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ta có \(3S=1\cdot2\cdot3+2\cdot3\cdot3+.....+99\cdot100\cdot3\)
\(3S=1\cdot2\cdot3+2\cdot3\cdot\left(4-1\right)....+99\cdot100\cdot\left(101-98\right)\)
\(3S=1\cdot2\cdot3-1\cdot2\cdot3+2\cdot3\cdot4-......-98\cdot99\cdot100+99\cdot100\cdot101\)
\(3S=99.100.101\)
\(S=\frac{99\cdot100\cdot101}{3}\)
S=...
3S=1.2.3+2.3.3+3.4.3+4.5.3+...+99.100.3
3S=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+4.5.6-3.4.5+...+99.100.101-98.99.100
3S=99.100.101
S=33.100.101
S=333300
Vậy S=333300
Đặt M = 1 . 2 + 2 . 3 + ... + 99 . 100
3M = 1 . 2 . 3 + 2 . 3 . 4 + 3 . 4 . 3 + ... + 99 . 100 . 3
3M = 1 . 2 . ( 3 - 0 ) + 2 . 3 . ( 4 - 1 ) + 3 . 4 . ( 5 - 2 ) ... . 99 . 100 . ( 101 - 98 )
3M = ( 1 . 2 . 3 + 2 . 3 . 4 + 3 . 4 . 5 +... + 99 . 100 . 101 ) - ( 0 . 1 . 2 + 1 . 2 . 3 + 2 . 3 . 4 +.......+ 98 . 99 . 100 )
3M = 99 . 100 . 101 - 0 . 1 . 2
3M = 999900 - 0 = 999900
M = 999900 : 3
M = 333300
1) (x-3)(x-5) = 0
\(\Rightarrow\orbr{\begin{cases}x-3=0\\x-5=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=3\\x=5\end{cases}}\)
(x+7).35 = 2.35
\(\Rightarrow x+7=2\)
\(\Rightarrow x=2-7=-5\)
Vậy x = -5
2) 1.2 + 2.3 + 3.4 + .... + 99.100
Đặt A = 1.2 + 2.3 + .... + 99.100
3A = 1.2.3 + 2.3.4 + 3.4.3 + .... + 99.100.3
3A = 1.2.(3-0) + 2.3.(4-1) + 3.4.(5-2)+ .... + 99.100.(101-98)
3A = ( 1.2.3 + 2.3.4 + 3.4.5 +.... + 99.100.101 ) - ( 0.1.2 + 1.2.3 + 2.3.4 + ... + 98.99.100 )
3A = 99.100.101 - 0.1.2
3A = 999900 - 0
3A = 999900
A = 999900 : 3
A = 333300
Vậy A = 333300
ĐẶT A LÀM BIỂU THỨC
=>A=1.2+2.3+3.4+.+99.100
=>3A=1.2.3+2.3.3+3.4.3+....+99.100.3
=>3A=1.2.3+2.3(4-1)+3.4(5-2) + .......+ 99.100(101-98)
=>A=1.2.3+2.3.4-1.2.3-3.4.5-2.3.4+.....+98.99.100-99.100.101
=>A3=99.100.101
=>A=99.100.101:3
=>A=333300
3A = 1.2.(3-0) + 2.3.(4-1) + 3.4.(5-2) + ... + 99.100.(101-98)
3A = 1.2.3 - 0.1.2 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + ... + 99.100.101 - 98.99.100
3A = 99.100.101 - 0.1.2
3A = 99.100.101
A = 33.100.101
A = 333300
\(B=1.2+2.3+3.4+4.5+....+99.100\)
\(3B=1.2.3+2.3.\left(4-1\right)+3.4.\left(5-2\right)+...+99.100.\left(101-98\right)\)
\(3B=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+....+99.100.101-98.99.100\)
\(3B=99.100.101\)
\(B=\frac{99.100.101}{3}=\frac{999900}{3}=333300\)
Đặt \(A=1.2+2.3+3.4+...+99.100\)
\(3A=1.2.3+2.3.3+3.4.3+...+99.100.3\)
\(3A=1.2.3+2.3.\left(4-1\right)+3.4.\left(5-2\right)+...+99.100.\left(101-98\right)\)
\(3A=1.2.3+2.3.4-1.2.3+...+99.100.101-98.99.100\)
\(3A=99.100.101\)
\(3A=999900\)
\(A=999900:3\)
\(A=333300\)
3B = 1.2.3 + 2.3.3 + 3.3.4 + .... + 3.99.100
Đặt M = 1.2.3 + 2.3.4 + 3.4.5 + .... + 99.100.101
=> M - 3A = 1.2.3 - 1.2.3 + 2.3.(4-3) + 3.4 ( 5-3) + .... + 99.100 ( 101 -3)
= 1.2.3 + 2.3.4 + .... + 98.99.100
=> M -3D = M - 99.100.101
=> D = 99.100.101/3 = 333300
Bạn nhân cả 2 vế với 3 nhé
3D=1.2.3+2.3.(4-1)+3.4.(5-2)+...+99.100.(101-98)
3D=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...+99.100.101-98.99.100
3D=99.100.101
D=99.100.101:3=333300