Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
3A=1.2.3+2.3.3+3.4.3+...+19.20.3
3A=1.2.3+2.3.(4-1)+3.4.(5-2)+...+19.20.(21-18)
3A=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...+19.20.21-18.19.20
3A=19.20.21
=> \(A=\frac{19.20.21}{3}=2660\)
mk dùng cách của lớp 8 nha bạn ;
ta có công thức xích ma như sau x(x+1)
nhập vào xích ma ta có kết quả 2660
Đặt \(A=1.2+2.3+3.4+...+19.20\)
Ta có: \(A=1.2+2.3+3.4+...+19.20\)
\(3A=1.2.3+2.3.3+3.4.3+...+19.20.3\)
\(3A=1.2.3+2.3.\left(4-1\right)+3.4.\left(5-1\right)+...+19.20.\left(21-1\right)\)
\(3A=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...+19.20.21-18.19.20\)
\(3A=19.20.21\)
\(A=19.20.7\)
\(A=2660\)
\(1\cdot2+2\cdot3+...+19\cdot20=\frac{1\cdot2\cdot\left(3-0\right)+2\cdot3\cdot\left(4-1\right)+...+19\cdot20\cdot\left(21-17\right)}{3}\)
\(=\frac{1\cdot2\cdot3+2\cdot3\cdot4-1\cdot2\cdot3+...+19\cdot20\cdot21-18\cdot19\cdot20}{3}\)\(=\frac{19\cdot20\cdot21}{3}=2660\)
\(A=\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+\dfrac{1}{3\cdot4}+...+\dfrac{1}{19\cdot20}\)
\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{19}-\dfrac{1}{20}\)
\(=1-\dfrac{1}{20}=\dfrac{19}{20}\)
\(A=\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+\dfrac{1}{3\cdot4}+\dfrac{1}{4\cdot5}+....+\dfrac{1}{19\cdot20}\)
\(A=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+....+\dfrac{1}{19}-\dfrac{1}{20}\)
\(A=1-\dfrac{1}{20}\)
\(A=\dfrac{19}{20}\)
a) Ta có :
\(A=1.2+2.3+3.4+.....+19.20\)
\(3A=1.2.\left(3-0\right)+2.3.\left(4-1\right)+3.4.\left(5-2\right)+.............+19.20.\left(21-18\right)\)
\(3A=1.2.3+2.3.4-1.2.3+3.4.5+-2.3.4+................+19.20.21-18.19.20\)\(3A=\left(1.2.3+2.3.4+.............+19.20.21\right)-\left(1.2.3+2.3.4+..........+18.19.20\right)\)\(3A=19.20.21=7980\)
\(\Rightarrow A=2660\)
~ Chúc bn học tốt ~
xy - x + 2y = 3
\(\Rightarrow\) x(y - 1) + 2y = 1 + 2
\(\Rightarrow\) x(y - 1) + 2y - 2 = 1
\(\Rightarrow\) x(y -1) + 2(y - 1) =1
\(\Rightarrow\) (x + 2) . (y - 1) = 1
Ta có bảng sau:
x + 2 | y - 1 |
1 | 1 |
- 1 | - 1 |
Suy ra
x | y |
-1 | 2 |
-3 | 0 |
Ta có:
S=1.2+2.3+3.4+...+19.20
3S=1.2.3+2.3.(4-1)+...+19.20.(21-18)
3S=1.2.3+2.3.4-2.3.1+...+19.20.21-18.19.20
3S=19.20.21=> S=\(\frac{19.20.21}{3}\)= 2660.
S = 1.2 + 2.3 + ... + 19.20
3S = 1.2.(3 - 0) + 2.3.(4 - 1) +...+ 19.20.(21 - 18)
3S = 1.2.3 - 0.1.2 + 2.3.4 - 1.2.3 +...+ 19.20.21 - 18.19.20
3S = (1.2.3 + 2.3.4 +...+ 19.20.21) - (0.1.2 + 1.2.3 +...+ 18.19.20)
3S = 19.20.21 - 0.1.2
3S = 19.20.21
S = \(\frac{19.20.21}{3}\)
S = 2660
D=1.2+2.3+3.4+..+19.20
=>3D=1.2.3+2.3.3+3.4.3+...+19.20.3
=1.2.3+2.3(4-1)+3.4(5-2)+...+19.20(21-18)
=>1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...+19.20.21-18.19.20
=19.20.21=7980
=>D=2660
vậy D=2660
S = 1.2+2.3 +3.4 +............+19.20
=>3S=1.2.3+2.3.3+3.4.3+.....+19.20.3
=1.2.(3-0)+2.3.(4-1)+3.4.(5-2)+...+19.20.(21-18)
=1.2.3-0.1.2+2.3.4-1.2.3+3.4.5-2.3.4+....+19.20.21-18.19.20
=19.20.21-0.1.2
=19.20.21
=>S=\(\frac{19.20.21}{3}\)
bạn tự bấm máy
Tính tổng : A=1.2+2.3+3.4+..+19.20
3A = 1.2.3 - 1.2.3 + 2.3.4 - 2.3.4 + ..... + 19.20.21
3A = 19.20.21
A = \(\frac{19.20.21}{3}=3990\)
Tính tổng : A=1.2+2.3+3.4+..+19.20
3a=1.2.3-1.2.3.+2.3.4-2.3.4+......+19.20.21
3a=19.20.21
a=19.20.21:3=3990