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`(8x-16)(x-5)=0`
`=>8x-16=0` hoặc `x-5=0`
`=>8x=16` hoặc `x=5`
`=>x=16:8` hoặc `x=5`
`=>x=2` hoặc `x=5`
Vậy `x in{2;5}`
TH1: 8x-16=0 8x =0+16 8x =16 x =16:8 x =2 | TH2: x-5=0 x=0+5 x=5 |
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(8x-6\right)\left(x-5\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}8x-16=0\\x-5=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=5\end{matrix}\right.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
(8x-16)(x-5)=0
=>8x-16=0 hoặc x-5=0
=>x=2 hoặc x=5.
Chúc bạn học tốt nhé
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(8x-16\right)\left(x-5\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}8x-16=0\\x-5=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}8x=16\\x=5\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=2\\x=5\end{matrix}\right.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\Rightarrow\left[{}\begin{matrix}8x-16=0\\x-5=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=2\\x=5\end{matrix}\right.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(8x-16\right)\left(x-5\right)=0\\ \Leftrightarrow8\left(x-2\right)\left(x-5\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x-2=0\\x-5=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=5\end{matrix}\right.\)
(8\(x\) - 16).(\(x\) - 5) = 0
\(\left[{}\begin{matrix}8x-16=0\\x-5=0\end{matrix}\right.\)
\(\left[{}\begin{matrix}8x=16\\x-5=0\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=2\\x=5\end{matrix}\right.\)
Vậy \(x\) \(\in\){2; 5}
![](https://rs.olm.vn/images/avt/0.png?1311)
a, \(x\) + 99: 3 = 55
\(x\) + 33 = 55
\(x\) = 55 - 33
\(x\) = 22
b, (\(x\) - 25):15 = 20
\(x\) - 25 = 20 x 15
\(x\) - 25 = 300
\(x\) = 300 + 25
\(x\) = 325
c, (3\(x\) - 15).7 = 42
3\(x\) - 15 = 42:7
3\(x\) - 15 = 6
3\(x\) = 6 + 15
3\(x\) = 21
\(x\) = 21: 3
\(x\) = 7
![](https://rs.olm.vn/images/avt/0.png?1311)
a). 3. |9 - 2x| - 17 = 16
3. |9 - 2x| = 16 + 17
3. |9 - 2x| = 33
|9 - 2x| = 33 : 3
|9 - 2x| = 11
=> 9 - 2x = 11
2x = 9 - 11
2x = -2
x = - 2 : 2
x = - 1
hay 9 - 2x = - 11
2x = 9 - (- 11)
2x = 9 + 11
2x = 20
x = 20 : 2
x = 10
Vậy x = -1; x = 10
a) 3.| 9 - 2x | -17 = 16
3. | 9 - 2x | = 16 + 17 = 33
| 9 - 2x | = 33 : 3 = 11
\(\Rightarrow\)9 - 2x = 11 hoặc 9 - 2x = -11
2x = 9 - 11 2x = 9 - ( - 11 )
2x = -2 2x = 20
x = -2 : 2 x = 20 : 2
x = -1 x = 10
8x -16(x-5)=0
8x-16x+80=0
8x - 16x=0-80
x.(8-16)=-80
x.(-8)=-80
x=-80:(-8)
x=10
Vậy x=10
8x - 16x + 80 = 0
-8x = -80
x = 10