Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a) \(x^2-4x+5+y^2+2y=\left(x^2-4x+4\right)+\left(y^2+2y+1\right)\)
\(=\left(x-2\right)^2+\left(y+1\right)^2\)
b) \(2x^2+y^2-2xy+10x+25=\left(x^2+10x+25\right)+\left(x^2-2xy+y^2\right)\)
\(=\left(x+5\right)^2+\left(x-y\right)^2\)
c) \(2x^2+2y^2=\left(x^2-2xy+y^2\right)+\left(x^2+2xy+y^2\right)=\left(x-y\right)^2+\left(x+y\right)^2\)
......................?
mik ko biết
mong bn thông cảm
nha ................
x2 + 10x + 26 + y2 + 2y
= x2 + 10 + 25 + 1 + y2 + 2y
= (x2 + 10x + 25) + (y2 + 2y + 1)
= (x + 5)2 + (y + 1)2
x2 - 2xy + 2y2 + 2y + 1
= x2 - 2xy + y2 + y2 + 2y + 1
= (x2 - 2xy + y2) + (y2 + 2y + 1)
= (x - y)2 + (y + 1)2
4x2 + 2z2 - 4xz - 2z + 1
= 4x2 + z2 + z2 - 4xz - 2z + 1
= (4x2 - 4xz + z2) + (z2 - 2z + 1)
= (2x + z)2 + (z - 1)2
\(a.x^2-4x+4+y^2+2y+1\)
\(=\left(x-2\right)^2+\left(y+1\right)^2\)
\(b.x^2+10x+25+x^2-2xy+y^2\)
\(=\left(x+5\right)^2+\left(x-y\right)^2\)
a: \(x^2-4x+y^2+2y+5\)
\(=x^2-4x+4+y^2+2y+1\)
\(=\left(x-2\right)^2+\left(y+1\right)^2\)
b: \(2x^2+y^2-2xy+10x+25\)
\(=x^2+y^2-2xy+x^2+10x+25\)
\(=\left(x-y\right)^2+\left(x+5\right)^2\)
c: \(2x^2+2y^2\)
\(=\left(x^2+2xy+y^2\right)+\left(x^2-2xy+y^2\right)\)
\(=\left(x+y\right)^2+\left(x-y\right)^2\)
a) 2x2 + y2 - 2xy + 10x + 25
= (x2 + y2 - 2xy) + (x2 + 10x + 25)
= (x - y)2 + (x + 5)2
các bn xem đúng ko nhé mk làm bừa nên lên olm hỏi lại mọi người giúp giùm câu b) nha!!
5747568568769868986997696976968978907890780
a: Ta có: \(\left(x+3\right)\left(x+4\right)\left(x+5\right)\left(x+6\right)+1\)
\(=\left(x^2+9x+18\right)\left(x^2+9x+20\right)+1\)
\(=\left(x^2+9x\right)^2+38\left(x^2+9x\right)+360+1\)
\(=\left(x^2+9x\right)^2+2\cdot\left(x^2+9x\right)\cdot19+19^2\)
\(=\left(x^2+9x+19\right)^2\)
b. \(x^2+y^2+2x+2y+2\left(x+1\right)\left(y+1\right)+2\)
\(=\left(x^2+2x+1\right)+2\left(x+1\right)\left(y+1\right)+\left(y^2+2y+1\right)\)
\(=\left(x+1\right)^2+2\left(x+1\right)\left(y+1\right)+\left(y+1\right)^2\)
\(=\left(x+1+y+1\right)^2=\left(x+y+2\right)^2\)
c. \(x^2-2x\left(y+2\right)+y^2+4y+4\)
\(=x^2-2x\left(y+2\right)+\left(y+2\right)^2\)
\(=\left(x-y-2\right)^2\)
d. \(x^2+2x\left(y+1\right)+y^2+2y+1\)
\(=x^2+2x\left(y+1\right)+\left(y+1\right)^2\)
\(=\left(x+y+1\right)^2\)
bạn lấy bài này ở đâu vậy