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Trả lời :
Sử dụng tổng xích ma nha ( k biết bấm thì bảo tui )
B = -10
Study well
\(=\left(28^2-27^2\right)+\left(26^2-25^2\right)+....+\left(2^2-1^2\right)\)
\(=\left(28-27\right)\left(28+21\right)+\left(26-25\right)\left(26+25\right)+...+\left(2-1\right)\left(2+1\right)\)
\(=55+51+...+3\)
\(=\frac{\left[\left(55-3\right):4+1\right]\left(55+3\right)}{2}\)
\(=406\)
\(Q=30^2-29^2+28^2-27^2+...+2^2-1^2\)
\(=\left(30-29\right)\left(30+29\right)+\left(28-27\right)\left(28+27\right)+...+\left(2-1\right)\left(2+1\right)\)
\(=30+29+28+27+...+2+1\)
\(=\frac{30\left(30+1\right)}{2}\)
\(=465\)
= (30^2-29^2)+(28^2-27^2)+......+(2^2-1^2)
=(30+29)*(30-29)+(28+27)*(28-27)+.....+(2+1)*(2-1)
=30+29+28+27+....+2+1
=(30+1)*30/2
=465
\(=\left(28^2-27^2\right)+\left(26^2-25^2\right)+...+\left(2^2-1^2\right)\))
\(=\left(28+27\right)\left(28-27\right)+\left(26-25\right)\left(26+25\right)+...+\left(2+1\right)\left(2-1\right)\)
\(=28+27+26+25+...+2+1\)
= 28 x 29 / 2 = 406
\(1,=-\left(y^2+12y+36\right)=-y^2-12y-36\)
\(2,=-\left(16-8y+y^2\right)=-16+8y-y^2\)
\(3,=-\left(\dfrac{4}{9}+\dfrac{4}{3}x+x^2\right)=-\dfrac{4}{9}-\dfrac{4}{3}x-x^2\)
\(4,=-\left(x^2-3x+\dfrac{9}{4}\right)=-x^2+3x-\dfrac{9}{4}\)
\(5,-\left(2+3y\right)^2=-\left(4+12y+9y^2\right)=-4-12y-9y^2\)
.... mấy ý còn lại bn tự lm nhé, tương tự thhooi
1) \(-\left(y+6\right)^2=-y^2-12y-36\)
2) \(-\left(4-y\right)^2=-y^2+8y-16\)
3) \(-\left(x+\dfrac{2}{3}\right)^2=-x^2-\dfrac{4}{3}x-\dfrac{4}{9}\)
4) \(-\left(x-\dfrac{3}{2}\right)^2=-x^2+3x-\dfrac{9}{4}\)
5) \(-\left(3y+2\right)^2=-9y^2-12y-4\)
6) \(-\left(2y-3\right)^2=-4y^2+12y-9\)
7) \(-\left(5x+2y\right)^2=-25x^2-20xy-4y^2\)
8) \(-\left(2x-\dfrac{3}{2}\right)^2=-4x^2+6x-\dfrac{9}{4}\)
21, \(x^3-4x^2+4x=x\left(x^2-4x+4\right)=x\left(x-2\right)^2\)
22, \(15x^2y+20xy^2-25xy=5xy\left(3x+4y-5\right)\)
23, \(4x^2+8xy-3x-6y=4x\left(x+2y\right)-3\left(x+2y\right)=\left(4x-3\right)\left(x+2y\right)\)
24, \(x^3-6x^2+9x=x\left(x^2-6x+9\right)=x\left(x-3\right)^2\)
Tương tự :))
21.\(x^3-4x^2+4x\)
\(=x\left(x^2-4x+4\right)\)
\(=x\left(x-2\right)^2\)
22,\(15x^2y+20xy^2-25xy\)
\(=5xy\left(3x+4y-5\right)\)
23,\(4x^2+8xy-3x-6y\)
\(=4x\left(x+2y\right)-3\left(x+2y\right)\)
\(=\left(4x-3\right)\left(x+2y\right)\)
24\(x^3-6x^2+9x\)
\(=x\left(x^2-6x+9\right)\)
\(=x\left(x-3\right)^2\)
25,\(x^2-xy+x-y\)
\(=x\left(x-y\right)+\left(x-y\right)\)
\(=\left(x+1\right)\left(x-y\right)\)
26.\(xy-2x-y^2+2y\)
\(=x\left(x-2\right)-y\left(y-2\right)\)
\(=\left(x-y\right)\left(x-2\right)\)
27,\(x^2+x-xy-y\)
\(=\left(x^2-xy\right)+\left(x-y\right)\)
\(=x\left(x-y\right)+\left(x-y\right)\)
\(=\left(x+1\right)\left(x-y\right)\)
28,\(x^2+4x-y^2+4\)
\(=\left(x^2+4x+4\right)-y^2\)
\(=\left(x+2\right)^2-y^2\)
\(=\left(x+2-y\right)\left(x+2+y\right)\)
29.\(x^2-2xy+y^2-4\)
\(=\left(x-y\right)^2-2^2\)
\(=\left(x-y-2\right)\left(x-y+2\right)\)
a,\(2axy-4a^2xy^2+6a^3x^2\)
\(=2ax\left(y-2ay^2+3a^2x\right)\)
b,\(5a^2xy-10a^3x-15ay\)
\(=5a\left(axy-2ax-3y\right)\)
Tự lm tiếp, tất cả đều dùng bằng phương phép đặt nhân tử chung nhé
23) \(2axy-4a^2xy^2+6a^3x^2\)
\(=2ax\left(y-2ay^2+3a^2x\right)\)
24) \(5a^2xy-10a^3x-15ay\)
\(=5a\left(axy-2a^2x-3y\right)\)
25) \(mxy-m^2x+my\)
\(=m\left(xy-mx+y\right)\)
26) \(2mx-4m^2xy+6mx\)
\(=2mx\left(1-2my+3\right)\)
\(=4mx\left(2-my\right)\)