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bạn viết sai đề bài nhé
(x+2)/11+(x+2)/12+(x+2)/13=(x+2)/14+(x+2)15
<=> (x+2)/11+(x+2)/12+(x+2)/13 - (x+2)/14 - (x+2)/15 = 0
<=> (x+2)(1/11+1/12+1/13 - 1/14 - 1/15 ) = 0
vì: (1/11+1/12+1/13 - 1/14 - 1/15 ) khác 0 nên x-2 = 0 => x=2
-3/11-(x-2/5)=-14/20
x-2/5=(-3/11)-(-14/20)
x-2/5=47/110
x=47/110+2/5
x=91/110
a: \(\dfrac{x}{0.9}=\dfrac{5}{6}\)
\(\Leftrightarrow x=\dfrac{3}{4}\)
b: \(\dfrac{-6}{x}=\dfrac{9}{-15}\)
\(\Leftrightarrow x=10\)
c: \(\dfrac{\dfrac{14}{15}}{\dfrac{9}{10}}=\dfrac{x}{\dfrac{3}{7}}\)
\(\Leftrightarrow x=\dfrac{3}{7}\cdot\dfrac{14}{15}:\dfrac{9}{10}=\dfrac{2}{5}\cdot\dfrac{10}{9}=\dfrac{20}{45}=\dfrac{4}{9}\)
a,\(\Leftrightarrow\frac{x}{0,2}=\frac{x}{0,8}\Leftrightarrow0,8x=0,2x\Leftrightarrow0,6x=0\Leftrightarrow x=0\)
b,\(\Leftrightarrow\frac{x+11}{14-x}=\frac{2}{3}\)
\(\Leftrightarrow3\left(x+11\right)=2\left(14-x\right)\)
\(\Leftrightarrow3x+33=28-2x\)
\(\Leftrightarrow3x+2x=28-33\)
\(\Leftrightarrow5x=-5\Leftrightarrow x=-1\)
\(\frac{\left(x+11\right)}{\left(14-x\right)}=\frac{2}{3}\)
\(\Leftrightarrow\)\(3.\left(x+11\right)=2.\left(14-x\right)\)
\(\Leftrightarrow\)\(3x+33=28-2x\)
\(\Leftrightarrow\)\(3x+2x=28-33\)
\(\Leftrightarrow\)\(5x=-5\)
\(\Leftrightarrow\)\(x=-1\)
ok thank