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a)(7^x-11)^3=2^5.5^2+200
<=>(7x-11)3=32*25+200
<=>(7x-11)3=1000
<=>(7x-11)3=103
<=>7x-11=10
<=>7x=21
Đề sai à bạn
b)x^10=1^x
<=>x10-1x=0
<=>(x-1)(x+1)(x4-x3+x2-x+1)(x4+x3+x2+x+1)=0
<=>x=1 hoặc -1 (vì lp 6 chưa học nghiệm số phức)
c)x^10=x
<=>x10-x=0
<=>x(x9-1)=0
<=>x=0 hoặc x9-1=0
<=>x=0 hoặc 1
a)(7^x-11)^3=2^5.5^2+200
<=>(7x-11)3=32*25+200
<=>(7x-11)3=1000
<=>(7x-11)3=103
<=>7x-11=10
<=>7x=21
Đề sai à bạn
b)x^10=1^x
<=>x10-1x=0
<=>(x-1)(x+1)(x4-x3+x2-x+1)(x4+x3+x2+x+1)=0
<=>x=1 hoặc -1 (vì lp 6 chưa học nghiệm số phức)
c)x^10=x
<=>x10-x=0
<=>x(x9-1)=0
<=>x=0 hoặc x9-1=0
<=>x=0 hoặc 1
\(6^2-\left(x+3\right)=45\)
\(36-\left(x+3\right)=45\)
\(x+3=35-45\)
\(x+3=-10\)
\(x=-13\)
a: \(=\dfrac{-3}{5}\cdot\dfrac{5}{7}+\dfrac{-3}{5}\cdot\dfrac{3}{7}+\dfrac{-3}{5}\cdot\dfrac{6}{7}\)
\(=\dfrac{-3}{5}\left(\dfrac{5}{7}+\dfrac{3}{7}+\dfrac{6}{7}\right)=\dfrac{-3}{5}\cdot2=-\dfrac{6}{5}\)
b: \(=\dfrac{3}{13}\cdot\dfrac{6}{11}+\dfrac{3}{13}\cdot\dfrac{5}{11}-\dfrac{2}{13}=\dfrac{3}{13}-\dfrac{2}{13}=\dfrac{1}{13}\)
c: =>1/2x+1+3/8=7/16
=>1/2x=-15/16
=>x=-15/8
d: =>5/2x-1/3=1/6*(-9)/2=-9/12=-3/4
=>5/2x=-3/4+1/3=-9/12+4/12=-5/12
=>x=-1/6
a, \(\left(x-1\right)^3=125\)
\(\Rightarrow x-1=5\Rightarrow x=6\)
b, \(\left(2x+1\right)^3=343\)
\(\Rightarrow2x+1=7\Rightarrow x=3\)
c, \(\left(7x-11\right)^3=2^5.5^2+200\)
\(\Rightarrow\left(7x-11\right)^3=32.25+200\)
\(\Rightarrow\left(7x-11\right)^3=1000\)
\(\Rightarrow7x-11=10\Rightarrow x=3\)
Chúc bạn học tốt!!!
a) \(\left(x-1\right)^3=125\Leftrightarrow\left(x-1\right)^3=5^3\Rightarrow x-1=5\)
\(\Leftrightarrow x=6\) vậy \(x=6\)
b) \(\left(2x+1\right)^3=343\Leftrightarrow\left(2x+1\right)^3=7^3\Rightarrow2x+1=7\)
\(\Leftrightarrow2x=6\Leftrightarrow x=\dfrac{6}{2}=3\) vậy \(x=3\)
c) \(\left(7x-11\right)^3=2^5.5^2+200\Leftrightarrow\left(7x-11\right)^3=32.25+200\)
\(\Leftrightarrow\left(7x-11\right)^3=800+200=1000=10^3\Rightarrow7x-11=10\)
\(\Leftrightarrow7x=21\Leftrightarrow x=\dfrac{21}{7}=3\) vậy \(x=3\)
\(\left(x-1\right)\cdot\left(x-1\right)=5\cdot5\)
\(\left(x-1\right)^2=5^2\)
\(\Rightarrow\left\{{}\begin{matrix}x-1=5\\x-1=-5\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x=5+1\\x=-5+1\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}x=6\\x=-4\end{matrix}\right.\)
(x - 1) . (x - 1) = 5,5
\(\left(x-1\right)^2\) = 5,5
x - 1 = \(\sqrt{5.5}\)
x = \(\sqrt{5.5}-1\)