{22}{35}\) : \(\dfrac{3}{4}\)
= \(\dfrac{88}{105}\)
a: =(21/11+12/11)-(9/19+3/19+6/19)=3-18/19=39/19
b: =(2/3+4/3)+(3/4+7/4)+(4/5+16/5)
=2+4+10/4
=6+5/2
=17/2
a) \(\dfrac{4}{7}+\dfrac{2}{8}=\dfrac{32}{56}+\dfrac{14}{56}=\dfrac{46}{56}=\dfrac{23}{28}\)
b) \(\dfrac{8}{6}-\dfrac{8}{24}=\dfrac{32}{24}-\dfrac{8}{24}=\dfrac{24}{24}=1\)
c) \(\dfrac{9}{28}\times\dfrac{14}{9}=\dfrac{126}{252}=\dfrac{1}{2}\)
d) \(\dfrac{7}{6}\div\dfrac{2}{3}=\dfrac{7}{6}\times\dfrac{3}{2}=\dfrac{21}{12}\)
1. \(\dfrac{4}{7}+\dfrac{2}{8}=\dfrac{32}{56}+\dfrac{14}{56}=\dfrac{32+14}{56}=\dfrac{46}{56}=\dfrac{23}{28}\)
2. \(\dfrac{8}{6}-\dfrac{8}{24}=\dfrac{32}{24}-\dfrac{8}{24}=\dfrac{32-8}{24}=\dfrac{24}{24}=1\)
3. \(\dfrac{9}{28}\text{×}\dfrac{14}{9}=\dfrac{9\text{×}14}{28\text{×}9}=\dfrac{126}{252}=\dfrac{7}{14}\)
4. \(\dfrac{7}{6}:\dfrac{2}{3}=\dfrac{7}{6}\text{×}\dfrac{3}{2}=\dfrac{7\text{×}3}{6\text{×}2}=\dfrac{21}{12}=\dfrac{7}{4}\)
các bạn chỉ cho mình cách nhân với 11 nhé