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10 tháng 3 2023

= 52/3

 

10 tháng 3 2023

( y - \(\dfrac{2}{3}\)) : \(\dfrac{4}{5}\) = \(\dfrac{5}{6}\)

y - \(\dfrac{2}{3}\)           = \(\dfrac{5}{6}\) \(\times\) \(\dfrac{4}{5}\)

y - \(\dfrac{2}{3}\)           = \(\dfrac{2}{3}\)

y                  = \(\dfrac{2}{3}\) + \(\dfrac{2}{3}\)

y                  =   \(\dfrac{4}{3}\) 

17 tháng 9 2023

\(a,y+\dfrac{2}{3}=\dfrac{5}{2}\)

\(y=\dfrac{5}{2}-\dfrac{2}{3}\)

\(y=\dfrac{15}{6}-\dfrac{4}{6}\)

\(y=\dfrac{11}{6}\)

\(b,3\dfrac{4}{5}-y=\dfrac{18}{5}\)

\(y=3\dfrac{4}{5}-\dfrac{18}{5}\)

\(y=\dfrac{19}{5}-\dfrac{18}{5}\)

\(y=\dfrac{1}{5}\)

\(c,y-4\dfrac{5}{6}=2\dfrac{1}{6}+\dfrac{5}{6}\)

\(y-\dfrac{29}{6}=\dfrac{13}{6}+\dfrac{5}{6}\)

\(y-\dfrac{29}{6}=\dfrac{18}{6}\)

\(y=\dfrac{18}{6}+\dfrac{29}{6}\)

\(y=\dfrac{47}{6}\)

27 tháng 3 2018

a, \(\frac{2}{5}\)+ y = 1

                y = 1 - \(\frac{2}{5}\)

                y = \(\frac{3}{5}\)

b, \(\frac{6}{8}\)- y = \(\frac{3}{5}\)

               y = \(\frac{6}{8}\)\(\frac{3}{5}\)

               y = \(\frac{3}{20}\)

c, y : 6 = \(\frac{7}{4}\)

         y = \(\frac{7}{4}\)x 6

         y = \(\frac{21}{2}\)

d, y - \(\frac{1}{3}\)= 5 x \(\frac{2}{3}\)

    y - \(\frac{1}{3}\)\(\frac{10}{3}\)

           y      = \(\frac{10}{3}\)\(\frac{1}{3}\)

           y      = \(\frac{11}{3}\)

27 tháng 3 2018

a,2/5 + y = 1

            y = 1 - 2/5

            y = 3/5

b, 6/8 - y = 3/5

            y = 6/8 - 3/5

            y = 3/10

c, y / 6 = 7/4 

         y = 7/4 * 6

         y = 15/2

d, y - 1/3 = 5 * 2/3

    y - 1/3 = 10/3

            y = 10/3 + 1/3

            y = 11/3

18 tháng 7 2023

Bài 4:

\(\dfrac{3}{4}+y:\dfrac{2}{5}=\dfrac{37}{16}\)

\(\Rightarrow y:\dfrac{2}{5}=\dfrac{37}{16}-\dfrac{3}{4}\)

\(\Rightarrow y:\dfrac{2}{5}=\dfrac{25}{16}\)

\(\Rightarrow y=\dfrac{2}{5}\cdot\dfrac{25}{16}\)

\(\Rightarrow y=\dfrac{5}{8}\)

________________

\(456+y:87=23987\)

\(\Rightarrow y:87=23987-456\)

\(\Rightarrow y:87=23531\)

\(\Rightarrow y=23531\cdot87\)

\(\Rightarrow y=2047197\)

a)\(\dfrac{4}{5}\times\dfrac{5}{8}:\dfrac{4}{5}\)

\(=\left(\dfrac{4}{5}:\dfrac{4}{5}\right)\times\dfrac{5}{8}\)

\(=1\times\dfrac{5}{8}=\dfrac{5}{8}\)

b)\(\dfrac{5}{6}+\left(\dfrac{1}{2}:\dfrac{3}{2}+\dfrac{4}{5}\right)\)

\(=\dfrac{5}{6}+\left(\dfrac{1}{3}+\dfrac{4}{5}\right)\)

\(=\dfrac{5}{6}+\dfrac{17}{15}\)

\(=\dfrac{59}{30}\)

Bài 2:

a) \(\dfrac{3}{4}+y:\dfrac{2}{5}=\dfrac{37}{16}\)

\(y:\dfrac{2}{5}=\dfrac{37}{16}-\dfrac{3}{4}\)

\(y:\dfrac{2}{5}=\dfrac{25}{16}\)

\(y=\dfrac{25}{16}\times\dfrac{2}{5}\)

\(y=\dfrac{5}{8}\)

b)\(456+y:87=23987\)

\(y:87=23987-456\)

\(y:87=23531\)

\(y=23531\times87\)

\(y=2047197\)

22 tháng 7 2023

a) \(\dfrac{1}{2}:y\times\dfrac{3}{5}=\dfrac{4}{3}+\dfrac{3}{4}\)

\(\dfrac{1}{2}:y\times\dfrac{3}{5}=\dfrac{25}{12}\)

\(\dfrac{1}{2}:y=\dfrac{25}{12}:\dfrac{3}{5}\)

\(\dfrac{1}{2}:y=\dfrac{125}{36}\)

\(y=\dfrac{1}{2}:\dfrac{125}{36}\)

\(y=\dfrac{18}{125}\)

b) \(\dfrac{4}{3}-\dfrac{1}{2}\times y=1\)

\(\dfrac{1}{2}\times y=\dfrac{4}{3}-1\)

\(\dfrac{1}{2}\times y=\dfrac{1}{3}\)

\(y=\dfrac{1}{3}:\dfrac{1}{2}\)

\(y=\dfrac{2}{3}\)

c) \(\dfrac{1}{4}+y:\dfrac{1}{3}=\dfrac{5}{6}\)

\(y:\dfrac{1}{3}=\dfrac{5}{6}-\dfrac{1}{4}\)

\(y:\dfrac{1}{3}=\dfrac{7}{12}\)

\(y=\dfrac{7}{12}\cdot\dfrac{1}{3}\)

\(y=\dfrac{7}{36}\)

30 tháng 10 2019

\(y+y.\frac{1}{3}.\frac{9}{2}+y.\frac{7}{2}=25\)

\(y+y.6+y.\frac{7}{2}=25\)

\(y.\left(1+6+\frac{7}{2}\right)=25\)

\(y.\frac{21}{2}=25\)

\(y=25:\frac{21}{2}\)

\(y=25.\frac{2}{21}\)

\(y=\frac{50}{21}\)

30 tháng 10 2019

\(y.5+y.3+y+y=50\)

\(y.\left(5+3+1+1\right)=50\)

\(y.10=50\)

\(y=5\)